1019

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 41293 Accepted Submission(s): 15567

Problem Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 … nm where m is the number of integers in the set and n1 … nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

Sample Input

2
3 5 7 15
6 4 10296 936 1287 792 1

Sample Output

105
10296

就是普通的求最小公倍数，按顺序依次求就行了

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

long long gcd(long long a,long long b)
{
    long long temp;
    while(b)
    {
        temp=a;
        a=b;
        b=temp%b;
    }
    return a;
}

int main()
{
    freopen("input.txt","r",stdin);
    freopen("output.txt","w",stdout);
    long long lcm;
    int n,m;
    long long a;
    scanf("%d",&n);
    while(n--)
    {
        scanf("%d%lld",&m,&lcm);
        while(--m)
        {
            scanf("%lld",&a);
            lcm=lcm/gcd(lcm,a)*a;
        }
        printf("%lld\n",lcm);
    }
    return 0;
}