【BZOJ1083】[SCOI2005]繁忙的都市【最小瓶颈生成树】

【题目链接】

最小瓶颈生成树 = 最小生成树

水过。

/* Footprints In The Blood Soaked Snow */
#include <cstdio>
#include <algorithm>

using namespace std;

const int maxn = 305, maxm = 50005;

int n, m, fa[maxn];

struct _edge {
	int u, v, w;

	bool operator < (const _edge &x) const {
		return w < x.w;
	}
} g[maxm];

inline int iread() {
	int f = 1, x = 0; char ch = getchar();
	for(; ch < '0' || ch > '9'; ch = getchar()) f = ch == '-' ? -1 : 1;
	for(; ch >= '0' && ch <= '9'; ch = getchar()) x = x * 10 + ch - '0';
	return f * x;
}

inline int find(int x) {
	return fa[x] == x ? x : fa[x] = find(fa[x]);
}

int main() {
	n = iread(); m = iread();
	for(int i = 1; i <= n; i++) fa[i] = i;
	for(int i = 1; i <= m; i++) {
		int u = iread(), v = iread(), w = iread();
		g[i] = (_edge){u, v, w};
	}

	sort(g + 1, g + 1 + m);
	int cnt = 0, now = 1;
	for(; cnt != n - 1; now++) {
		int u = find(g[now].u), v = find(g[now].v);
		if(u != v) fa[u] = v, cnt++;
	}
	
	printf("%d %d\n", n - 1, g[now - 1].w);
	return 0;
}


你可能感兴趣的:(【BZOJ1083】[SCOI2005]繁忙的都市【最小瓶颈生成树】)