165. Compare Version Numbers

原题

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

1.0 = 1.0.00

代码实现

public class Solution {
    public int CompareVersion(string version1, string version2) {
        string[] parts1 = version1.Split('.');
        string[] parts2 = version2.Split('.');
        for(int i=0,j=0; i<parts1.Length || j<parts2.Length;i++,j++){
            if(i==parts1.Length){
                while(j<parts2.Length ){
                    if(isAllZeros(parts2[j++])) continue;
                    return -1;
                }
                break;
            } 
            if(j==parts2.Length) {
                while(i<parts1.Length ){
                    if(isAllZeros(parts1[i++])) continue;
                    return 1;
                }
                break;
            }
            if(Convert.ToInt32(parts1[i]) < Convert.ToInt32(parts2[i]))
                return -1;
            else if(Convert.ToInt32(parts1[i]) > Convert.ToInt32(parts2[i]))
               return 1;
        }
        return 0;
    }
    //is all Zeros? 
    //v1 = "1.0.00" v2 = "1.0.0.0000" => v1=v2
    private bool isAllZeros(string s){
        foreach(var c in s){
            if(c!='0') return false;
        }
        return true;
    }
}

题库

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完成题目索引

http://blog.csdn.net/daigualu/article/details/73008186