Given a binary tree, return the postorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 \ 2 / 3
return [3,2,1]
.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> res; vector<int> postorderTraversal(TreeNode* root) { if(root == NULL) return res; if (root->left) postorderTraversal(root->left); if (root->right) postorderTraversal(root->right); res.push_back(root->val); return res; } };