XFire集成Spring配置

1.在项目的src下建了一个xfireservice的包，然后在这个包下建了一个名为XFireService的接口和XFireServiceImpl这个实现接口的类。把相关的jar文件添加进项目里。

XFireService.java接口

package xfireservice;
public interface XFireService {
	public String sayHello();
}

XFireServiceImpl.java
package xfireservice;
import org.springframework.stereotype.Component;
@Component("XFireService")
public class XFireServiceImpl implements XFireService {
	public String sayHello() {
		return "Hello World!";
	}
}

2.在放置配置文件的包里新建一个xfireService.xml的配置文件，代码如下：

<?xml version="1.0" encoding="UTF-8"?>
<beans
	xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns:p="http://www.springframework.org/schema/p"
	xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
	 
	<import resource="classpath:org/codehaus/xfire/spring/xfire.xml"/>
	<bean id="XFireServiceImpl" class="xfireservice.XFireServiceImpl"></bean>	
	<bean id="XFireServiceImpl.xfire"
		class="org.codehaus.xfire.spring.remoting.XFireExporter">
		<property name="serviceFactory" ref="xfire.serviceFactory"></property>	
		<property name="xfire" ref="xfire"></property>
		<property name="serviceBean" ref="XFireServiceImpl"></property>
		<property name="serviceClass" value="xfireservice.XFireService"></property>
	</bean>	
	<bean id="handlerMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
		<property name="mappings">
			<props>
				<prop key="/XFireServiceImpl">XFireServiceImpl.xfire</prop>
			</props>
		</property>
	</bean>
</beans>  

3. 在web.xml文件中加上相关配置

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
	http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>
			classpath:xfireService.xml
		</param-value>
	</context-param>
<servlet>
  		<servlet-name>XFireService</servlet-name>
  		<servlet-class>org.codehaus.xfire.spring.XFireSpringServlet</servlet-class>
  		<init-param>
   			<param-name>contextConfigLocation</param-name>
   			<param-value>classpath:xfireService.xml</param-value>
  		</init-param>
 	</servlet>
 	<servlet-mapping>
  		<servlet-name>XFireService</servlet-name>
  		<url-pattern>/xfireservice/*</url-pattern>
 	</servlet-mapping>

上面这几个都配置完以后，启动tomcat就可以访问了，我项目里的路径为http://localhost:8080/arweb/xfireservice/XFireService?wsdl
我在配置时，最后遇到了一个问题，在web.xml文件中，我的servlet-class写的是<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>，启动项目后访问的时候报404错误，后来改成<servlet-class>org.codehaus.xfire.spring.XFireSpringServlet</servlet-class>这个就可以了，这应该是和我引进的包有影响，而且我的项目是用Spring框架写的。