Multiplication

poj3318--Matrix Multiplication（随机算法）

题目链接：点击打开链接题目大意：给出三个n*n矩阵的矩阵a，b，c问a*b是否等于c，等于输出YES，否则输出NOn的最大值是500，计算矩阵乘法的话需要O(n^3)的复杂度，很明显超时。随机出一列k，计算a*(b*k)和c*k，计算出一列的值，这样的如果a*b==c那么a*(b*k)和c*k也一定会相等的，因为是随机的数，所以可以多测试几次。#include #include #include
u013015642·2015-08-12 16:00

HDU 1082 Matrix Chain Multiplication

题目地址：点击打开链接思路：用map和stack即可解决AC代码：#include #include #include #include usingnamespacestd; structnode{introw,col;}; intmain() { intn,i,count; charc; mapmar; cin>>n; for(i=0;i>c; cin>>mar[c].row>>mar[c
qq_25605637·2015-08-11 10:00

UVA 442 Matrix Chain Multiplication

DescriptionSupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmultiplicationisassociative,theorderinwhichmultiplicationsareperformedisarbitrary.However,thenumberof
jtjy568805874·2015-08-09 15:00

【动态规划DP，二维动归】poj1651，Multiplication Puzzle

http://poj.org/problem?id=1651有N张写有数字的卡片排成一行，按一定次序从中拿走N-2张（第1张和最后一张不能拿），每次只拿一张，取走一张卡片的同时，会得到一个分数，分值的计算方法是：要拿的卡片，和它左右两边的卡片，这三张卡片上数字的乘积。按不同的顺序取走N-2张卡片，得到的总分可能不相同，求出给定一组卡片按上述规则拿取的最小得分。思路，对于i，j之间的任意一个k都可能
mmc2015·2015-08-06 19:00

poj 1651 Multiplication Puzzle【区间DP】

题目链接：http://poj.org/problem?id=1651题意：初使ans=0,每次消去一个值,位置在pos（pos!=1&&pos!=n）同时ans+=a[pos-1]*a[pos]*a[pos+1]，一直消元素直到最后剩余2个，求方案最小的ans是多少？代码：#include #include #include #include #include #include #include
u014427196·2015-08-03 01:00

A Multiplication Game HDOJ (巴什)

AMultiplicationGameTimeLimit:5000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):4369    AcceptedSubmission(s):2480ProblemDescriptionStanandOllieplaythegameofmultiplica
Grit_ICPC·2015-08-02 20:00

CodeForces - 448D—Multiplication Table--二分法（nlogn）

DescriptionBizontheChampionisn'tjustcharming,healsoisverysmart.Whilesomeofuswerelearningthemultiplicationtable,BizontheChampionhadfuninhisownmanner.BizontheChampionpaintedan n × m multiplicationtable,
sinat_30062549·2015-08-01 00:00

programming-challenges A multiplication game (110505) 题解

思路是从结果向开始的情况逆向推算，利用极大值和极小值。代码如下：#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using
houhouzhe·2015-07-23 06:00

Multiplication Table

packagecom.demo;importjava.awt.BorderLayout;importjava.awt.Graphics;importjavax.swing.JFrame;importjavax.swing.JLabel;importjavax.swing.JPanel;publicclassDemoextendsJFrame{publicDemo(){this.setLayout(
u013238950·2015-07-21 16:00

POJ 3673：Cow Multiplication

CowMultiplicationTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 12210 Accepted: 8509DescriptionBessieistiredofmultiplyingpairsofnumberstheusualway,sosheinventedherownstyleofmultiplication.Inhe
u010885899·2015-07-09 10:00

Leetcode - Multiply String

Given two numbers represented as strings, return multiplication of the numbers as a string.
likesky3·2015-06-15 09:00

Multiply Strings

Given two numbers represented as strings, return multiplication of the numbers as a string.
hcx2013·2015-06-11 19:00

leetcode：Multiply Strings

Given two numbers represented as strings, return multiplication of the numbers as a string.
·2015-06-09 13:00

Divide Two Integers

Divide two integers without using multiplication, division and mod operator.
hcx2013·2015-06-05 19:00

UVA442 Matrix Chain Multiplication

 1  #include <cstdio>  2  #include <iostream>  3  #include < string >  4  #include <stack>  5  &
·2015-06-04 23:00

HDU 1517 (POJ 2505) A Multiplication Game 简单博弈

题目大意：就是现在初始p=1,然后两个人轮流进行操作每次可以把p乘上2~9中的任意一个正整数,先把p变成>=n的人获胜大致思路：首先不难发现对于点k,k>=n的都是P点,那么所有能到达P点的都是N点,所以[n/9,n-1]是N点,当然这里n/9向上取整,所以写代码的时候注意一下,那么接下来一段只能到达N点的是P点,所以[n/9/2,n/9-1]是P点,一次类推即可,一直推到1的位置看是N点还是P点
u013738743·2015-05-09 11:00

CSU1600:Twenty-four point(DFS)

DescriptionGivenfournumbers,canyougettwenty-fourthroughtheaddition,subtraction,multiplication,anddivision
libin56842·2015-05-03 19:00

Codeforces Round #256 (Div. 2) D Multiplication Table（很巧妙二分）

CodeforcesRound#256(Div.2)DMultiplicationTableBizontheChampionisn’tjustcharming,healsoisverysmart.Whilesomeofuswerelearningthemultiplicationtable,BizontheChampionhadfuninhisownmanner.BizontheChampionp
yexiaohhjk·2015-04-29 19:00

CSU 1561-(More) Multiplication

题目链接：http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1561题面：1561:(More)MultiplicationTimeLimit: 1Sec  MemoryLimit: 128MBSubmit: 180  Solved: 95[Submit][Status][WebBoard]DescriptionEducatorsarealwaysc
David_Jett·2015-04-19 19:00

[LeetCode] Divide Two Integers 两数相除

  Divide two integers without using multiplication, division and mod operator.
·2015-04-16 14:00

UVA442 Matrix Chain Multiplication

UVA442MatrixChainMultiplication 1 #include  2 #include  3 #include  4 #include  5  6 using namespace std; 7  8 struct Matrix { 9     int r,c;10     Matrix(int a = 0, int b = 0) : r(a), c(b) {};11 }m[2
f(sixleaves) = sixleaves·2015-04-11 02:00

1561: (More) Multiplication

DescriptionEducatorsarealwayscomingupwithnewwaystoteachmathtostudents.In2011,aneducationalsoftwarecompany,AllComputerMath(ACM),developedanapplicationtodisplayproductsinatraditionalgradeschoolmathforma
Kirito_Acmer·2015-04-07 16:00

[LeetCode] Multiply Strings 字符串相乘

  Given two numbers represented as strings, return multiplication of the numbers as a string.
·2015-04-06 06:00

POJ - 3673 Cow Multiplication

POJ-3673CowMultiplicationDescriptionBessieistiredofmultiplyingpairsofnumberstheusualway,sosheinventedherownstyleofmultiplication.Inherstyle, A*B isequaltothesumofallpossiblepairwiseproductsbetweenthed
axiqia·2015-03-28 23:00

ZOJ 2316 Matrix Multiplication

DescriptionLetusconsiderundirectedgraphG= whichhasNverticesandMedges.IncidencematrixofthisgraphisN*MmatrixA={a ij},suchthata ij is1ifi-thvertexisoneoftheendsofj-thedgeand0intheothercase.Yourtaskistofi
jtjy568805874·2015-03-25 23:00

SGU - 196 - Matrix Multiplication （矩阵乘法）

196.MatrixMultiplicationtimelimitpertest:0.25sec.memorylimitpertest:65536KBinput:standardoutput:standardLetusconsideranundirectedgraphG=whichhasNverticesandMedges.IncidencematrixofthisgraphisanN×Mmatr
u014355480·2015-03-19 19:00

POJ1651:Multiplication Puzzle(区间DP 最优矩阵链乘)

题意：除了头尾不能动，每次取出一个数字，这个数字与左右相邻数字的乘积为其价值，最后将所有价值加起来，要求最小值和最优矩阵链乘模型一样，最后取出的数决定了序，如果没学过最优矩阵连乘找重复子问题还是比较难找的DP//180K0MS #include #include #include #include usingnamespacestd; intdp[110][110]; intn; intnum[1
kalilili·2015-03-09 20:00

LeetCode 29 - Divide Two Integers

Divide two integers without using multiplication, division and mod operator.
yuanhsh·2015-03-05 03:00

LeetCode 29 - Divide Two Integers

Divide two integers without using multiplication, division and mod operator.
yuanhsh·2015-03-05 03:00

矩阵链乘(Matrix Chain Multiplication)

MatrixChainMultiplicationTimeLimit:3000MS MemoryLimit:Unknown 64bitIOFormat:%lld&%lluSubmitStatusDescriptionSupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmult
qq_15096707·2015-02-21 00:00

Matrix Chain Multiplication-geeksforgeeks

(ABC)D=(AB)(CD)=A(BCD)calculatetheleastcalculation.第一种方法穷举发，willltakenptime. defmatrixp(p,i,j): ifi==j: return0 k=i minval=10000000 whilekresult: minval=result k+=1 returnminval defmain(): p=[40,20,
hyperbolechi·2015-02-18 22:00

UVA 348 Optimal Array Multiplication Sequence

Giventwoarrays A and B,wecandeterminethearray C = AB usingthestandarddefinitionofmatrixmultiplication:Thenumberofcolumnsinthe A arraymustbethesameasthenumberofrowsinthe B array.Notationally,let'ssayth
jtjy568805874·2015-02-17 21:00

POJ1651 Multiplication Puzzle ACM解题报告（区间dp）

这题就是个简单的区间DP，方法是很简单，重点是这种思想，不确定最优解是i-j中的哪一个，就要遍历一下然后取最优解状态转移方程d(i,j)=min(d(i,k)+dp(k,j)+a[i]*a[k]*a[j])注意a[k]是最后取走的一个数字。类似区间dp的还有矩阵链乘。我再去找个练练。#include #include #include #include #include #include #inc
Miracle_ma·2015-02-06 20:00

[LeetCode] Multiplication Withtout Division

Question:ThereisanarrayA[N]ofNnumbers.YouhavetocomposeanarrayOutput[N]suchthatOutput[i]willbeequaltomultiplicationofalltheelementsofA[N]exceptA[i].SolveitwithoutdivisionoperatorandinO(n).ForexampleOut
furuijie8679·2015-01-18 09:58

[LeetCode] Multiplication Withtout Division

Question:ThereisanarrayA[N]ofNnumbers.YouhavetocomposeanarrayOutput[N]suchthatOutput[i]willbeequaltomultiplicationofalltheelementsofA[N]exceptA[i].SolveitwithoutdivisionoperatorandinO(n).ForexampleOut
furuijie8679·2015-01-18 09:58

LeetCode - Multiply Strings

Given two numbers represented as strings, return multiplication of the numbers as a string.
yuanhsh·2015-01-10 06:00

UVA442 Matrix Chain Multiplication【stack】【栈】

 MatrixChainMultiplication SupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmultiplicationisassociative,theorderinwhichmultiplicationsareperformedisarbitrary.How
u011676797·2014-12-11 09:00

poj 1651 Multiplication Puzzle (区间dp)

题意：给出一串数字串，可以任意取数，所得到的价值为这个数乘以左右相邻的数，问如何去数让总价值最大。题解：区间dp不用说了，状态要好好体会，很好。dp[i][j]表示“开区间”里面的数都被取走了的最大价值。Ps：记着实开区间两种情况：1、后面一段和前面一段都被取走了2、对于i-j区间，断点k，i-k k-j内的都被取走了。/* 状态： dp[i][j]表示“开区间”内的数都被取走了所得的最大值，开区
My_ACM_Dream·2014-12-10 13:00

杭电OJ（HDOJ）4920题：Matrix multiplication（线性代数，矩阵相乘）

题意：给出两个N*N的矩阵A，B。求出这两个矩阵的乘积C。为了防止展生大数，结果矩阵C的每个元素都模除3，其中保证1 #definem3 intA[800][800],B[800][800],C[800][800]; intmain() { intn,i,j,k,temp; while(scanf("%d",&n)!=EOF) { for(i=0;i
u014174811·2014-12-02 22:00

poj Matrix Chain Multiplication

Language:DefaultMatrixChainMultiplicationTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 2053 Accepted: 1297DescriptionSupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematric
DoJintian·2014-11-15 19:00

UVA - 348 Optimal Array Multiplication Sequence （最优矩阵连乘）

题目大意：给你一些矩阵，你要写一个程式来决定该如何相乘的顺序，使得用到乘法的次数会最少。思路：最优矩阵链乘问题，典型的动态规划题目。该问题的子问题为“把Ai，Ai+1，……，Aj乘起来需要多少次乘法”，如果用dp(i,j)表示这个问题的子问题的值，则状态转移方程：dp(i,j)=min{dp(i,k)+dp(k+1,j)+row(i)*col(k)*col(j)}row代表当前矩阵的行，col代表
HelloWorld10086·2014-11-13 15:00

POJ1651——Multiplication Puzzle

MultiplicationPuzzleTimeLimit:1000MS MemoryLimit:65536KTotalSubmissions:6511 Accepted:3964DescriptionThemultiplicationpuzzleisplayedwitharowofcards,eachcontainingasinglepositiveinteger.Duringthemovepl
Guard_Mine·2014-11-10 20:00

Multiplication Table

BizontheChampionisn'tjustcharming,healsoisverysmart.Whilesomeofuswerelearningthemultiplicationtable,BizontheChampionhadfuninhisownmanner.BizontheChampionpaintedan n × m multiplicationtable,wheretheele
u011345136·2014-10-23 08:00

emmet基本语法汇总

Child: >     输入：nav>ul>li 输出：                     Multiplication: *      输入：ul>li*5 输出：          
莎莉翁·2014-10-14 15:00

Acdream 1213——Matrix Multiplication

MatrixMultiplicationTimeLimit: 2000/1000MS(Java/Others)MemoryLimit: 128000/64000KB(Java/Others)SubmitStatisticNextProblemProblemDescription    LetusconsiderundirectedgraphG={V;E}whichhasNverticesandMe
Guard_Mine·2014-10-01 21:00

HDU 1517 A Multiplication Game(博弈论)

题目地址：HDU1517NP状态转换。可以把题目的向上乘变成向下除。这样1是终结状态，设1的时候为必败点。根据所有能一步到达必败点的点是必胜点，所以[x,x*9]必胜点；根据只能到达必胜点的点是必败点，所以[x*9+1,x*9*2]是必败点.然后求解。代码如下：#include #include #include #include #include #include #include #inclu
u013013910·2014-09-16 14:00

HDOJ 4915 Multiplication table

可以特判出0和1,再统计每行出现了多少种十位上的数就可以了....没有考虑2的情况似乎也过了......MultiplicationtableTimeLimit:4000/2000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):800    AcceptedSubmission(s):360Pro
u012797220·2014-09-11 01:00

九度OJ 1534 数组中第K小的数字 && codeforces 448D Multiplication Table

题目链接~~>解题思路：         我们可以看出，二个数组的和 min = a[0]+b[0] , max = a[ n-1]+b[m-1],这样我们就可以二分枚举这个区间的所有数，枚举每个数的时候判断它是第几大，你可能会问：怎样判断第几大？？？假如你要查找 x是第几大，那么可以对比a数组中的每个数，让其在b数组中查找不大于 x-a[i] (这里x>=a[i])的数，有几个就表示a[i]分别
u011074149·2014-08-21 17:00

HDU4951:Multiplication table

ProblemDescriptionTeacherMaihasamultiplicationtableinbasep.Forexample,thefollowingisamultiplicationtableinbase4:*0123000000000100010203200021012300031221Butanaughtykidmapsnumbers0..p-1intoanotherpermu
libin56842·2014-08-15 18:00

Hdu 4951 Multiplication table

题目链接MultiplicationtableTimeLimit:4000/2000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):491    AcceptedSubmission(s):230ProblemDescriptionTeacherMaihasamultiplicationtable
madaidao·2014-08-15 14:00
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