poj 2608 soundx

//注意重复的或者其soundx值相等的字符应该先去掉！ 
#include <iostream>
#include <string>
#include <map>
using namespace std;

map<char, int> m;

int main()
{
    m['B'] = 1, m['F'] = 1, m['P'] = 1, m['V'] = 1;
    m['C'] = 2, m['G'] = 2, m['J'] = 2, m['K'] = 2, m['Q'] = 2, m['S'] = 2, m['X'] = 2, m['Z'] = 2;
    m['D'] = 3, m['T'] = 3;
    m['L'] = 4;
    m['M'] = 5, m['N'] = 5;
    m['R'] = 6;
    string str1, str2, ans;
    int len, i;
    while (cin >> str1){
          len = str1.length();
          str2.clear();
          ans.clear();
          //将重复的字符进行删除 
          for (i = 0; i < len; i++){
              str2.push_back(str1[i]);
              while ((str1[i] == str1[i+1]) || (m[str1[i]] == m[str1[i+1]])) i++;
          }
          len = str2.length();
          for (i = 0; i < len; i++){
              if (str2[i] == 'A' || str2[i] == 'E' || str2[i] == 'I' || str2[i] == 'O' || str2[i] == 'U' || str2[i] == 'H' || str2[i] == 'W' || str2[i] == 'Y')
                  continue;
              else
                  ans.push_back(m[str2[i]]+48); 
          }
          cout << ans << endl;
    }
    
    system("pause");
}