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Multiplication
UVa 348 - Optimal Array
Multiplication
Sequence
题目链接:UVa348-OptimalArrayMultiplicationSequence最优矩阵链乘。DP中枚举乘号位置。状态转移方程:dp[x][y]=min(dp[x][y], DP(x,i)+DP(i+1,y)+node[x].x*node[i].y*node[y].y)难点在于打印,我看了人家的代码才写出来,很精妙。#include #include usingnamespacest
fobdddf
·
2014-03-14 18:00
Multiplication
Table
二分判定答案D.MultiplicationTabletimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputBizontheChampionisn'tjustcharming,healsoisverysmart.Whilesomeofuswerelearningthemu
u012797220
·
2014-02-12 02:00
poj 1651
Multiplication
Puzzle(区间DP,直接用矩阵相乘的方式也对)
1、http://poj.org/problem?id=16512、题目大意:给出n个数,现在要将这些数一个一个的取出来,但是不能取出两个端点的数字,取出第i个数字(c[i])的代价是c[i-1]*c[i]*c[i+1]用矩阵相乘的思想dp[i][j]表示i到j区间取出来的代价dp[i][j]=min(dp[i][j],dp[i][k]+dp[k][j]+c[i]*c[k]*c[j])3、AC代码
sdjzping
·
2014-02-10 21:00
POJ 2505 A
multiplication
game
博弈第一题。对我来说不是很简单。。总是把自己打败==对于每一个人只考虑他能算到的最小的数,因为只要得到这个最小数,当n=18的数,于是n=18。而2-9是先手必胜区间,那么此时后手必胜区间是10-18,因为如果n=18的数,所以此时先手得到的后手乘完的数最小是18,那么先手乘上9可以得到最小的数=18*9=162(这意味着此时先手乘出来的所有数都>=162),所以先手的必胜区间是19-162。那么
zzxyyx_1
·
2014-02-05 00:00
442 - Matrix Chain
Multiplication
题目:442-MatrixChainMultiplication题目大意:求矩阵相乘需要的加法步数。解题思路:将给出的式子,一个一个字符的放到栈中,当遇到右括号,就从栈中退出两个矩阵,和一个左括号。判断这两个举阵能不能相乘,(前一个的列等于后一个的行)再将这个矩阵入栈,之后遇到右括号再出栈,一直到式子末尾就结束。最后要将栈清空,为了下一次计算做准备。还要注意特殊情况:就是没有括号的式子,单独考虑。
u012997373
·
2014-01-24 20:00
Geeks面试题:Matrix Chain
Multiplication
MatrixChainMultiplicationGivenasequenceofmatrices,findthemostefficientwaytomultiplythesematricestogether. Theproblemisnotactuallytoperformthemultiplications,butmerelytodecideinwhichordertoperformthemu
kenden23
·
2014-01-12 10:00
面试题
chain
Matrix
geeks
Multipl
小白dp 348 Optimal Array
Multiplication
Sequence
OptimalArrayMultiplicationSequenceGiventwoarrays A and B,wecandeterminethearray C = A B usingthestandarddefinitionofmatrixmultiplication:Thenumberofcolumnsinthe A arraymustbethesameasthenumberofrowsi
u010228612
·
2013-12-30 09:00
DP8 矩阵链相乘 Matrix Chain
Multiplication
@geeksforgeeks
思路是在矩阵链的每一个地方分别分开,然后找最小Givenasequenceofmatrices,findthemostefficientwaytomultiplythesematricestogether. Theproblemisnotactuallytoperformthemultiplications,butmerelytodecideinwhichordertoperformthemult
hellobinfeng
·
2013-12-25 05:00
UVA - 10825 Anagram and
Multiplication
题意:有m位n进制整数非常神奇:乘以2,3...,m之后,所有得到的数恰好是原数各数字的一个排列,输入m,n,求出这样的整数(最多只有一个)思路:枚举0~n-1的数,因为乘以m次后得到不同的排列,所以我们可以根据这个求出m个数来,然后再用排列树搜索答案,最后check一下#include #include #include #include usingnamespacestd; intn,m,a
u011345136
·
2013-12-18 22:00
hdu-1082Matrix Chain
Multiplication
栈的简单使用MatrixChainMultiplicationTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):930 AcceptedSubmission(s):634ProblemDescriptionMatrixmultiplicationprobl
yinzm520
·
2013-12-03 23:00
UVa 348 Optimal Array
Multiplication
Sequence (区间DP&矩阵链乘,MCM)
348-OptimalArrayMultiplicationSequenceTimelimit:3.000seconds http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=284记忆化搜索:dp[a][b]=max(dp[a][b],
synapse7
·
2013-11-25 14:00
C++
dp
ACM
uva
SPOJ PGCD 4491. Primes in GCD Table && BZOJ 2820 YY的GCD (莫比乌斯反演)
But instead of a boring
multiplication
tabl
·
2013-10-19 22:00
table
hdu1517 A
Multiplication
Game
AMultiplicationGameTimeLimit:5000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3013AcceptedSubmission(s):1732ProblemDescriptionStanandOllieplaythegameofmultiplicationbymu
u010422038
·
2013-09-24 23:00
Strassen's Subcubic Matrix
Multiplication
Algorithm
Considermultiplyingtwo2x2matrices,asfollows:AB*EF=AE+BGAF+BH CDGHCE+DGCF+DH Theobviouswaytocomputetherightsideisjusttodothe8multipliesand4additions.Butimaginemultipliesarealotmoreexpensivethanaddition
Qxietingwen
·
2013-09-24 09:00
C++ AMP with Matrix
Multiplication
AspartofourAPItourof C++AMP,welookedrecentlyat parallel_for_each.Iendedthatpostbysayingwewouldrevisitparallel_for_eachafterintroducing arrayandarray_view.Nowisthetime,sothisispart2ofparallel_for_each,
Augusdi
·
2013-09-16 11:00
uva 348 Optimal Array
Multiplication
Sequence(区间dp)
题目连接:348-OptimalArrayMultiplicationSequence题目大意:给出n个矩阵,每个矩阵有它的行和列,现在要计算这n个连续的矩阵的乘积,要求找出计算量最小的方案,每两个矩阵相乘的计算量为(a.l*a.r*b.r),然后生成一个a.l和b.r的矩阵。解题思路:典型的区间dp,只不过在每次找最优解之后要记录当前区间的最优分解点rec[a][b]。#include #inc
u011328934
·
2013-09-13 19:00
UVA 348 Optimal Array
Multiplication
Sequence(区间dp)
OptimalArrayMultiplicationSequence Giventwoarrays A and B,wecandeterminethearray C = A B usingthestandarddefinitionofmatrixmultiplication:Thenumberofcolumnsinthe A arraymustbethesameasthenumberofrowsi
u011217342
·
2013-09-07 21:00
UVa:348 Optimal Array
Multiplication
Sequence
早就做出来了一直存在没发。经典的区间DP。时间复杂度O(n^3)三重循环分别枚举长度起点切点。打印路径的思路出自算法导论。 #include #include #include #include usingnamespacestd; ints[20][20]={0}; voidPrint_optimal_parens(inti,intj) { if(i==j) printf("
kkkwjx
·
2013-09-02 10:00
动态规划
区间DP
BNU 26584 Mosquito
Multiplication
【数蚊子】
链接:http://www.bnuoj.com/bnuoj/problem_show.php?pid=26584http://www.bnuoj.com/bnuoj/contest_show.php?cid=2318#problem/25692F.MosquitoMultiplicationTimeLimit: 1000msCaseTimeLimit: 1000msMemoryLimit: 655
Cfreezhan
·
2013-08-26 22:00
uva442 Matrix Chain
Multiplication
UVA 442题意:输入几个矩阵然后输入字符串,根据输出的字符串,判断矩阵相乘所需要计算的乘法次数思路:用栈的思想,用一个二维数组模拟栈,遇到左括号往上多一层,遇到右括号运算结果,保存到下一层中,计算到字符串末尾。每次计算结果,把乘法次数加上去,最后得到的就是总次数代码:#include usingnamespacestd; #include #include structSB { intx; i
u011217342
·
2013-08-25 20:00
ACM
uva
[Leetcode] Multiply Strings
Multiply Strings Mar 12 '12 4253 / 16074 Given two numbers represented as strings, return
multiplication
cozilla
·
2013-08-20 18:00
LeetCode
POJ1651
Multiplication
Puzzle(区间DP)
原文链接:http://www.cnblogs.com/gj-Acit/p/3269201.html比较好做的区间DP状态转移方程:DP[i][j]表示区间[i,j]最小的乘积和。DP[i][j]=MIN{DP[i][k-1]+DP[k+1][j]+a[k]*a[i-1]*a[j+1]|i2#include3#include4#include5#include6#include7#include8
weixin_33802505
·
2013-08-19 23:00
Matrix Chain
Multiplication
模拟栈
MatrixChainMultiplicationTimeLimit:1000MS MemoryLimit:32768KTotalSubmit:36Accepted:26DescriptionMatrixmultiplicationproblemisatypicalexampleofdynamicalprogramming. Supposeyouhavetoevaluateanexpression
haha593572013
·
2013-08-19 18:00
uva 442 - Matrix Chain
Multiplication
(记忆化搜索 | 重做一年前的题)
本文出自 http://blog.csdn.net/shuangde800 题目链接: 点击打开链接 题目大意 给出一系列的矩阵,给他们取名A ,B…… 并且给出了它们的行数和列数。给完后,给出一系列的表达式,然后要求求出按这些表达式进行计算,会有多少次乘法步骤。 思路 这题去年的暑假是有做过的,在《入门经典》的数据结构专题 ...打开 现在
king_tt
·
2013-08-12 13:00
Matrix
uva 442 - Matrix Chain
Multiplication
(记忆化搜索 | 重做一年前的题)
本文出自 http://blog.csdn.net/shuangde800题目链接: 点击打开链接题目大意给出一系列的矩阵,给他们取名A,B…… 并且给出了它们的行数和列数。给完后,给出一系列的表达式,然后要求求出按这些表达式进行计算,会有多少次乘法步骤。思路这题去年的暑假是有做过的,在《入门经典》的数据结构专题... 打开现在在看一年前的代码,无论是方法还是代码都觉得不是一般地搓--||在过几
shuangde800
·
2013-08-12 13:00
uva
区间DP
leetcode -- Multiply Strings
Given two numbers represented as strings, return
multiplication
of the numbers as a string.
·
2013-08-05 23:00
LeetCode
Prime Cryptarithm(枚举)
Prime Cryptarithm The following cryptarithm is a
multiplication
problem that can be solved by substituting
Simone_chou
·
2013-08-05 13:00
Prim
442 - Matrix Chain
Multiplication
MatrixChainMultiplication SupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmultiplicationisassociative,theorderinwhichmultiplicationsareperformedisarbitrary.How
SIOFive
·
2013-08-01 13:00
算法
String
STL
uva
POJ 1651 / ZOJ 1602 / Northeastern Europe 2001
Multiplication
Puzzle(dp)
MultiplicationPuzzlehttp://poj.org/problem?id=1651http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1602TimeLimit: 1000MSMemoryLimit: 65536KDescriptionThemultiplicationpuzzleisplayedwitharo
synapse7
·
2013-07-31 14:00
dp
动态规划
ACM
442 - Matrix Chain
Multiplication
注:此题比较无脑,且没有意思,建议不要做.题意:矩阵乘法,要求计算出几个矩阵相乘时需要进行的相乘次数.输入分为firstpart与secondpart,firstpart给出各个矩阵的行数与列数,secondpart格式如下:SecondPart=Line{Line}Line =ExpressionExpression =Matrix|"("ExpressionExpression")"M
sailtseng
·
2013-07-31 00:00
chain
Matrix
uva
442
Multiplication
POJ 3318 - Matrix
Multiplication
第一次用随机化解决问题...
随机化还是很厉害的...印象最深的是以前手写快排~~一般加个随机化会使耗时不受输入数据的..时间更加稳定 这个题是人品题了...开始交了好多遍都过不了..多交几次终于过了...Program:#include #include #include #include #include #include #include #include #definelllonglong #defineoo
kk303
·
2013-07-24 12:00
×_7_12_2013 H: Matrix
Multiplication
ProblemH:MatrixMultiplicationTimeLimit: 1Sec MemoryLimit: 128MBSubmit: 87 Solved: 34[Submit][Status][WebBoard]DescriptionJohnnyandJohnaregoodfriends.Johnnyisgoingtotaketheentranceexamsforpostgraduat
電泡泡
·
2013-07-19 18:00
Multiplication
Puzzle
题目大致意思是:一个整数序列包含N个1~100的整数(3 #include #definemin(a,b)((a)<(b)?(a):(b)) intdp[110][110]; intmain(void) { inti,j,k,a[110]; intn; scanf("%d",&n); for(i=1;i<=n;i++) scanf("%d",&a[i]); for(k=2;k
·
2013-07-15 18:00
cat
Hdu 1517 A
Multiplication
Game
AMultiplicationGameTimeLimit:5000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):2717 AcceptedSubmission(s):1553ProblemDescriptionStanandOllieplaythegameofmultiplica
Magic____
·
2013-07-14 13:00
uva 442 Matrix Chain
Multiplication
(模拟)
MatrixChainMultiplication SupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmultiplicationisassociative,theorderinwhichmultiplicationsareperformedisarbitrary.How
u011328934
·
2013-07-07 09:00
UVA442 Matrix Chain
Multiplication
矩阵运算量计算(栈的简单应用)
栈的练习,如此水题竟然做了两个小时。。。 题意:给出矩阵大小和矩阵的运算顺序,判断能否相乘并求运算量。 我的算法很简单:比如(((((DE)F)G)H)I),遇到 (就cnt累计加一,字母入栈,遇到)减一,并出栈两个矩阵计算运算量,将计算后的矩阵压入栈。当cnt等于0时就输出运算量。 难点是当不能运算后的处理。 卡那么就其实主要是细节问题,最大的坑是里面退栈时倒着退出,没注意到结果每次计算
runfeel
·
2013-07-05 19:00
Matrix
uva-442 Matrix Chain
Multiplication
SupposeyouhavetoevaluateanexpressionlikeA*B*C*D*EwhereA,B,C,DandEarematrices.Sincematrixmultiplicationisassociative,theorderinwhichmultiplicationsareperformedisarbitrary.However,thenumberofelementarym
ultimater
·
2013-07-04 15:00
HDU 1517 A
Multiplication
Game (博弈)
A
Multiplication
Game Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 65536
·
2013-06-20 13:00
game
uva348 - Optimal Array
Multiplication
Sequence(简单动规)
矩阵相乘求最小运算次数。经典的动规题目。代码如下;#include #defineN20 #defineINF0x7fffffff intn,a[N][2],d[N][N],pa[N][N]; voiddp() { for(inti=0;itt){min=tt;minx=k;} } d[s][s+len]=min;pa[s][s+len]=minx; } } } voidprint_ans(int
shankeliupo
·
2013-06-05 18:00
hdu 1082 Matrix Chain
Multiplication
MatrixChainMultiplicationTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):797 AcceptedSubmission(s):553ProblemDescriptionMatrixmultiplicationproblemisat
u010228612
·
2013-06-01 20:00
Useful resources for matrix
multiplication
on mapreduce
Algorithm:http://www.norstad.org/matrix-multiply/index.htmlAclassicsummarizationofamapreducealgorithmformatrixmultiplication,includingfourblockingstrategies.anatomyofhigh-performancematrixmultiplicati
Daisy8867
·
2013-05-24 11:00
mapreduce
cost
matrix
multiplicatio
百宝箱
Useful resources for matrix
multiplication
on mapreduce
Algorithm:http://www.norstad.org/matrix-multiply/index.htmlAclassicsummarizationofamapreducealgorithmformatrixmultiplication,includingfourblockingstrategies.anatomyofhigh-performancematrixmultiplicati
Daisy8867
·
2013-05-24 11:00
mapreduce
Matrix
cost
blocking
Multiplication
strategies
poj2505 - A
multiplication
game
题目大意:两个人轮流玩游戏,Stan先手,数字p从1开始,Stan乘以一个2-9的数,然后Ollie再乘以一个2-9的数,直到谁先将p乘到p>=n时那个人就赢了,而且轮到某人时,某人必须乘以2-9的一个数。解题思路:博弈,找规律,首先我们容易得到在[2,9]这个区间,是Stan必胜[10,18]这个区间,是Ollie必胜那么下个区间左边肯定是[18+1,?],是Stan必胜区间闭应该填一个什么数呢
wangjian8006
·
2013-05-22 20:00
Multiplication
Puzzle
题目链接http://poj.org/problem?id=1651Poj1651区间动态规划#include usingnamespacestd; constintMaxNum=0x3f3f3f3f; intp[101]={0}; intm[101][101]={0}; intDP(intN,intp[]) { //初始化 memset(m,0,sizeof(m)); for(intle
insistGoGo
·
2013-05-14 21:00
poj2246 - Matrix Chain
Multiplication
想看更多的解题报告:http://blog.csdn.net/wangjian8006/article/details/7870410 转载请注明出处:http://blog.csdn.net/wangjian8006题目大意:有n个矩阵,给出这些矩阵的行和列,并标记矩
wangjian8006
·
2013-05-09 13:00
Matrix
multiplication
in OpenCV
Youhavetobecarefulwhenmultiplyingmatrices,astherearetwopossiblemeaningsofmultiply.Matrixmultiplication iswheretwomatricesaremultiplieddirectly.ThisoperationmultipliesmatrixAofsize[axb]withmatrixBofsiz
tanmengwen
·
2013-05-07 14:00
ZOJ 1602
Multiplication
Puzzle
区间dpF(i,j)=min(F(i,k)+a[i]*a[k]*a[j]+F(k,j))#include #include usingnamespacestd; #defineN103 typedeflonglongLL; constlonglonginf=1r)returnf[l][r]=0; LLmin=inf,tmp; for(intk=l+1;k
yang_7_46
·
2013-05-05 14:00
ZOJ_1094/hdoj_1082_Matrix Chain
Multiplication
_...
MatrixChainMultiplicationTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):893 AcceptedSubmission(s):603ProblemDescriptionMatrixmultiplicationproblemisat
電泡泡
·
2013-04-26 20:00
【leetcode】Divide Two Integers
Question : Divide two integers without using
multiplication
, division and mod operator.
king_tt
·
2013-04-20 10:00
LeetCode
poj 1060 Modular
multiplication
of polynomials 二进制多项式取余式运算。
题目:来源于http://poj.org/problem?id=1060描述: 定义二进制多项式加法和减法 : (x^6+x^4+x^2+x+1)+(x^7+x+1)=x^7+x^6+x^4+x^2 (x^6+x^4+x^2+x+1)-(x^7+x+1)=x^7+x^6+
u010064842
·
2013-04-17 00:00
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