A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string s consisting of lowercase English letters. Since Kerem likes it when things are different, he wants allsubstrings of his string s to be distinct. Substring is a string formed by some number of consecutive characters of the string. For example, string "aba" has substrings "" (empty substring), "a", "b", "a", "ab", "ba", "aba".
If string s has at least two equal substrings then Kerem will change characters at some positions to some other lowercase English letters. Changing characters is a very tiring job, so Kerem want to perform as few changes as possible.
Your task is to find the minimum number of changes needed to make all the substrings of the given string distinct, or determine that it is impossible.
The first line of the input contains an integer n (1 ≤ n ≤ 100 000) — the length of the string s.
The second line contains the string s of length n consisting of only lowercase English letters.
If it's impossible to change the string s such that all its substring are distinct print -1. Otherwise print the minimum required number of changes.
2 aa
1
4 koko
2
5 murat
0
In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko".
Codeforces Round #352 (Div. 2) B. Different is Good
the smallest Substring of the given string can be lowercase English letters, so if it is possible to make the goal string the size of the given string
can't be bigger than 26, so is size > 26 print -1;
the use set too find the number of the different letters from the string, then print n - set.size()
#include <iostream> #include <cstdio> #include <string> #include <set> using namespace std; set<char> dif; int main() { int n; string str; scanf("%d", &n); cin>>str; int sz = str.size(); if(sz > 26) printf("-1"); else{ for(int i = 0; i < sz; i++) dif.insert(str[i]); printf("%d", sz - dif.size()); } return 0; }
Thank you!
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