Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN
Sample Output
1 3 0
通过KMP统计匹配次数。
#include<cstdio> #include<cstring> using namespace std; char s[1000005],t[10005]; int next[10005]; void get_next() { int i=0,j=-1; next[0]=-1; for(;t[i];) if(j==-1||t[i]==t[j]) { ++i;++j; next[i]=j; } else j=next[j]; } int kmp() { int i=0,j=0,num=0,len=strlen(t); for(;s[i];) { if(j==-1||s[i]==t[j]) ++i,++j; else j=next[j]; if(j>=len) { num++; j=next[j]; } } return num; } int main() { int cas; scanf("%d",&cas); for(;cas--;) { scanf("%s",t); scanf("%s",s); get_next(); printf("%d\n",kmp()); } return 0; }