#include <stdio.h>
#include <stdlib.h>
// 第一题
// 找出N个数的第k个最大者
// 方法1：排序(冒泡)，降序找出第k个值
// 方法2：选前k个点进行降序排序，后面的数进行比较，
// 如果数比第k个数小则忽略, 复杂度低于方法1
#define TYPE int
#define TESTBUBLESORT 1
#define TESTBLOCKCOMPARE 1
#define TESTWORDPUZZLE 1
int findk_bublesort(TYPE *pData, int N, int k);
int findk_blockcompare(TYPE *pData, int N, int k); // 缺点修改了原数据
// 第二题
// wordpuzzle猜字谜游戏，在三个方向上找单词
// dirction = 0 水平方向 从左至右
// dirction = 1............右..左
// ...........2............上..下
// ...........3............下..上
// ...........4............正对角线->
// ...........5....................<-
// ...........6............负对角线<-
// ...........7....................->
// pData字谜
// pattern：欲猜的单词
int wordpuzzle(char *pData, char *pattern, int row, int col, int driction);
int my_strlen(char *s); // 获取字符串的长度
void my_strcat(char *s, char *t); // 连接字符串
void my_strcpy(char *s, char *t); // 复制字符串
// Test Model
int main()
{
printf("Hello world!\n");
int N = 10000;
int k = N / 2;
TYPE *pTestData = (TYPE *)malloc(sizeof(TYPE) * N);
int i;
for (i = 0; i < N; ++i)
pTestData[i] = i;
#ifdef TESTBUBLESORT
// printf("the k = %d in N is %d\n", k, findk_bublesort(pTestData, N, k));
#endif
#ifdef TESTBLOCKCOMPARE
printf("the k = %d in N is %d\n", k, findk_blockcompare(pTestData, N, k));
#endif
// for (i = 0; i < N; ++i)
// printf("%d ", pTestData[i]);
// printf("\n");
free(pTestData);
#ifdef TESTWORDPUZZLE
int row = 4;
int col = 4;
char *WorldModle = (char *)malloc(sizeof(char) * row * col);
char *a1 = "this";
char *a2 = "wats";
char *a3 = "oahg";
char *a4 = "fght";
my_strcpy(WorldModle, a1);
my_strcat(WorldModle, a2);
my_strcat(WorldModle, a3);
my_strcat(WorldModle, a4);
char *pattern = "that";
int np = my_strlen(pattern);
if (np > row || np > col)
{
fputs("the pattern size is bigger!", stderr);
return -1;
}
for (i = 0; i < 8; ++i)
{
if (wordpuzzle(WorldModle, pattern, row, col, i))
{
printf("find word:[%s] at dirction [%d] of wordwidget\n", pattern, i);
break;
}
}
#endif
return 0;
}
void my_strcpy(char *s, char *t)
{
while (*s++ = *t++)
;
}
void my_strcat(char *s, char *t)
{
while(*s)
{
++s;
}
my_strcpy(s, t);
}
int findk_bublesort(TYPE *pData, int N, int k)
{
// 对数据进行冒泡排序 降序
int i, j;
for (i = 0; i < N; ++i)
{
for (j = i + 1; j < N; ++j)
{
if (pData[i] < pData[j])
{
TYPE temp;
temp = pData[i];
pData[i] = pData[j];
pData[j] = temp;
}
}
}
return pData[k - 1];
}
int findk_blockcompare(TYPE *pData, int N, int k)
{
// 先读入前k个数进行降序排列，然后与后面的数比较
// 前k个数进行降序排列
int i, j, z;
for (i = 0; i < k; ++i)
{
for (j = i + 1; j < k; ++j)
{
if (pData[i] < pData[j])
{
TYPE temp;
temp = pData[i];
pData[i] = pData[j];
pData[j] = temp;
}
}
}
// 与后面的数与前k个数进行比较
for (i = k; i < N; ++i)
{
for (j = 0; j < k; ++j)
{
if (pData[j] <= pData[i])
{
// 大于k个数中的一个 插入新元素
for (z = k - 2; z >= j; --z)
pData[z + 1] = pData[z]; // 右移元素
pData[j] = pData[i]; // 插入新元素
break;
}
}
}
return pData[k - 1];
}
int wordpuzzle(char *pData, char *pattern, int row, int col, int driction)
{
int result = 0;
int i, j;
int np;
int k = 0;
switch (driction)
{
case 0: // 从水平方向从左至右找
for (i = 0; i < row; ++i)
{
for (j = 0; j < col; ++j)
{
if (pData[i * col + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
k = 0;
}
break;
case 1: // 从水平方向上从右至左找
for (i = 0; i < row; ++i)
{
for (j = col - 1; j >= 0; --j, --np)
{
if (pData[i * col + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
k = 0;
}
break;
case 2: // 按列从上往下找
for (i = 0; i < col; ++i)
{
for (j = 0; j < row; ++j)
{
if (pData[j * row + i] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
k = 0;
}
break;
case 3: // 按列从下往上找
for (i = 0; i < col; ++i)
{
for (j = row - 1; j >= 0; --j)
{
if (pData[i * row + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
k = 0;
}
break;
case 4: // 按正对角线从左到右
for (i = 0; i < row; ++i)
{
for (j = 0; j < col; ++j)
{
if (i == j)
{
if (pData[i * row + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
}
}
k = 0;
break;
case 5: // 按正对角线从右到左
for (i = row - 1; i >= 0; --i)
{
for (j = col - 1; j >= 0; --j)
{
if (i == j)
{
if (pData[i * row + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
}
}
k = 0;
break;
case 6: // 按负对角线从右到左
for (i = col - 1; i >= 0; --i)
{
for (j = 0; j < row ; --j)
{
if (i + j == col - 1)
{
if (pData[i * row + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
}
}
k = 0;
break;
case 7: // 从负对角线从左到右
for (i = row - 1; i >= 0; --i)
{
for (j = 0; j < col; ++j)
{
if (i + j == row - 1)
{
if (pData[i * row + j] == pattern[k])
{
k++;
}
if (pattern[k] == '\0')
result = 1;
}
}
}
k = 0;
break;
default:
break;
}
return result;
}
int my_strlen(char *s)
{
int n = 0;
while (*s++)
++n;
return n;
}
