就是用DFS找个数
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
const int maxm=55;
char map[maxm][maxm];
int DIR[22][2] = {{0,1},{1,0},{0,-1},{-1,0}};
int dir[22][4] = {{0,0,1,1}, {1,0,0,1}, {0,1,1,0}, {1,1,0,0}, {0,1,0,1}, {1,0,1,0}, {1,0,1,1}, {0,1,1,1}, {1,1,1,0},{1,1,0,1}, {1,1,1,1}};
int vis[maxm][maxm];
int m,n;
void dfs(int x,int y,int t)
{
vis[x][y]=1;
for(int i=0; i<4; i++)
{
if(dir[t][i])
{
int xx=x+DIR[i][0];
int yy=y+DIR[i][1];
int k=map[xx][yy]-'A';
if(xx>=0&&xx<m&&yy>=0&&yy<n&&!vis[xx][yy]&&dir[k][(i+2)%4])
{
dfs(xx,yy,k);
}
}
}
}
int main()
{
while(scanf("%d%d",&m,&n)!=EOF&&(m+n)!=-2)
{
memset(vis,0,sizeof(vis));
for(int i=0; i<m; i++)
{
scanf("%s",map[i]);
}
int cnt=0;
for(int i=0; i<m; i++)
{
for(int j=0; j<n; j++)
{
if(!vis[i][j])
{
dfs(i,j,map[i][j]-'A');
cnt++;
}
}
}
printf("%d\n",cnt);
}
return 0;
}