AtCoder Beginner Contest 290 G. Edge Elimination(思维题 枚举+贪心)
题目T(Tusingnamespacestd;constintN=65;typedeflonglongll;intt,c;lld,k,x,a[N],sum[N],now,cur;intmain(){cin>>t;while(t--){cin>>d>>k>>x;a[0]=1;sum[0]=1;cur=0;for(inti=1;i0){llnex=(now-1)/k;cur+=sum2/nex;//p