HDU4287- Intelligent IME

题意：输入n,m，n个目标数，m个匹配数，求出每个目标数与匹配数相同的个数，没有的话为0

思路：排序检索题，，可以把字符串转化为整数，然后再检索是否相同

#include<stdio.h>
#include<string.h>

int change[] = {2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 9, 9, 9, 9};
int main() {
	int cas;
	int arr[5005], num[5005], vis[5005];
	char str[10];
	scanf("%d", &cas);
	while (cas--) {
		int n, m;	
		int temp, cnt = 0;
		memset(vis, 0, sizeof(vis));

		scanf("%d%d", &n, &m);	
		for(int i = 0; i < n; i++)	
			scanf("%d", &arr[i]);
		while (m--){
			temp = 0;
			scanf("%s", str);
			for(int i = 0; i < strlen(str); i++){
				temp = temp * 10 + change[str[i] - 'a']; 	
			}
				num[cnt++] = temp;
		}
		for(int i = 0; i < n; i++){
			for(int j = 0; j < cnt; j++)	
				if (arr[i] == num[j])	
					vis[i]++;	
		}
		for(int i = 0; i < n; i++)	
			printf("%d\n", vis[i]);
	}
	return 0;
}