zoj 2747 Paint the Wall

继续矩形切割。

直接上个程序改了改。这次是问颜色不同的矩形覆盖后剩下多少种颜色的矩形，并且求出来面积。

直接标记下颜色，然后相同颜色的面积加一起即可。

本来应该一次AC的。。。WA了数次。。。输出没看清楚 = = color与colors考虑到了。。。但是is 和are没注意 = =T T 。。。我还以为是精度问题。。全换成int了。。。double也过了。

#include <queue>
#include <stack>
#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <limits.h>
#include <string.h>
#include <string>
#include <algorithm>

using namespace std;

const int MAX = 105*2;
int x[MAX];
int y[MAX];
struct rectangle{ int lx,ly,rx,ry;int col;};
rectangle r[105];
int map[MAX][MAX];
int area[105];
int find(int a[],int m,int x)  
{  
    int beg = 0,end = m-1;  
    while( beg <= end )  
    {  
        int mid = (beg+end) >> 1;  
        if( x == a[mid] )  
            return mid;  
        if( x > a[mid] )  
            beg = mid + 1;  
        else  
            end = mid;  
    }  
}  
void solve(int n,int cnt)
{
	for(int i=0; i<n; i++)
	{
		int x1 = find(x,cnt,r[i].lx);
		int x2 = find(x,cnt,r[i].rx);
		int y1 = find(y,cnt,r[i].ly);
		int y2 = find(y,cnt,r[i].ry);
		for(int k=x1; k<x2; k++)
			for(int j=y1; j<y2; j++)
				map[k][j] = r[i].col;
	}
	for(int i=0; i<cnt-1; i++)
		for(int k=0; k<cnt-1; k++)
			if( map[i][k] )
				area[map[i][k]] += (x[i+1] - x[i])*(y[k+1] - y[k]);
}
int main()
{	
	int n,cnt,ind = 1,h,w;
	bool flag = false;
	while( ~scanf("%d%d",&h,&w) && (h || w) )
	{
		if( flag ) printf("\n");
		flag = true;
		cnt = 0;
		memset(map,0,sizeof(map));
		scanf("%d",&n);
		for(int i=0; i<n; i++)
		{
			scanf("%d%d%d%d%d",&r[i].lx,&r[i].ly,&r[i].rx,&r[i].ry,&r[i].col);
			x[cnt] = r[i].lx;
			y[cnt++] = r[i].ly;
			x[cnt] = r[i].rx;
			y[cnt++] = r[i].ry;
		}
		for(int i=0; i<MAX; i++)
	 		area[i] = 0;
		sort(x,x+cnt);
		sort(y,y+cnt);
		solve(n,cnt);
		int ans = 0;
		printf("Case %d:\n",ind++);
		for(int i=0; i<MAX; i++)
			if( area[i] )
			{
				printf("%d %d\n",i,area[i]);
				ans++;
			}
		if( ans == 1 )
			printf("There is %d color left on the wall.\n",ans);
		else
			printf("There are %d colors left on the wall.\n",ans);
	}
return 0;
}