[C语言][LeetCode][24]Swap Nodes in Pairs

题目

Swap Nodes in Pairs
Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

标签

Linked List

难度

简单

分析

题目意思是给定一个单链表,交换两个相邻的节点。我的做法是先找到新链表的头结点,然后像交换两个变量的值的方式,来交换两个相邻的节点,这里需要注意的是,交换的时候,需要保存交换节点的前后节点,这里我用left、right去保存,为了交换之后,前后节点不丢失。

C代码实现

struct ListNode* swapPairs(struct ListNode* head) 
{
    struct ListNode *p, *q, *right, *left;
    struct ListNode * ret;

    if(!head || !head->next)
        return head;

    p = head;
    q = p->next;

    if(p && q)
        ret = q;

    while(p && q)
    {
        right = q->next;
        q->next = p;
        left = p;
        p->next = right;
        p = right;

        if(!right || !right->next)
            break;

        if(right->next)
        {
            q = p->next;
            left->next = q;
        }
    }

    return ret;
}

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