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Combination
Combination
Sum 组合求和 解题报告
1解题思想原题是说给定一些数字和一个目标值,从这些数字中挑选几个加起来,加起来后他的和正好等于目标值,其中一个数字可以选择多次。要求输出的不能有重复,并且组内的顺序是不能降序的。这道题首先必须要想到的就是排序了,排序是非常基本,又非常常用的一种操作。然后我们需要排除重复的(注意可以重复选择一个数,所以重复的最好先去掉,因为我们需要进行递归回溯,这样做可以降低无谓的开销)随后我们就开始求解,求解的做
MebiuW
·
2016-04-10 23:00
LeetCode
组合
递归
回溯
USACO 1.3-
Combination
Lock
/* ID:m1590291 TASK:combo LANG:C++ */ #include #include #include /****************************************************************************************************************** 此题没什么难度,简单遍历即可 坑一:b
qq_28300479
·
2016-04-04 23:00
Combination
Sum & 40.
Combination
Sum II分析及解法&DFS
39.CombinationSumTotalAccepted: 87334 TotalSubmissions: 283947 Difficulty: MediumGivenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The sa
Jin_Kwok
·
2016-04-01 16:00
LeetCode
C++
search
first
DFS
回溯法
Deepth
[LeetCode]
Combination
Sum III
Findallpossiblecombinationsof k numbersthatadduptoanumber n,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.Ex
CiaoLiang
·
2016-03-27 12:00
Combination
Sum II
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.Eachnumberin C mayonlybeused once inthecombination.Note:Allnumbers(includingtarg
u014568921
·
2016-03-19 10:00
LeetCode
Combination
Sum
Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbers(includi
u014568921
·
2016-03-19 00:00
LeetCode
Combination
Sum II
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.Eachnumberin C mayonlybeused once inthecombination.Note:Allnumbers(includingtarg
水果拼盘武士G
·
2016-03-18 23:00
Combination
Sum
Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbers(includi
水果拼盘武士G
·
2016-03-17 23:00
Combination
Sum III
Findallpossiblecombinationsof k numbersthatadduptoanumber n,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.Ex
u014568921
·
2016-03-16 20:00
LeetCode
leetcode:
Combination
Sum 【Java】
一、问题描述Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbers(i
tterminator
·
2016-03-16 15:00
LeetCode
Combination
Sum | Java最短代码实现
原题链接:39.CombinationSum拓展博文:CombinationSumII|Java最短代码实现【思路】基本思路是先排好序,然后每次递归中把剩下的元素一一加到结果集合中,并且把目标减去加入的元素,然后把剩下元素(包括当前加入的元素)放到下一层递归中解决子问题。算法复杂度因为是NP问题,所以自然是指数量级的:publicList>combinationSum(int[]candidate
happyaaaaaaaaaaa
·
2016-03-15 17:00
backtracking
Combination
Sum II | Java最短代码实现
原题链接:40. CombinationSumII基础博文:CombinationSum【思路】和CombinationSum十分类似,都是用回溯算法。只不过candidates中含有重复元素,要求不能有重复组合:publicList>combinationSum2(int[]candidates,inttarget){ ArrayList>result=newArrayList>(); Arra
happyaaaaaaaaaaa
·
2016-03-15 16:00
array
backtracking
lintcode-数字组合II
C中每个数字在每个组合中只能使用一次类型:回溯地址:http://www.lintcode.com/zh-cn/problem/
combination
-sum-ii/注意事项所有的数字(包括目标数字)均为正整数
鬼谷神奇
·
2016-03-14 10:36
HNU 2015暑期新队员训练赛2 B
Combination
先转化出求Cnr中有多少奇数其实就是(n的二进制数中1的个数为k,则这个奇数为2^k)因为数很大,故要快速求出区间的奇数然后求0–low-1的奇数,0-high的奇数,相减既是结果求0–N中Cnr的奇数通过上图可以快速求出1----(2^N)-1的个数,其他数则可以用迭代的方式求出来(代码比赛写的有点残)#include#include#include#include#include#includ
Aoxuets
·
2016-03-14 10:43
HDU 3104
Combination
Lock
Description给一个钟,N个刻度,再给T1,T2,T3个刻度,执行以下操作转2圈,再顺时针转到T1再转1圈,逆时针转到T2再顺时针转到T3问最多要转多少步?然后呵呵,这个只能钟转刻度不能转,所以说上面的都是逗你的,顺时针==逆时针,逆时针==顺时针Algorithm转到T1以后,后面的都是定的,所以只需要决定第一步最大步数就好了想都不要想就是T1旁边的那个,这样的话一个要转3*n-1,肯定
YYecust
·
2016-03-12 10:00
39 / 40
Combination
Sum(I / II)
TotalAccepted: 83289 TotalSubmissions: 274461 Difficulty: MediumGivenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumber
EbowTang
·
2016-03-11 09:00
LeetCode
C++
面试
二叉树
回溯法
39 / 40
Combination
Sum(I / II)
TotalAccepted: 83289 TotalSubmissions: 274461 Difficulty: MediumGivenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumber
EbowTang
·
2016-03-11 09:00
LeetCode
C++
面试
二叉树
回溯法
Combination
Sum III
TotalAccepted: 26890 TotalSubmissions: 77419 Difficulty: MediumFindallpossiblecombinationsof k numbersthatadduptoanumber n,giventhatonlynumbers from1to9canbeusedandeachcombinationshouldbeauniquesetofn
EbowTang
·
2016-03-10 20:00
LeetCode
C++
面试
动态规划
回溯法
Combination
Sum III
TotalAccepted: 26890 TotalSubmissions: 77419 Difficulty: MediumFindallpossiblecombinationsof k numbersthatadduptoanumber n,giventhatonlynumbers from1to9canbeusedandeachcombinationshouldbeauniquesetofn
EbowTang
·
2016-03-10 20:00
LeetCode
C++
面试
动态规划
回溯法
Combination
Sum
39.CombinationSum Problem'sLink ----------------------------------------------------------------------------Mean: 给你一个待选集合s和一个数n,让你找出集合s中相加之和为n的所有组合.(每个数可选多次)analyse:作此题需对递归有一定的理解.Timecomplexity:O(N)
crazyacking
·
2016-03-05 20:00
Combination
Sum
1.每个元素可用多次Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbe
ArgenBarbie
·
2016-03-05 18:00
Combination
Sum III
Findallpossiblecombinationsofknumbersthatadduptoanumbern,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.Examp
KickCode
·
2016-02-21 12:28
组合
回溯法
Combination
Sum III
阅读更多Findallpossiblecombinationsofknumbersthatadduptoanumbern,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.E
KickCode
·
2016-02-21 02:00
回溯法
组合
Combination
Sum III
阅读更多Findallpossiblecombinationsofknumbersthatadduptoanumbern,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.E
KickCode
·
2016-02-21 02:00
回溯法
组合
Combination
Sum III
Findallpossiblecombinationsofknumbersthatadduptoanumbern,giventhatonlynumbersfrom1to9canbeusedandeachcombinationshouldbeauniquesetofnumbers.Ensurethatnumberswithinthesetaresortedinascendingorder.Examp
偏爱纯白色
·
2016-02-20 17:00
Combination
Sum,
Combination
Sum II,
Combination
Sum III
39.CombinationSumGivenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:A
zengzy
·
2016-02-18 17:00
Leetcode -
Combination
Sum
题目链接 https://leetcode.com/problems/
combination
-sum/ 思路先对candidates进行排序,原因有两点,一是最后的结果中要求每个combo中的数字是排好序的
sjz@cv
·
2016-02-17 20:00
DFS + BackTracking
这是Leetcode经典系列题,就是考对于DFS的理解,确实有技术含量想上来
Combination
上来热一下身,如何回溯。
伊萨卡钢琴家
·
2016-02-14 12:28
Leetcode
backtracking
Combination
Sum
Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbers(includi
walkwalkwalk
·
2016-02-07 15:00
Combination
Sum II
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.Eachnumberin C mayonlybeused once inthecombination.Note:Allnumbers(includingtarg
walkwalkwalk
·
2016-02-06 20:00
Combination
Sum III
题目链接:https://leetcode.com/problems/
combination
-sum-iii/题目描述:寻找所有满足k个数之和等于n的组合,只允许使用数字1-9,并且每一种组合中的数字应该是唯一的
codeTZ
·
2016-02-04 20:00
LeetCode
回溯
Combination
Sum II
题目链接:https://leetcode.com/problems/
combination
-sum-ii/题目描述:给出一组候选数字(C)和目标数字(T),找出C中所有的组合,使组合中数字的和为T。
codeTZ
·
2016-02-03 10:00
LeetCode
回溯
Combination
Sum
题目链接:https://leetcode.com/problems/
combination
-sum/题目描述:给出一组候选数字(C)和目标数字(T),找出C中所有的组合,使组合中数字的和为T。
codeTZ
·
2016-02-03 10:00
LeetCode
回溯
Combination
Sum
Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.ThesamerepeatednumbermaybechosenfromCunlimitednumberoftimes.Note:Allnumbers(includingtarge
KickCode
·
2016-01-31 13:42
组合求和
Combination
Sum II
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.EachnumberinCmayonlybeusedonceinthecombination.Note:Allnumbers(includingtarget)will
KickCode
·
2016-01-31 12:04
java
组合
Combination
Sum II
阅读更多Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.EachnumberinCmayonlybeusedonceinthecombination.Note:Allnumbers(includingtarget)
KickCode
·
2016-01-29 02:00
组合
java
Combination
Sum II
阅读更多Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.EachnumberinCmayonlybeusedonceinthecombination.Note:Allnumbers(includingtarget)
KickCode
·
2016-01-29 02:00
组合
java
Combination
Sum II leetcode Python 2016 new season
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.Eachnumberin C mayonlybeused once inthecombination.Note:Allnumbers(includingtarg
hyperbolechi
·
2016-01-24 10:00
Combination
Sum leetcode python 2016 new season
Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsin C wherethecandidatenumberssumsto T.The same repeatednumbermaybechosenfrom C unlimitednumberoftimes.Note:Allnumbers(includi
hyperbolechi
·
2016-01-23 13:00
2982:
combination
|lucas定理
卢卡斯定理裸题忘输出回车wa了两发#include #defineM10007 usingnamespacestd; intfac[10086],inv[10086]; intcal(intx) { inty=M-2,ans=1; while(y) { if(y&1)ans=ans*x%M; x=x*x%M; y>>=1; } returnans; } voidpre() { fac[0]=1;f
ws_yzy
·
2016-01-17 14:00
数论
unsupported format or
combination
of ···解决方法
编译连接时候是不会出错的,但是运行时会说“unsupportedformat。。。。”如下图: 出错原因在cvCanny函数cvCanny函数用来进行边缘检测,函数原型如下:CVAPI(void) cvCanny(constCvArr*image,CvArr*edges,doublethreshold1, doublethres
我叮叮咚咚
·
2016-01-16 16:00
【LEETCODE】216-
Combination
Sum III [Python]
题目:https://leetcode.com/problems/
combination
-sum-iii/Findallpossiblecombinationsofknumbersthatadduptoanumbern
aliceyangxi1987
·
2016-01-07 10:00
LeetCode
python
LeetCode
Combination
Sum II
LeetCode解题之CombinationSumII原题在一个数组(存在重复值)中寻找和为特定值的组合。注意点:所有数字都是正数组合中的数字要按照从小到大的顺序原数组中的数字只可以出现一次结果集中不能够有重复的组合例子:输入:candidates=[10,1,2,7,6,1,5],target=8输出:[[1,1,6],[1,2,5],[1,7],[2,6]]解题思路这道题和Combinatio
u013291394
·
2016-01-04 14:00
LeetCode
算法
python
回溯法
traceback
LeetCode
Combination
Sum
LeetCode解题之CombinationSum原题在一个集合(没有重复数字)中找到和为特定值的所有组合。注意点:所有数字都是正数组合中的数字要按照从小到大的顺序原集合中的数字可以出现重复多次结果集中不能够有重复的组合虽然是集合,但传入的参数类型是列表例子:输入:candidates=[2,3,6,7],target=7输出:[[2,2,3],[7]]解题思路采用回溯法。由于组合中的数字要按序排
u013291394
·
2016-01-04 09:00
LeetCode
算法
python
笔试
回溯法
Combination
Sum III 解题报告
题目链接:https://leetcode.com/problems/
combination
-sum-iii/Findallpossiblecombinationsof k numbersthatadduptoanumber
qq508618087
·
2015-12-30 06:00
LeetCode
算法
DFS
backtracking
[LeetCode]040-
Combination
Sum II
题目:Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.EachnumberinCmayonlybeusedonceinthecombination.Note:Allnumbers(includingtarget)w
htx931005
·
2015-12-29 14:00
LeetCode
[LeetCode]039-
Combination
Sum
题目:Givenasetofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT.ThesamerepeatednumbermaybechosenfromCunlimitednumberoftimes.Note:Allnumbers(includingta
htx931005
·
2015-12-29 14:00
LeetCode
Combination
Sum II 解题报告
题目链接:https://leetcode.com/problems/
combination
-sum-ii/Givenacollectionofcandidatenumbers(C)andatargetnumber
qq508618087
·
2015-12-21 09:00
LeetCode
backtracking
深搜
Combination
Sum 解题报告
题目链接:https://leetcode.com/problems/
combination
-sum/Givenasetofcandidatenumbers(C)andatargetnumber(T),
qq508618087
·
2015-12-21 08:00
LeetCode
DFS
backtracking
leetcode
Combination
Sum II python
Givenacollectionofcandidatenumbers(C)andatargetnumber(T),findalluniquecombinationsinCwherethecandidatenumberssumstoT. EachnumberinCmayonlybeusedonceinthecombination. Note: Allnumbers(includingt
hao.ma
·
2015-12-20 21:00
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