Total Accepted: 1167 Total Submissions: 3961
Given a string, find the length of the longest substring T that contains at most 2 distinct characters.
For example,Given s = “eceba”
,
[分析]
用HASHTABLE 记录 当前两个字符的数目, 如果遇到新字符, 移动start指针的位置, 直到新的start位置, 只包含两个字符. 这题思路很简单, 不知为何标为HARD. 也许有更优解, 不需要用extra space.
[code]
public class Solution { public int lengthOfLongestSubstringTwoDistinct(String s) { //input check if(s== null || s.length()==0) return 0; Map<Character, Integer> map = new HashMap<Character, Integer>(); int start = 0; int max = 0; for(int i=0; i<s.length(); i++) { char c = s.charAt(i); if(map.containsKey(c)) { map.put( c, map.get(c) + 1 ); } else if(map.size() < 2) { map.put(c, 1); } else { while( (map.size()==2) && start<i) { char temp = s.charAt(start); int x = map.get(temp); --x; if(x==0) map.remove(s.charAt(start)); else map.put(s.charAt(start), x); ++start; } map.put(c,1); } max = Math.max(max, i-start+1); } return max; } }