1242

iOS-支付宝&微信支付

//应用的APPIDkWXAppID@"wxc82cXXXXXXXX"//AppSecretkWXAppSecret@"7f47bfe47b84XXXXXXXXXXXx"//商户号kWXMchID@"1242XXXXXX
Eric博客·2020-07-31 10:55

三好一改 2019年5月28日 1242期

1好：拜访客户今次拜访一个客户，此客户之前有过沟通，在一些思路上已经达成了一致，今次拜访的目的是落实产品和对市场推广进行有效的沟通，以及落实客户的展会。由于有之前的沟通基础，各方面沟通非常顺利，客户的定位与企业的定位很匹配，目标客户一致，经营思路也很相近。在客户的门店，看到来来往往的客户，都是本地知名的餐饮一线品牌，还有客户主动过来结款，说明客户的客情做的很到位。客户计划做一场推广活动，看到客户主
8f9514241cc4·2020-07-30 23:16

启动图。引导页以及EAIntroView的使用

ios启动图：1242x2208（6plus）R5.5位置750x1334（6）R4.7位置640x960（4/4s）2x位置640x1136（5/5s/5c）R4位置网址：http://www.360doc.com
weixin_33907511·2020-07-30 12:29

hdoj 1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):21713AcceptedSubmission(s):7748ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
张小象·2020-07-30 06:04

hdoj 1242 Rescue （bfs+优先队列）

运算符重载定义：C++中预定义的运算符的操作对象只能是基本数据类型。但实际上，对于许多用户自定义类型（例如类），也需要类似的运算操作。这时就必须在C++中重新定义这些运算符，赋予已有运算符新的功能，使它能够用于特定类型执行特定的操作。运算符重载的实质是函数重载，它提供了C++的可扩展性，也是C++最吸引人的特性之一。运算符重载是通过创建运算符函数实现的，运算符函数定义了重载的运算符将要进行的操作。
巍笑i·2020-07-30 06:02

HDOJ1242Rescue(BFS+优先队列)

DescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#include#include#include#defineMAXN10000usingnamespacestd;charmap[1100][1100];intvis[1100][1100];i
Zhac·2020-07-30 06:41

HDU - 1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):36265AcceptedSubmission(s):12541ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.T
zezzezzez·2020-07-30 06:00

HDU - 1242 Rescue

AngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#include#include#defineinf0x3f3f3f3fusingnamespacestd;typedefstruct{intx,y;intstep;}node;struct//优先队列重载优先级{bo
zbspy_ZJF·2020-07-30 06:17

1242 Rescue

RescueProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,Musingnamespacestd;usingLL=int64_t;charans[205][205];intdx,dy;intn,m;boolbook[205][205];inttem
yqdjl6·2020-07-30 06:47

hdu1242 Rescue(BFS +优先队列 or BFS )

pid=1242题意：Angel被传说中神秘的邪恶的Moligpy人抓住了！他被关在一个迷宫中。迷宫的长、宽不超过200。迷宫中有不可以越过的墙以及监狱的看守。
yew1eb·2020-07-30 06:11

HDU 1242 Rescue（bfs+优先队列）

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):24119AcceptedSubmission(s):8504ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
Calm微笑·2020-07-30 06:52

HDU 1242 Rescue

这道题没看懂题，也没想到天使有多个朋友，而且特坑的是多组输入，唉被坑了，真不爽，dfs足以解决了AC代码：#include#include#include#include#include#includeusingnamespacestd;#defineN250charMap[N][N];intdir[4][2]={1,0,0,1,0,-1,-1,0};intbook[N][N],minx,sx,s
Vain957·2020-07-30 06:17

HDU 1242 Rescue（BFS优先队列）

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):28234AcceptedSubmission(s):10002ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.T
香橙之殇·2020-07-30 05:37

HDU :1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):27990AcceptedSubmission(s):9900ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
温姑娘·2020-07-30 05:10

杭电1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):20846AcceptedSubmission(s):7446ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
非常可乐（이녕）·2020-07-30 05:38

HDU——1242 Rescue（广搜）

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):21875AcceptedSubmission(s):7792ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
这个异常不抛出·2020-07-30 05:21

(HDU - 1242)Rescue

(HDU-1242)RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission
Hold_My_Own·2020-07-30 05:52

【BFS】HDU1242Rescue

pid=1242ProblemDescriptionAngelwascaughtbytheMOLIGPY!
wlxsq·2020-07-30 05:36

Rescue HDU1242 bfs+优先队列

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#definerep(i,x,y)for(inti=(x);ib.time;}};intjudge(intx,inty){if(x=n||y>=m||vis[x][y]==1||s[x][y]=='
狂飙的小蜗牛呦·2020-07-30 04:42

HDU 1242 Rescue (搜索)

pid=1242)RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission
>执迷不悔<·2020-07-30 04:40

hdu1242 Rescue(BFS+优先队列)

原题链接大意：天使被MOLIGPY抓住了！他被Moligpy监禁了。监狱被描述为N*M（N，Mpq=newPriorityQueue=0&&x=0&&y{intx,y,t;publicNode(intx,inty,intt){this.x=x;this.y=y;this.t=t;}@OverridepublicintcompareTo(Nodeo){returnthis.t-o.t;}}}
一叶之修·2020-07-30 04:58

HDOJ1242 拯救天使 (BFS)

题目：1242Rescue1//这是一个比较标准的bfs，没有经过任何优化，但是思路比较清晰，容易看懂。
weixin_33736649·2020-07-30 03:46

HDOJ/HDU 1242 Rescue(经典BFS深搜-优先队列)

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#include#includeusingnamespacestd;structnode{intx,y,t;friendbooloperator=n||y=m){return0;}i
weixin_30919919·2020-07-30 02:53

HDU——1242Rescue（BFS+优先队列求点图最短路）

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):25203AcceptedSubmission(s):8936ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
weixin_30619101·2020-07-30 02:26

HDU 1242 Rescue BFS+优先队列

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,Ma.x;//最小值优先}};structnumber2{intx;booloperator#include#include#include#defineMAXN205usingnamespacest
weixin_30568715·2020-07-30 02:17

【搜索】POJ1242:Rescue

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M2#include3#include4#include5usingnamespacestd;6charmapp[205][205];7boolvis[205][205];8intdx[4]={0,1
weixin_30436891·2020-07-30 02:23

[ACM] hdu 1242 【BFS】

pid=1242参考链接：http://www.acmerblog.com/hdu-1242-Rescue-1605.html普通队列+bfs确实是蒙对的，因为击败守卫需要消耗时间1，因此普通队列每一次出队列的元素只是步数上最优
weixin_30367169·2020-07-30 02:07

hdu1242 Rescue bfs+优先队列

直接把Angle的位置作为起点，广度优先搜索即可，这题不是步数最少，而是time最少，就把以time作为衡量标准，加入优先队列，队首就是当前time最少的。遇到Angle的朋友就退出。只需15msAC代码：#include#include#includeusingnamespacestd;constintmaxn=202;intd[maxn][maxn];intn,m;charG[maxn][ma
weixin_30301183·2020-07-30 02:53

HDUoj 1242 Rescue ( BFS+优先队列

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):29289AcceptedSubmission(s):10347ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.T
Yishui_Blog·2020-07-30 02:52

HDU - 1242 - Rescue (BFS)

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):32900AcceptedSubmission(s):11516ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.T
vloai·2020-07-30 02:38

HDU 1242 Rescue

DescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#includeusingnamespacestd;constintdir[4][2]={{0,1},{1,0},{0,-1},{-1,0}};charmatrix[202][202];charu
ultimater·2020-07-30 02:04

hdu 1242 Rescue (bfs+优先队列)

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):15639AcceptedSubmission(s):5673题意：给出起点和终点走迷宫求最短路（注意起点有多个）简单bfs（由于有多个起点所以上做下处理从终点起去搜起点）+优先队列求出最优解#include
范贰小青年·2020-07-30 02:25

Hduoj1242【广搜+优先队列】

/*RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):16997AcceptedSubmission(s):6151ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.
乐着过一辈子·2020-07-30 01:21

hdu 1242 Rescue（BFS优先队列）

ProblemCTimeLimit:2000/1000ms(Java/Other)MemoryLimit:65536/32768K(Java/Other)TotalSubmission(s):19AcceptedSubmission(s):9ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Thepriso
A_Happyer·2020-07-30 01:48

HDU 1242 Rescue (BFS+优先队列)

pid=1242angel被困在迷宫里，他的朋友们去救。n*m的迷宫，'.'代表路，'#'代表墙，'x'代表守卫，'r'代表朋友，'a'代表ANGEL。求最少时间。
珞辰·2020-07-30 01:43

hdu1242

pid=1242题目：RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission
FBI-PC·2020-07-30 01:06

HDU-1242——DFS+优先队列

题意大概就是：从起点r到终点a的最短距离，经过.那么时间加1；经过x那么时间加2；#代表障碍不能通过；也有可能没有a。。。。。#include#include#include#include#include#includeusingnamespacestd;structnode{intx,y,step;friendbooloperator=n||y>=m||!vis[x][y]||ch[x][y]
Dragon--C·2020-07-30 01:12

杭电1242————搜索之优先队列

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):15823AcceptedSubmission(s):5731ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
SixDayy·2020-07-30 01:32

hdu 1242 Rescue bfs+优先队列priority

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):18318AcceptedSubmission(s):6544ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
luckyone2014·2020-07-30 01:00

HDU1242-Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):16313AcceptedSubmission(s):5925ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
光仔December·2020-07-30 01:59

HDU1242 Rescue-BFS，优先队列

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#defineinf40010intmin;charmap[210][210];intz[4][2]={{-1,0},{1,0},{0,-1},{0,1}};intfind(inti
szf向日葵·2020-07-30 01:59

HDU 1242 -Rescue (双向BFS）&&（ BFS+优先队列)

题目链接：Rescue进度落下的太多了，哎╮(╯▽╰)╭，渣渣我总是埋怨进度比别人慢。。。为什么不试着改变一下捏。。。。开始以为是水题，想敲一下练手的，后来发现并不是一个简单的搜索题，BFS做肯定出事。。。后来发现题目里面也有坑题意是从r到a的最短距离，“.”相当时间单位1，“x”相当时间单位2，求最短时间HDU搜索课件上说，这题和HDU1010相似，刚开始并没有觉得像剪枝，就改用双向BFS0ms
品尝这杯浓咖啡·2020-07-30 01:27

HDU1242 Rescue 【BFS】

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):16314AcceptedSubmission(s):5926ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
长风Qiu·2020-07-30 01:45

hdu oj 1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14222AcceptedSubmission(s):5164ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
尘飞acmer·2020-07-30 01:54

HDU-1242 Rescue

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#include#inclu
J_Sure·2020-07-30 01:52

HDU--1242 -- Rescue [广搜]

RescueTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):12409AcceptedSubmission(s):4541ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.Th
kiya-z·2020-07-30 01:39

HDU1242 Rescue

#include#include#include#include#include#include#include#include#includeusingnamespacestd;intmap[211][211];intn,m;intx_s,y_s;intx_e,y_e;structnode{intx,y;intstep;friendbooloperator=n||y=m)return1;if(m
韦我独尊-德天独厚·2020-07-30 01:45

hdu1242

这题是搜索的好题，第一次做不会做，第二次还是勉强。。噗噗。。。要想真正会做，还是要自己想啊。。呜呜。。//有多条路径，如何选出最短的那条就退出呢？//还以为是简单的bfs但其实不是//用优先队列又做了一遍还是不对#include#include#include#includeusingnamespacestd;intr,c;charmap[210][210];boolvis[210][210];i
穆林幕·2020-07-30 01:40

hdu1242 Rescue 优先队列BFS

Angel'sfriendswanttosaveAngel.Theirtaskis:approachAngel.Weassumethat"approachAngel"istogettothepositionwhereAngelstays.Whenthere'saguardinthegrid,wemustkillhim(orher?)tomoveintothegrid.Weassumethatwem
小七和小墨·2020-07-30 01:52

HDU 1242 Rescue（dfs深搜）

ProblemDescriptionAngelwascaughtbytheMOLIGPY!HewasputinprisonbyMoligpy.TheprisonisdescribedasaN*M(N,M#include#include#include#include#include#include#include#include#include#definemem(a,x)memset(a,x,s
Must_so·2020-07-30 01:43
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