杭电1012


u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18822    Accepted Submission(s): 8211


Problem Description
A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

Sample Output
   
   
   
   
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333






//杭电1012
#include <stdio.h>
int main (int argc, char **argv)
{

    printf("n e\n");
    printf("- -----------\n");
    printf("0 1\n");
    printf("1 2\n");
    printf("2 2.5\n");
    double result = 2.5 ;
    double p = 0.5;
    for (int i = 3; i <= 9; ++ i )
    {
        p /= i;
        result += p;
        printf("%d %.9f\n", i , result);
    }
    return  0;
}


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