soap用post传递xml及xml问题

首先别人 已经做了一个库

http://sourceforge.net/projects/ksoap2/

http://code.google.com/p/ksoap2-android/wiki/SourceCodeHosting?tm=4

 

如果想自己写一个

1.传递简单html 以及数据问题

HttpClient httpclient = new DefaultHttpClient(); 
        // 你的地势

        HttpPost httppost = new HttpPost("http://192.71.100.21:8000"); 
 
        try { 
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); 
            // 数据传送的

            nameValuePairs.add(new BasicNameValuePair("id", "12345")); 
            nameValuePairs.add(new BasicNameValuePair("stringdata","AndDev is Cool!")); 
 
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
 
            HttpResponse response; 
            response = httpclient.execute(httppost); 
        } catch (ClientProtocolException e) { 
            // TODO Auto-generated catch block 
            e.printStackTrace(); 
        } catch (IOException e) { 
            // TODO Auto-generated catch block 
            e.printStackTrace(); 
        } 
2.传递xml

 

 

public void postData() { 
         // Create a new HttpClient and Post Header   
         HttpClient httpclient = new DefaultHttpClient();   
         HttpPost httppost = new HttpPost("http://10.10.4.35:53011/"); 
 
         try {   
           
              
         } catch (ClientProtocolException e) {   
             // TODO Auto-generated catch block   
         } catch (IOException e) {   
             // TODO Auto-generated catch block   
         }   
     } 

                                     StringEntity se = new StringEntity(SOAPRequestXML,HTTP.UTF_8);

                                         se.setContentType("text/xml");

                         httppost.setHeader("Content-Type","application/soap+xml;charset=UTF-8");

                         httppost.setEntity(se);

                        BasicHttpResponse httpResponse = (BasicHttpResponse) httpclient .execute(httppost);

                        response.put("HTTPStatus",httpResponse.getStatusLine().toString());