UVA - 11488 Hyper Prefix Sets

题意:给定一个字符串集合S,定义P(S)为所有字符串的公共前缀长度与S中字符串个数的乘积,从中选出一个集合S,使得P(S)最大

思路:也是一道Trie树的应用,在每个节点在加上一个当前到此节点的字符串个数就行了

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 10000010;

struct Trie{
    int ch[MAXN][2];
    int val[MAXN];
    int n[MAXN];
    int sz;
    void initTrie(){
        sz = 1,memset(ch[0],0,sizeof(ch[0]));
        memset(val,0,sizeof(val));
        memset(n,0,sizeof(n));
    }
    int idx(char c){
        return c - '0';
    }
    void insert(char *s){
        int u = 0,len = strlen(s);
        for (int i = 0; i < len; i++){
            int c = idx(s[i]);
            if (!ch[u][c]){
                memset(ch[sz],0,sizeof(ch[sz]));
                n[sz] = i+1;
                ch[u][c] = sz++;
            }
            u = ch[u][c];
            val[u]++;
        }
    }
}trie;

int main(){
    int t,m;
    char str[300];
    scanf("%d",&t);
    while (t--){
        scanf("%d",&m);
        trie.initTrie();
        while (m--){
            scanf("%s",str);
            trie.insert(str);
        }
        int ans = -1;
        for (int i = 1; i < trie.sz; i++)
            ans = max(ans,trie.n[i]*trie.val[i]);
        printf("%d\n",ans);
    }
    return 0;
}



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