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Theorem
HDU1905 Pseudoprime numbers
K (Java/Others)Total Submission(s): 633Accepted Submission(s): 258 Problem Description Fermat's
theorem
isiqi
·
2011-04-05 20:00
J#
Brewer's CAP
Theorem
ByJulianBrowneonJanuary11,2009.FiledUnderarchitecture,business,strategyOnFriday4thJune1976,inasmallupstairsroomawayfromthemainconcertauditorium,theSexPistolskickedofftheirfirstgigatManchester'sLesserF
zgl_dm
·
2011-03-31 15:00
application
database
NetWork
transactions
translation
Scalability
HBase 101: Row key design for paging (LIMIT, OFFSET) queries
hbase-row-key-design-for-paging-limit-offset-queries/ 另外一篇CAPTheoremhttp://devblog.streamy.com/2009/08/24/cap-
theorem
macyang
·
2011-02-17 19:00
exception
hbase
table
query
action
byte
角谷静夫不动点（Kakutani fixed point
theorem
）----资料整理
一、不动点算法又称固定点算法。所谓不动点，是指将一个给定的区域A,经某种变换ƒ(x),映射到A时,使得x=ƒ(x)成立的那种点。最早出现的不动点理论是布劳威尔定理(1912)：设A为Rn中的一紧致凸集,ƒ为将A映射到A的一连续函数，则在A中至少存在一点x，使得x=ƒ（x）。其后，角谷静夫于1941年将此定理推广到点到集映射上去。设对每一x∈A，ƒ(x)为A的一子集。若ƒ(x)具有性质：对A上的任一
foxeatapple
·
2011-01-19 16:00
博弈论
角谷静夫不动点（Kakutani fixed point
theorem
）----资料整理
一、不动点算法又称固定点算法。所谓不动点，是指将一个给定的区域A,经某种变换ƒ(x),映射到A时,使得x=ƒ(x)成立的那种点。最早出现的不动点理论是布劳威尔定理(1912)：设A为Rn中的一紧致凸集,ƒ为将A映射到A的一连续函数，则在A中至少存在一点x，使得x=ƒ（x）。其后，角谷静夫于1941年将此定理推广到点到集映射上去。设对每一x∈A ，ƒ(x)为A的一子集。若ƒ(x)具有性质：对A上的任
foxeatapple
·
2011-01-19 16:00
算法
工作
优化
function
扩展
each
Differences between
Theorem
, Lemma and Corollary, etc.
Definition — a precise and unambiguous description of the meaning of a mathematical term. It characterizes the meaning of a word by giving all the properties and only those properties that must be tr
imcdragon
·
2010-12-29 19:00
POJ 3006 Dirichlet's
Theorem
on Arithmetic Progressions 素数的判断 筛选法
http://poj.org/problem?id=3006 Dirichlet'sTheoremonArithmeticProgressionsTimeLimit: 1000MS MemoryLimit: 65536KDescriptionIf a and d arerelativelyprimepositiveintegers,thearithmeticsequencebeginningwit
yming0221
·
2010-12-28 07:00
POJ 3006 Dirichlet's
Theorem
on Arithmetic Progressions 素数的判断 筛选法
id=3006 Dirichlet's
Theorem
on Arithmetic Progressions Time Limit:1000MS Memory Limit:65536K
soboer
·
2010-12-28 07:00
progress
POJ 3006 Dirichlet's
Theorem
on Arithmetic Progressions 素数的判断 筛选法
id=3006 Dirichlet's
Theorem
on Arithmetic Progressions Time Limit:1000MS Memory Limit:65536K
thecloud
·
2010-12-28 07:00
progress
My first blog entry also is my first english math proof ( GCD(a,b)=min{a*x+b*y, a*x+b*y>0} )
theorem
31.2 Ifaandbareanyintegers,notbothzero,thenGCD(a,b)isthesmallestpositiveelementoftheset{a*x+b*
ysjjovo
·
2010-12-21 20:00
杭州现场J题_Infinite monkey
theorem
构造一个DFA， 对于样例：2100a0.312345b0.687655abab即： (b)----------- | / | / | /// / (a) (b) (a) (b) NULL----->a---->ab---->aba---->abab(ACC,成功状态)
SwordHoly
·
2010-10-26 18:00
struct
HDU 1788 Chinese remainder
theorem
again
HDU1788Chineseremaindertheoremagain/**//**********************************N % MI = MI - a因为 a #include using namespace std;__int64 gcd( __int64 a, __int64 b ){ if( b == 0 ) return a; return gcd(
Vontroy
·
2010-10-02 14:00
中国剩余定理（chinese remainder
theorem
）【模板】
#includeusingnamespacestd;intExtended_Euclid(inta,intb,int&x,int&y)//扩展欧几里得算法{intd;if(b==0){x=1;y=0;returna;}d=Extended_Euclid(b,a%b,y,x);y-=a/b*x;returnd;}intChinese_Remainder(inta[],intw[],intlen)//
xiaotaoqibao
·
2010-08-01 17:00
算法
ini
扩展
include
poj 3006 Dirichlet's
Theorem
on Arithmetic Progressions
http://162.105.81.212/JudgeOnline/problem?id=3006 又是一个跟素数有关的题目-_-,这两天贴那个素数打表模板都不知道贴几次了,囧 题目中最后一句话很有用:FYI,itisknownthattheresultisalwayslessthan106(onemillion)underthisinputcondition.所以先打表(1-10^6),然后再逐
SMCwwh
·
2010-07-15 13:00
POJ 3006 Dirichlet's
Theorem
on Arithmetic Progressions
POJ3006Dirichlet'sTheoremonArithmeticProgressions这两天都是水题，没有什么想法而言，就是为了熟悉一下感觉。我又给互联网上增加了不少垃圾日志。昨晚出了点突发事件，原定的写程序事件被用来处理事情了。不过后来我倒是有点想明白了，题目只是很少一点时间在看题目，很忙的时候可以先花几分钟把题目弄明白了，然后在去忙别的事情，这种件的空隙还能想一想思路。不知POJ有
GLORY | 学习·记录
·
2010-07-12 13:00
广义中国剩余定理
GeneralizedChineseRemainderTheorem来源：http://www.cut-the-knot.org/blue/chinese.shtml(IEonly)
Theorem
1[quote
digiterrush
·
2010-07-10 19:57
ICPC
广义中国剩余定理
Generalized Chinese Remainder
Theorem
来源：http://www.cut-the-knot.org/blue/chinese.shtml (IE only)
digiter
·
2010-07-10 19:00
算法
IE
J#
POJ 3006 Dirichlet's
Theorem
on Arithmetic Progressions(素数表)
//简单题。筛选法打素数表。#includeusingnamespacestd;constintMAXP=1100000;boolisPrime[MAXP];intprime[MAXP];voidprimeList(){memset(isPrime,true,sizeof(isPrime));isPrime[1]=false;for(inti=2;i0;i+=d){if(isPrime[i])--
ChinaCzy
·
2010-06-13 21:00
Parseval's
Theorem
信号，在时域上的能量（信号的平方的积分）等于在频域上的能量，工程一般写为： 另一个类似的定理，Plancherel'sTheorem。
shenyan008
·
2010-04-07 15:00
数学词汇表
数学mathematics,maths(BrE),math(AmE)公理axiom定理
theorem
计算calculation运算operation证明prove假设hypothesis,hypotheses
chl033
·
2010-03-11 15:00
Integer
System
Graph
statistics
prism
permutation
主定理 Master
Theorem
当遇到形如T(n) = aT(n/b) + f(n)的递归表达式的时候，如果要用渐进符号表示T(n)，每次都花时间来画递归树（RecursionTree）显然不够经济。 在这个问题上，主定理给了我们一个捷径：
killua_hzl
·
2010-02-16 21:00
tree
recursion
Test Prime Using Fermat's Little
Theorem
;Fermat'slittletheorem ;IfNisaprimenumberandAisanypositivenumberlessthanN,then(A^N%N)==(A%N).(A^NstandsforAraisedtotheNthpower.) ;Thistheoremcanbeusedtotesttheprimalityofanumber.Iftheaboverelationisno
xuhx
·
2009-08-01 15:00
Distributed 分布式: CAP etc
//foundationdb.com/key-value-store/white-papers/the-cap-theoremhttp://robertgreiner.com/2014/08/cap-
theorem
-revisited
Wuaner
·
2009-05-21 18:00
partition
CAP
Replication
sharding
Distributed
Distributed 分布式: CAP etc
//foundationdb.com/key-value-store/white-papers/the-cap-theoremhttp://robertgreiner.com/2014/08/cap-
theorem
-revisited
Wuaner
·
2009-05-21 18:00
Distributed
CAP
partition
sharding
replication
Distributed 分布式: CAP etc
//foundationdb.com/key-value-store/white-papers/the-cap-theoremhttp://robertgreiner.com/2014/08/cap-
theorem
-revisited
Wuaner
·
2009-05-21 18:00
Distributed
CAP
partition
sharding
replication
Distributed 分布式: CAP etc
//foundationdb.com/key-value-store/white-papers/the-cap-theoremhttp://robertgreiner.com/2014/08/cap-
theorem
-revisited
Wuaner
·
2009-05-21 18:00
partition
CAP
Replication
sharding
Distributed
Distributed 分布式: CAP etc
//foundationdb.com/key-value-store/white-papers/the-cap-theoremhttp://robertgreiner.com/2014/08/cap-
theorem
-revisited
Wuaner
·
2009-05-21 18:00
partition
CAP
Replication
sharding
Distributed
数学英语词汇
数学英语词汇一般词汇 数学 mathematics, maths(BrE), math(AmE) 公理 axiom 定理
theorem
计算 calculation 运算 operation 证明 prove
wapysun
·
2009-05-02 21:00
Google
UP
浅究初等数论之中国剩余定理（Chinese Remainder
Theorem
）
浅究初等数论之中国剩余定理（ChineseRemainderTheorem） 推论1：方程ax=b(modn)对于未知量x有解，当且仅当gcd(a,n)|b。 推论2：方程ax=b(modn)或者对模n有d个不同的解，其中d=gcd(a,n)，或者无解。 定理1：设d=gcd(a,n)，假定对整数x和y满足d=ax+by(比如用扩展Euclid算法求出的一组解)。如果d|b，则方程ax=b(mod
The Fourth Dimension Space
·
2009-04-08 01:00
Which Numbers are the Sum of Two Squares?
Themaingoaloftoday'slectureistoprovethefollowingtheorem.
Theorem
1.1Anumberisasumoftwosquaresifandonlyifallprimefactorsofoftheformhaveevenexponentintheprimefactorizationof.Beforetacklingaproof
ihuashao
·
2008-11-24 19:00
C++
c
C#
Which Numbers are the Sum of Two Squares?
Themaingoaloftoday'slectureistoprovethefollowingtheorem.
Theorem
1.1 Anumber isasumoftwosquaresifandonlyifallprimefactorsof
cjc
·
2008-11-24 19:00
number
Which Numbers are the Sum of Two Squares?
Themaingoaloftoday'slectureistoprovethefollowingtheorem.
Theorem
1.1 Anumber isasumoftwosquaresifandonlyifallprimefactorsof
cjc
·
2008-11-24 19:00
number
Which Numbers are the Sum of Two Squares?
Themaingoaloftoday'slectureistoprovethefollowingtheorem.
Theorem
1.1 Anumber isasumoftwosquaresifandonlyifallprimefactorsof
eimhee
·
2008-11-24 19:00
number
Lagrange's four-square
theorem
Lagrange's four-square
theorem
( http://en.wikipedia.org/wiki/Lagrange%27s_four-square_
theorem
) Lagrange's
eimhee
·
2008-11-01 22:00
lag
Lagrange's four-square
theorem
Lagrange's four-square
theorem
( http://en.wikipedia.org/wiki/Lagrange%27s_four-square_
theorem
) Lagrange's
ihuashao
·
2008-11-01 22:00
lag
Lagrange's four-square
theorem
Lagrange's four-square
theorem
( http://en.wikipedia.org/wiki/Lagrange%27s_four-square_
theorem
) Lagrange's
eimhee
·
2008-11-01 22:00
lag
Lagrange's four-square
theorem
Lagrange's four-square
theorem
( http://en.wikipedia.org/wiki/Lagrange%27s_four-square_
theorem
) Lagrange's
cjc
·
2008-11-01 22:00
lag
Master method/Master
theorem
According to my understand,Detail to see OLCRS chapter 4. Master Method: T(n)=aT(n/b)+f(n) base
wss71104307
·
2008-10-14 17:00
F#
Master method/Master
theorem
According to my understand,Detail to see OLCRS chapter 4. Master Method: T(n)=aT(n/b)+f(n) base
wss71104307
·
2008-10-14 17:00
F#
[zz]中国剩余公理+扩展欧几里德算法
[reference:http://en.wikipedia.org/wiki/Chinese_remainder_
theorem
&http://en.wikipedia.org/wiki/Extended_Euclidean_algorithm
xan walking & thinking
·
2008-09-26 13:00
中国剩余定理（Chinese Remainder
Theorem
）
中国剩余定理民间传说着一则故事――“韩信点兵”。秦朝末年，楚汉相争。一次，韩信将1500名将士与楚王大将李锋交战。苦战一场，楚军不敌，败退回营，汉军也死伤四五百人，于是韩信整顿兵马也返回大本营。当行至一山坡，忽有后军来报，说有楚军骑兵追来。只见远方尘土飞扬，杀声震天。汉军本来已十分疲惫，这时队伍大哗。韩信兵马到坡顶，见来敌不足五百骑，便急速点兵迎敌。他命令士兵3人一排，结果多出2名；接着命令士兵5
yangwen13
·
2008-09-09 10:50
算法
职场
休闲
秦九韶
剩余定理
Bayes’
Theorem
贝叶斯定理
贝叶斯定理在数据挖掘，邮件过滤，人工智能方面都有应用，近几年来开始被广泛关注当另一事件B发生时，事件A的条件概率是Pr{A|B}=Pr{A&B}/Pr{B}另外Pr{B|A}=Pr{A&b}/Pr{A}===>Pr{A|B}Pr{B}=Pr{B|A}Pr{A}===>Pr{A|B}=Pr{B|A}Pr{A}/Pr{B}又Pr{B}=Pr{A&B}+Pr{~A&B}===>Pr{A|B}=Pr{B|
浪漫主义
·
2007-08-17 14:00
Intuition out of counter-intuition
C++的罗浮宫(http://blog.csdn.net/pongba) Lately I stumbled across an interesting article about Bayes
Theorem
wapysun
·
2006-12-18 16:00
count
Intuition out of counter-intuition
C++的罗浮宫(http://blog.csdn.net/pongba) Lately I stumbled across an interesting article about Bayes
Theorem
61party
·
2006-12-18 16:00
Blog
Intuition out of counter-intuition
C++的罗浮宫(http://blog.csdn.net/pongba) Lately I stumbled across an interesting article about Bayes
Theorem
winzenghua
·
2006-12-18 16:00
Blog
Intuition out of counter-intuition
C++的罗浮宫(http://blog.csdn.net/pongba) Lately I stumbled across an interesting article about Bayes
Theorem
varsoft
·
2006-12-18 16:00
Blog
数学词汇英语翻译
数学 mathematics, maths(BrE), math(AmE) 公理 axiom 定理
theorem
计算 calculation 运算 operation 证明 prove 假设 hypothesis
wapysun
·
2006-09-26 10:00
UP
数学词汇英语翻译
数学mathematics,maths(BrE),math(AmE)公理axiom定理
theorem
计算calculation运算operation证明prove假设hypothesis,hypotheses
Suprman
·
2006-09-26 10:00
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