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Subarrays
number-of-
subarrays
-with-bounded-maximum 最大值在界内的子数组个数
给定一个包含正整数的数组A,以及两个正整数L和R(Lr跳出循环,如果a[j]>==lresult++,整体思想有点dp的感觉思路2O(N)、遍历数组,记录下符合位置的索引index,和不符合位置的索引temp,result+=index-temppublicclassSolution{/***@parama:anarray*@paraml:aninteger*@paramr:aninteger*@
龙潭吴彦祖丶
·
2019-07-19 14:22
LeetCode 1031: Maximum sum of two non-overlapping
subarrays
原题目GivenanarrayAofnon-negativeintegers,returnthemaximumsumofelementsintwonon-overlapping(contiguous)
subarrays
Yuqi喵
·
2019-06-20 18:19
Bitwise ORs of
Subarrays
子数组按位或操作
WehaveanarrayAofnon-negativeintegers.Forevery(contiguous)subarrayB=[A[i],A[i+1],...,A[j]](withi&A){unordered_setres,cur;for(inti:A){unordered_settmp={i};for(intj:cur)tmp.insert(i|j);cur=tmp;for(intj:c
Grandyang
·
2019-06-05 23:00
gym-101532A -
Subarrays
Beauty(按位算贡献+尺取)
题目给一个序列a[],每个子区间都要把所有元素相与(and)之后得到一个值v,求所有v的和思路来源https://blog.csdn.net/lifelikes/article/details/78174268题解就是算每一位的贡献,先按二进制压位这样对于某一位来说,就变成了01序列1110111对于左边的三个1,其贡献为[1,1],[1,2][1,3][2,2][2,3][3,3],共6个区间即
Code92007
·
2019-02-08 15:59
位运算/异或线性基
AtCoder-Dwango Programming Contest V-B - Sum AND
Subarrays
地址:https://dwacon5th-prelims.contest.atcoder.jp/tasks/dwacon5th_prelims_b思路:贪心,首先将n*(n-1)/2个数求出来,在从高位开始遍历,若当前位为1的个数>=k,则将当前位为0的全部删除掉,同时ans加上当前位的值。Code:#include#includeusingnamespacestd;typedeflonglong
z岁月无声
·
2018-12-01 01:23
贪心
AtCoder
Maximum Sum of 3 Non-Overlapping
Subarrays
ProblemInagivenarraynumsofpositiveintegers,findthreenon-overlappingsubarrayswithmaximumsum.Eachsubarraywillbeofsizek,andwewanttomaximizethesumofall3*kentries.Returntheresultasalistofindicesrepresentin
linspiration
·
2018-10-24 00:00
java
Gym - 101532A
Subarrays
Beauty(位操作找规律)
Youaregivenanarrayaconsistingofnintegers.Asubarray(l, r)fromarrayaisdefinedasnon-emptysequenceofconsecutiveelementsal, al + 1, …, ar.Thebeautyofasubarray(l, r)iscalculatedasthebitwiseANDforallelements
Cymbals
·
2018-03-19 21:18
ACM
位操作
Maximum Sum of 3 Non-Overlapping
Subarrays
Inagivenarraynumsofpositiveintegers,findthreenon-overlappingsubarrayswithmaximumsum.Eachsubarraywillbeofsizek,andwewanttomaximizethesumofall3*kentries.Returntheresultasalistofindicesrepresentingthesta
Jeanz
·
2018-03-13 03:28
Codeforces 665E Beautiful
Subarrays
(01字典树)
题目传送门:http://codeforces.com/contest/665/problem/E给你长度n的数组,然后问你有多少个区间,区间异或和大于等于k区间异或和,一看就是01字典树,然后就是在01字典树上如何判断大于等于k咯,可以把k也每一位是0是1讨论,并且每个节点上记录放进去了多少个前缀,查询的时候就是当前查询的位数上是0是1和k这一位上是0是1分类讨论即可代码:#include #i
Miracle_ma
·
2016-05-24 13:00
Codeforces 655E Beautiful
Subarrays
【01trie树】
题目链接:http://codeforces.com/contest/665/problem/E题意:求异或值大于给定K的区间个数。分析:首先我们可以得到区间前缀的异或值。这样我们将这个前缀M和K一起走trie树,如果该位K的值为0,那么无论怎么走最后得到的答案都不会比K小,所以直接加上另一边的子树大小,然后继续沿着当前边走。如果该位K的值为1,那么想要大于等于K必须沿着另一边贪心的走。代码:#i
Yukizzz
·
2016-05-09 10:00
Beautiful
Subarrays
【字典树】
/************************************************Author:MaltubEmail:
[email protected]
:htttp://www.xiang578.top*************************************************/ #include #include #include #inc
xinag578
·
2016-04-30 09:00
Beautiful
Subarrays
维护一个异或的前缀数组sum(),并把数组中的数挂在字典树上,寻找在sum(0)..sum(i-1)中和sum(i)异或值大于等于K的数的数目.累加#include #definemaxn205 #defineINF1e9 usingnamespacestd; typedeflonglongll; typedefstructNode{ intnum; Node*p[2]; }*T; Troot;
qq_26122039
·
2016-04-24 19:00
Beautiful
Subarrays
题意:问有多少个连续区间异或和大于等于k思路:sum[l,r]=sum[1,l-1]^sum[1,r]所以记录异或前缀和,并用字典树维护从高位开始插入,num维护有多少数的前缀等于插入路径的,只要高位异或大于等于k,则之后肯定满足;否则,必须将cur的那一位置为1,然后继续。(因为退役已久,写了一发样例都没过,于是改着改着就改成codeforces的tutorial的样子,最后发现是我从低位开始插
u013007900
·
2016-04-23 15:00
CodeForces 665E Beautiful
Subarrays
题意:问你有多少个区间,异或起来大于等于k思路:显然求个前缀和之后,就等于有多少对数异或起来大于等于k了,每次暴力爬字典树就好了,当k这一位等于0的时候,我们可以直接加上另外一边1的子树大小,因为爬那边之后,我怎么爬都是大于等于k的#include usingnamespacestd; constintmaxn=2e7+6; structTri { intch[maxn][2]; intsz[ma
qq_21057881
·
2016-04-23 00:00
Beautiful
Subarrays
字典树
E.BeautifulSubarrays题目连接:http://www.codeforces.com/contest/665/problem/EDescriptionOneday,ZStheCoderwrotedownanarrayofintegersa withelementsa1, a2, ..., an.Asubarrayofthearrayaisasequenceal, al +
qscqesze
·
2016-04-21 22:00
partition list - Groovy built-in to split an array into equal sized
subarrays
? - Stack Overflow
list - Groovy built-in to split an array into equal sized
subarrays
?
·
2015-11-13 21:59
partition
Data Structure Array: Maximum of all
subarrays
of size k
http://www.geeksforgeeks.org/maximum-of-all-
subarrays
-of-size-k/ 1 #include <iostream> 2 #
·
2015-11-13 10:50
Arrays
Lintcode: Maximum Subarray III
Given an array of integers and a number k, find k non-overlapping
subarrays
which have the largest sum
·
2015-11-11 01:10
array
Lintcode: Maximum Subarray II
Given an array of integers, find two non-overlapping
subarrays
which have the largest sum.
·
2015-11-11 01:08
array
Lintcode: Maximum Subarray Difference
Find two non-overlapping
subarrays
A and B, which |SUM(A) - SUM(B)| is the largest.
·
2015-11-11 01:07
array
[LintCode] Maximum Subarray Difference
Find two non-overlapping
subarrays
A and B, which |SUM(A) - SUM(B)| is the largest
·
2015-10-27 15:32
array
[LintCode] Maximum Subarray III
Maximum Subarray III Given an array of integers and a number k, find knon-overlapping
subarrays
·
2015-10-27 15:30
array
所有子序列的最大值 Maximum of all
subarrays
of size k
给定一个数组和一个整数k,找到每一个长度为k的子序列的最大值。例如:Input:arr[]={1,2,3,1,4,5,2,3,6}k=3Output:3345556Input:arr[]={8,5,10,7,9,4,15,12,90,13}k=4Output:10101015159090#include #include usingnamespacestd; //ADequeue(Double
jiyanfeng1
·
2014-11-24 05:00
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