Multiplication

ROR学习系列5－Ruby基础4－Ruby中的运算符

addition puts value value = value / 2   #division puts value value = value * 3   #multiplication
jiyanliang·2008-01-08 13:00

Big number multiplication 大整数乘法

constintN=1100;structBigNum...{intfront;intdata[N+1];};BigNum&Mulit(BigNumup,BigNumdown)...{inti,k,carry,v;BigNumprod;prod.front=up.front+down.front-N+1;for(i=prod.front;i=down.front;i--)...{BigNumtmp
wapysun·2008-01-05 09:00

get quotient without division and multiplication

unsignedintNDivide3(unsignedintn)...{unsignedintans=0,i,b;while(n>3)...{b=n>>2;ans+=b;n=n^3+b;}if(3==n)return++ans;elsereturnans;}
wapysun·2007-12-17 09:00

get quotient without division and multiplication

unsignedintNDivide3(unsignedintn)...{unsignedintans=0,i,b;while(n>3)...{b=n>>2;ans+=b;n=n^3+b;}if(3==n)return++ans;elsereturnans;}
wapysun·2007-12-17 09:00

MySQL数据库function列表

=(notequal)"%(modulo)%(wildcardcharacter)&(bitwiseAND)&&(logicalAND)()(06-3)(Control-Z)\z*(multiplication
风故故，也依依·2007-12-03 07:00

[导入]3.5.1 Operators运算符之算术运算符

Theusualarithmeticoperators+–*/areusedinJavaforaddition,subtraction,multiplication,anddivision.The/operatordenotesintegerdivisionifbothargumentsareintegers
X-Spirit·2007-08-30 12:00

ZOJ-1026-Modular multiplication of polynomials

这道题很怪的，你会发现如果老老实实按手动的方法进行多项式除法，时间肯定超，而且题目中有点诱引你建立加法，乘法，取模的函数，但其实加法的函数是不必要的，因为如果在取模中按部就班调用加法，会超时。解决办法就是利用模2的特性，直接用除的多项式系数对齐被除系数的最高部分，加上，然后再移到加后的被除系数最高部分，再加，直到最高的degree小于除式的degree这一题开始，采用了单进单出的输入输出方式，借鉴
immortality·2007-07-16 17:00

Matrix Chain Multiplication

Timelimit:1SecondsMemorylimit:32768KTotalSubmit:468AcceptedSubmit:308Matrixmultiplicationproblemisatypicalexampleofdynamicalprogramming.SupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,Dand
kinglliam·2006-05-18 00:00
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