信息安全数学基础课程-相关计算题代码

广义欧几里得(列表法):

#include<iostream>
#include<cstdio>
#include<cmath>
#include<map>
#include<cstring>
#include<algorithm>
using namespace std;

int main()
{
    int a,b,c,d,e,f,g;
    while(~scanf("%d%d",&a,&b))
    {
        c=0,d=1;e=1,f=0,g=1;
        printf("   %d %d %d %d\n",a,b,e,f);
        while(b)
        {
            int n=a/b;
            int h=b;
            int i=a%b;
            int j=e-n*c;
            int k=f-n*d;
            g=n,e=c;f=d;c=j,d=k,a=h,b=i;
            printf("%d %d %d %d %d\n",g,a,b,e,f);
        }
    }
    return 0;
}

模重复平方法:

#include<iostream>
#include<cstdio>
#include<cmath>
#include<map>
#include<cstring>
#include<algorithm>
using namespace std;

int main()//2 251 503
{
    int c,k,m,d;
    cout<<"模重复平方法:分别输入底数a,幂k,模m"<<endl;
    while(~scanf("%d%d%d",&c,&k,&m))
    {
        int i=0,a=1,b=c;
        printf("设a=%d b0=%d\n",a,b);
        while(k>=(1<<i))
        {
            if(k&(1<<i))a=a*b%m;
            b=(b*b)%m;
            if(i&&k&(1<<i))printf("(%d)x%d=%d\n\ta%d=a%d*b%d=%d,b%d=sqrt(b%d)=%d\n",i+1,i,k&(1<<i),i,i-1,i,a,i+1,i,b);
            else if(i)printf("(%d)x%d=%d\n\ta%d=a%d=%d,b%d=sqrt(b%d)=%d\n",i+1,i,k&(1<<i)>0,i,i-1,a,i+1,i,b);
            else if(k&(1<<i))printf("(%d)x%d=%d\n\ta%d=a*b%d=%d,b%d=sqrt(b%d)=%d\n",i+1,i,k&(1<<i),i,i,a,i+1,i,b);
            else printf("(%d)x%d=%d\n\ta%d=a=%d,b%d=sqrt(b%d)=%d\n",i+1,i,k&(1<<i)>0,i,a,i+1,i,b);
            i++;
        }
    }
    return 0;
}



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