1.想法 在调用存储过程时候,如果出现出错,应该在页面弹出异常提示信息,快速定位错误原因,
也应该在存储过程和函数过程中尽可能的捕获概率发生较大的异常情况,并且在客户端页面通知(如果发生的话)
首先百度了,借鉴了下面这种方案
自定义oracle抛出异常解决
我的做法
1.函数写法如下
create or replace function GET_PERFORMANCE_COEFFICIENT(PERFORMANCE_SCORE number) return
number is --获取绩效系数
coefficient number(10,2);
maxScore number(10,2);
begin
select max(hign_score) into maxScore from PERFORMANCE_RULE;
select p.coefficient into coefficient from PERFORMANCE_RULE p
where
(PERFORMANCE_SCORE<p.hign_score and PERFORMANCE_SCORE>=p.lower_score)
or (PERFORMANCE_SCORE = maxScore and p.hign_score = maxScore)
;
return coefficient;
exception
when no_data_found then
RAISE_APPLICATION_ERROR(-20002, '未找到绩效系数');
end;
上面的做法就可以让我们的JAVA程序捕获到异常了
2.JAVA端
throws SQLException
public void executeSpGenerateSalary(int year,int month,Double holidayBase) throws SQLException {
String sql="{ CALL sp_generate_salary(?,?,?) }";
Connection conn = getSession().connection();
CallableStatement cs = conn.prepareCall(sql);
cs.setInt(1, year);
cs.setInt(2, month);
cs.setDouble(3, holidayBase);
cs.execute();
cs.close();
}
然后在controller捕获
@RequestMapping("/generateSalary")
@ResponseBody
public Map<String,Object> generateSalary(SalaryEntity salaryEntity){
Map<String,Object> mapResult = new HashMap<String,Object>();
try{
salaryService.generateSalary(salaryEntity);
mapResult.put("result", true);
}
catch(java.sql.SQLException e){
mapResult.put("result", false);
mapResult.put("message", e.getMessage());
e.printStackTrace();
}
catch(Exception e){
e.printStackTrace();
mapResult.put("result", false);
mapResult.put("message", e.getMessage());
}
return mapResult;
}