Hangman Judge

UVa489

这道题只要注意标记,统计一下个数就行了。

#include <stdio.h>
#include <string.h>
const int maxn = 105, N = 26;
char str[maxn], ch[maxn];
int vis[N];
int main ( )
{
    int cas, len1, len2, err, cnt, rig;
    while ( ~ scanf ( "%d", &cas ) && ~ cas )
    {
        cnt = rig = err = 0;
        memset ( vis, 0, sizeof ( vis ) );
        scanf ( "%s%s", str, ch );
        len1 = strlen ( str );
        len2 = strlen ( ch );
        for ( int i = 0; i < len1; i ++ )
        {
            if ( vis[ str[i]-'a'] == 0 )
            {
                vis[ str[i]-'a' ] = 1;
                cnt ++; //统计字母个数
            }
        }
        for ( int j = 0; j < len2; j ++ )
        {
            if ( rig >= cnt || err >= 7 )
                break ; //如果对的个数达到或错误次数达到
            if ( vis[ ch[j]-'a' ] )
            {
                vis[ ch[j]-'a' ] = 0;
                rig ++;
            }
            else
                err ++;
        }
        printf ( "Round %d\n", cas );
        if ( err >= 7 )
            printf ( "You lose.\n" );
        else if ( rig >= cnt )
            printf ( "You win.\n" );
        else
            printf ( "You chickened out.\n" );
    }
    return 0;
}


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