先对所有点做bfs求出任意两点间最短距离,然后暴力枚举中转点i,j求出答案。。。。
#include <iostream> #include <queue> #include <stack> #include <map> #include <set> #include <bitset> #include <cstdio> #include <algorithm> #include <cstring> #include <climits> #include <cstdlib> #include <cmath> #include <time.h> #define maxn 3005 #define maxm 10005 #define eps 1e-12 #define mod 998244353 #define INF 0x3f3f3f3f #define PI (acos(-1.0)) #define lowbit(x) (x&(-x)) #define mp make_pair #define ls o<<1 #define rs o<<1 | 1 #define lson o<<1, L, mid #define rson o<<1 | 1, mid+1, R #pragma comment(linker, "/STACK:102400000,102400000") #define pii pair<int, int> typedef long long LL; typedef unsigned long long ULL; //typedef int LL; using namespace std; LL qpow(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base;base=base*base;b/=2;}return res;} LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;} // head struct Edge { int v; Edge *next; }*H[maxn], E[maxm], *edges; queue<pii> q; int dis[maxn][maxn]; int n, m, ans; void addedges(int u, int v) { edges->v = v; edges->next = H[u]; H[u] = edges++; } void init() { edges = E; memset(H, 0, sizeof H); memset(dis, INF, sizeof dis); } void bfs(int now) { q.push(mp(now, 0)); while(!q.empty()) { int u = q.front().first, dist = q.front().second; q.pop(); if(dis[now][u] != INF) continue; dis[now][u] = dist; for(Edge *e = H[u]; e; e = e->next) { int v = e->v; if(dist + 1 < dis[now][v]) q.push(mp(v, dist + 1)); } } } void calc(int s0, int t0, int l0, int s1, int t1, int l1) { for(int i = 1; i <= n; i++) for(int j = 1; j <= n; j++) if(dis[s0][i] + dis[i][j] + dis[j][t0] <= l0) if(dis[s1][i] + dis[i][j] + dis[j][t1] <= l1) ans = min(ans, dis[s0][i] + dis[j][t0] + dis[s1][i] + dis[j][t1] + dis[i][j]); } void work() { int u, v, cnt = 0; for(int i = 1; i <= m; i++) { scanf("%d%d", &u, &v); addedges(u, v); addedges(v, u); cnt++; } for(int i = 1; i <= n; i++) bfs(i); int s0, t0, l0, s1, t1, l1; scanf("%d%d%d", &s0, &t0, &l0); scanf("%d%d%d", &s1, &t1, &l1); ans = INF; if(dis[s0][t0] <= l0 && dis[s1][t1] <= l1) ans = dis[s0][t0] + dis[s1][t1]; else { printf("-1\n"); return; } calc(s0, t0, l0, s1, t1, l1); calc(t0, s0, l0, s1, t1, l1); printf("%d\n", cnt - ans); } int main() { while(scanf("%d%d", &n, &m)!=EOF) { init(); work(); } return 0; }