最大权闭合图。。。简单题
#include <bits/stdc++.h> using namespace std; typedef long long LL; const int maxn = 60005; const int maxm = 400005; const int INF = 0x3f3f3f3f; struct Edge { int v, c, next; Edge() {} Edge(int v, int c, int next) : v(v), c(c), next(next) {} }E[maxm]; queue<int> q; int H[maxn], cntE; int dis[maxn]; int cur[maxn]; int cnt[maxn]; int pre[maxn]; int n, m, s, t, flow, nv; void addedges(int u, int v, int c) { E[cntE] = Edge(v, c, H[u]); H[u] = cntE++; E[cntE] = Edge(u, 0, H[v]); H[v] = cntE++; } void bfs() { memset(cnt, 0, sizeof cnt); memset(dis, -1, sizeof dis); cnt[0]++, dis[t] = 0; q.push(t); while(!q.empty()) { int u = q.front(); q.pop(); for(int e = H[u]; ~e; e = E[e].next) { int v = E[e].v; if(dis[v] == -1) { dis[v] = dis[u] + 1; cnt[dis[v]]++; q.push(v); } } } } int isap() { memcpy(cur, H, sizeof cur); bfs(); flow = 0; int u = pre[s] = s, f, minv, e, pos; while(dis[s] < nv) { if(u == t) { f = INF; for(int i = s; i != t; i = E[cur[i]].v) if(f > E[cur[i]].c) { f = E[cur[i]].c; pos = i; } for(int i = s; i != t; i = E[cur[i]].v) { E[cur[i]].c -= f; E[cur[i] ^ 1].c += f; } flow += f; u = pos; } for(e = cur[u]; ~e; e = E[e].next) if(E[e].c && dis[E[e].v] + 1 == dis[u]) break; if(~e) { cur[u] = e; pre[E[e].v] = u; u = E[e].v; } else { if(--cnt[dis[u]] == 0) break; for(minv = nv, e = H[u]; ~e; e = E[e].next) if(E[e].c && minv > dis[E[e].v]) { minv = dis[E[e].v]; cur[u] = e; } dis[u] = minv + 1; cnt[dis[u]]++; u = pre[u]; } } return flow; } void init() { cntE = 0; memset(H, -1, sizeof H); } void work() { int a, b, c, sum = 0, x; s = 0, t = n + m + 1, nv = t + 1; for(int i = 1; i <= n; i++) { scanf("%d", &x); addedges(i, t, x); } for(int i = 1; i <= m; i++) { scanf("%d%d%d", &a, &b, &c); addedges(s, i + n, c); addedges(i + n, a, INF); addedges(i + n, b, INF); sum += c; } printf("%d\n", sum - isap()); } int main() { while(scanf("%d%d", &n, &m) != EOF) { init(); work(); } return 0; }