DATAFILE的extents的回收resize
DATAFILE的extents的回收resize
ORACLE Alter database datafile resize extents
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LMT TABLESPACE
，有时候虽然里面的数据不是很多，但是RESIZE DATAFILE
的时候会失败，因为一些OBJECT
的EXTENTS
已经扩展到DATAFILE
的边缘（最大的地方）。下面的SQL
可以让我们找到前5
个最边缘的OBJECT
select *
from (
select owner, segment_name,
segment_type, block_id
from dba_extents
where file_id =
( select file_id
from dba_data_files
where file_name = :FILE ) --
用你的
DATAFILE
代替
order by block_id desc
)
where rownum <= 5
结果是行如下面的五行
OWNER
--------------------------------------------------------
SEGMENT_NAME
--------------------------------------------------------
SEGMENT_TYPE BLOCK_ID
------------------------------------ ----------
PERFSTAT
STATS$PARAMETER
TABLE 30345
讲得到的这些OBJECT通过
ALTER TABLE MOVE
或
ALTER INDEX REBUILD
转移到其他
DATAFILE中去，依次类推，直到满足你要RESIZE的空间为止。
下面的SQL可以得到ALTER DATABASE DATAFILE RESIZE字句，自动判断可以RESIZE到什么地方。
column value new_val blksize
select value
from v$parameter
where name = 'db_block_size'
/
select 'alter database datafile ''' ||
file_name || ''' resize ' ||
ceil( (nvl(hwm,1)*&&blksize)/1024/1024 )
|| 'm;' cmd
from dba_data_files a,
( select file_id,
max(block_id+blocks-1) hwm
from dba_extents
group by file_id ) b
where a.file_id = b.file_id(+)
and
ceil(blocks*&&blksize/1024/1024)-
ceil((nvl(hwm,1)*
&&blksize)/1024/1024 ) > 0
/
3: ceil( (nvl(hwm,1)*&&blksize)/1024/1024 )
3: ceil( (nvl(hwm,1)*8192)/1024/1024 )
12: ceil(blocks*&&blksize/1024/1024)-
12: ceil(blocks*8192/1024/1024)-
14: &&blksize)/1024/1024 ) > 0
14: 8192)/1024/1024 ) > 0
CMD
--------------------------------------------------------------------------------
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/SYSTEM01.DBF' resize 413m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/UNDOTBS01.DBF' resize 75m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/CWMLITE01.DBF' resize 10m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/DRSYS01.DBF' resize 10m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/ODM01.DBF' resize 10m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/TOOLS01.DBF' resize 7m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/USERS01.DBF' resize 239m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/XDB01.DBF' resize 38m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/DATA01.DBF' resize 720m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/WWM.DBF' resize 1m;
alter database datafile 'D:/ORACLE/ORADATA/SIDDB/DATA02.DBF' resize 1m;
alter database datafile 'D:/ORACLE/ORADATA/SIDDB/DATA04.DBF' resize 1m;
alter database datafile 'D:/ORACLE/ORADATA/SIDDB/DATA03.DBF' resize 1m;
alter database datafile 'E:/ORACLE/ORADATA/SIDDB/INDX01.DBF' resize 1m;
测试下
SQL> alter database datafile 'E:/ORACLE/ORADATA/SIDDB/INDX01.DBF' resize 1m;
执行成功
或者换个写法直接用一下命令整体察看并得到结果
SELECT
a.file_id,
a.file_name
file_name,
CEIL( ( NVL( hwm,1 ) * blksize ) / 1024 / 1024 ) smallest,
CEIL( blocks * blksize / 1024 / 1024 ) currsize,
CEIL( blocks * blksize / 1024 / 1024 ) -
CEIL( ( NVL( hwm,1) * blksize ) / 1024 / 1024 ) savings,
'alter database datafile ''' || file_name || ''' resize ' ||
CEIL( ( NVL( hwm,1) * blksize ) / 1024 / 1024 ) || 'm;' cmd
FROM
DBA_DATA_FILES a,
(
SELECT file_id, MAX( block_id + blocks - 1 ) hwm
FROM DBA_EXTENTS
GROUP BY file_id
) b,
(
SELECT TO_NUMBER( value ) blksize
FROM V$PARAMETER
WHERE name = 'db_block_size'
)
WHERE
a.file_id = b.file_id(+)
AND
CEIL( blocks * blksize / 1024 / 1024 ) - CEIL( ( NVL( hwm, 1 ) * blksize ) / 1024 / 1024 ) > 0
ORDER BY 5 desc
/
FILE_ID
----------
FILE_NAME
--------------------------------------------------------------------------------
SMALLEST CURRSIZE SAVINGS
---------- ---------- ----------
CMD
--------------------------------------------------------------------------------
11
E:/ORACLE/ORADATA/SIDDB/DATA01.DBF
721 3000 2279
alter database datafile 'E:/ORACLE/ORADATA/SIDCDB/DATA01.DBF' resize 721m;