division

nagios 监控windows 网卡流量

from __future__ import division import time,wmi,win32com from optparse import OptionParser parser = 
jastme·2015-12-07 10:00

nagios 监控windows 磁盘 IO

from __future__ import division import time,wmi,win32com from optparse import OptionParser parser = 
jastme·2015-12-07 09:00

LightOJ 1214 - Large Division 【同余定理】

LightOJ1214-LargeDivision TimeLimit:1000MS     MemoryLimit:32768KB     64bitIOFormat:%lld&%lluSubmit StatusDescriptionGiventwointegers, a and b,youshouldcheckwhether a isdivisibleby b ornot.Weknowthat
lin14543·2015-12-06 15:00

LightOJ 1214 - Large Division【同余定理】

1214-LargeDivisionPDF(English)StatisticsForumTimeLimit: 1second(s)MemoryLimit: 32MBGiventwointegers, a and b,youshouldcheckwhether a isdivisibleby b ornot.Weknowthataninteger a isdivisiblebyaninteger 
qq_29600137·2015-12-06 12:00

Light OJ 1214 - Large Division 【同余定理】

1214-LargeDivisionPDF(English)StatisticsForumTimeLimit:1second(s)MemoryLimit:32MBGiventwointegers,aandb,youshouldcheckwhetheraisdivisiblebybornot.Weknowthatanintegeraisdivisiblebyanintegerbifandonlyif
liu6886·2015-12-03 18:00

poj3140 Contestants Division（树形dp）

ContestantsDivisionTimeLimit: 2000MS MemoryLimit: 65536KTotalSubmissions: 9004 Accepted: 2583DescriptionInthenewACM-ICPCRegionalContest,aspecialmonitoringandsubmittingsystemwillbesetup,andstudentswill
d_x_d·2015-11-28 20:00

python 系统监控

/usr/bin/python2.7 # -*- coding:utf-8 -*- #检查网卡流量 from __future__ import division import commands from
eddy_linux·2015-11-27 14:00

再次阅读《精通CSS-高级Web标准解决方案（第二版）》

《精通CSS》第一章：语义化的好处：①自己更易处理（搜索和避免不必要的代码膨胀）②利用SEO③屏幕阅读的用户可以依靠标题进行页面导航div（division
刘健超-J.c·2015-11-24 00:00

OpenCASCADE Quaternion

The quaternions are members of a noncommutative division algebra first invented by William Rowan Hamilton
·2015-11-13 22:17

poj 3140 Contestants Division [DFS]

题意：一棵树每个结点上都有值，现删掉一条边，使得到的两棵树上的数值和差值最小。 思路：这个题我直接dfs做的，不知道树状dp是什么思路。。一开始看到数据规模有些后怕，后来想到long long 可以达到10^18，我突然就释然了。 整体思路就是，先记录下整棵树的数值之和tot，然后对这棵树进行一遍dfs，每个结点都维护一个num值，num[x]表示结点x和它子树上的数值和。每求出一个结点的nu
·2015-11-13 17:38

poj 3140 Contestants Division（树形dp? dfs计数+枚举）

  本文出自   http://blog.csdn.net/shuangde800 --------------------------------------------------------------------------------------   题目链接： poj-3140   题目 &n
·2015-11-13 16:35

LeetCode 029 Divide Two Integers

题目要求：Divide Two Integers Divide two integers without using multiplication, division and mod operator
·2015-11-13 13:31

Leetcode | Divide Two Integers

Divide two integers without using multiplication, division and mod operator. 这道题要AC也不容易，许多基础概念不懂。
·2015-11-13 13:02

poj 3140 Contestants Division

http://poj.org/problem?id=3140 一遍DFS 枚举任一条边被切断的情况就可以 代码： #include<iostream> #include<stdio.h> #include<string.h> #include<queue> #include<cmath> #include<stac
·2015-11-13 12:14

Python基础教程读书笔记（第1章—第2章：基础知识、列表和元组）

from _future_ import division 加入此语句，则只执行普通除法（3.0之前是这样）。
·2015-11-13 10:35

【HDU】3480 Division

http://acm.hdu.edu.cn/showproblem.php?pid=3480 题意：一个n个元素的集合S要求分成m个子集且子集并为S，要求$\sum_{S_i} (MAX-MIN)^2$最小。（n<=10000, m<=5000） #include <cstdio> #include <cstring> #include <alg
·2015-11-13 10:02

【读书笔记】精通CSS 第二版

div代表division，它可以将文档分隔为几个有意义的部分，应该只在没有现有元素能实现区域分隔的情况下使用div。
·2015-11-13 09:34

leetcode第28题--Divide Two Integers

Divide two integers without using multiplication, division and mod operator.
·2015-11-13 08:45

LeetCode Online Judge 题目C# 练习 - Divid Two Integer

Divide two integers without using multiplication, division and mod operator. 1 public static int Divid
·2015-11-13 08:48

[LeetCode]Divide Two Integer

Divide two integers without using multiplication, division and mod operator. 思考：位运算。
·2015-11-13 08:00

FOJ 1607 Greedy division 数学题

题目地址： http://acm.fzu.edu.cn/problem.php?pid=1607 给定一个n，将n平均分成m份，问有几种方法，每种方法中找出最大的数。思路：就是求n的因子数、先将每个数求出最小素因子、再将n的所有素因子数加1相乘。小结论：求一个数的所有因子数、先分解、n=(a^x)*(b^y)*(c^z),(a、b、c均为素数)，因子数=(x+1)*(y+1)*(
·2015-11-13 07:05

poj 3140 Contestants Division

http://poj.org/problem?id=3140 这道题数据大，需要用long long，dfs枚举删除的边求最小就行。 1 #include <cstdio> 2 #include <vector> 3 #include <cstring> 4 #include <algorithm> 5 #define
·2015-11-13 07:05

HTML中的解释

div              语义：Division（分隔
·2015-11-13 06:27

Java 语法 索引 ----- 运算符

// addition 加 x = 3-2; // 1 // subtraction 减 x = 3*2; // 6 // multiplication 乘 x = 3/2; // 1 // division
·2015-11-13 06:25

BZOJ 1385: [Baltic2000]Division expression

题目 1385: [Baltic2000]Division expression Time Limit: 5 Sec  Memory Limit: 64 MB
·2015-11-13 03:56

poj 3140 Contestants Division（树形dp? dfs计数+枚举）

  本文出自   http://blog.csdn.net/shuangde800 --------------------------------------------------------------------------------------   题目链接： poj-3140   题目 &n
·2015-11-13 02:07

IBM大型主机（Mainframe）技术简介之三——应用开发摘要（一）

代码结构 COBOL的源程序的代码主体部分必须从第8列开始（A区域），通常包括分区Division，分段Section和第一级的数据等。
·2015-11-13 02:42

zoj 3033 Board Games

      Memory Limit: 32768 KB You have been hired by the quality control division
·2015-11-13 01:40

SRM 176 Division-I, Level 2

Problem Statement     A derangement of n numbers is a permutation of those numbers in which none of the numbers appears in its original place. For example, the numbers {1,2,3} can be
·2015-11-13 01:46

SRM 171 Division-I, Level 2

Problem Statement     You are an electrical engineer putting together a prototype circuit in the lab. You need to add in one resistor to finish things up, but there is a problem: you
·2015-11-13 01:45

SRM 169 Division-I, Level 2

Problem Statement     Fabian is in charge of a law firm working on an important case. For a case coming up, he needs a specific folder which is stored in one of the filing cabinets ar
·2015-11-13 01:44

SRM 161 Division-I, Level 2

Problem Statement     You are practicing your tennis game with a hitting partner. Each time the ball comes over the net a player can either hit it cross-court, or down-the-line. In th
·2015-11-13 01:44

SRM 159 Division-I, Level 2

Problem Statement     The Price Is Right is a television game show. In the final round of competition, the contestant is shown the prizes which he can win. To win everything, he must
·2015-11-13 01:43

SRM 158 Division-I, Level 2

Problem Statement     Note to plugin users: there is an image in this problem statement. Please view the statement in the applet to see the image There is a collection of multi-color
·2015-11-13 01:42

SRM 156 Division-I, Level 2

Problem Statement     You have been put in charge of writing the sofware that powers an elevator in a very tall office building. Because there is only one elevator in the building, an
·2015-11-13 01:41

SRM 148 Division-I, Level 2

Problem Statement     9 numbers need to be arranged in a magic number square. A magic number square is a square of numbers that is arranged such that every row and column has the same
·2015-11-13 01:41

SRM 150 Division-I, Level 2

Problem Statement     Karel is a frustrated painter who works by day in an electrical repair shop. Inspired by the color-coded bands on resistors, he is painting a series of long, nar
·2015-11-13 01:40

SRM 146 Division-I, Level 2

Problem Statement     Masterbrain is a two player board game in which one player decides on a secret combination of digits, while the other must figure it out in 10 guesses or less. T
·2015-11-13 01:39

SRM 149 Division-I, Level 2

Problem Statement     It is a common practice in cryptography to remove the spaces from a message before encoding it to help to disguise its structure. Even after it is then decoded,
·2015-11-13 01:39

LeetCode: Divide Two Integers 解题报告

Divide Two Integers Divide two integers without using multiplication, division and mod operator.
·2015-11-13 00:17

解读手机专业术语

下面让大家了解以上的专业术语所指为 何 CDMA CDMA是Code－Division M
·2015-11-13 00:01

poj3140Contestants Division

链接 这叫树形DP吗。。？断开某条边 求剩下两颗树数权值和的差最小 dfs一遍 枚举边 查了n久 wa n次  dp数组没初始化。。 在poj上1A感觉应该挺爽 1 #include <iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algori
·2015-11-13 00:13

LeetCode_Divide Two Integers

Divide two integers without using multiplication, division and mod operator.
·2015-11-12 23:14

HDOJ树形DP专题之Contestants Division

题目链接 题目大意：给定一棵树，每个结点有一个权值，一棵树的权值为所有结点的权值和，现将这棵树分为两棵子树，要使得两子树的权值差最小。 我的做法是先将无根树化为有根树，然后求每棵子树的权值，最后用一次扫描求结果。需要注意的是结果要用long long型。 View Code 1 #include <stdio.h> 2 #include <string.h&
·2015-11-12 22:25

物理层—信道复用

1.频分复用技术FDM（Frequency Division Multiplexing） 　　频分复用技术就是用户在分配到一定的频带后，在通信过程中自始至终都占用这个频带，可见频分复用的所有用户在同样的时间占用不同的带宽资源
·2015-11-12 20:33

[LeetCode#29]Divide Two Integers

The problem: Divide two integers without using multiplication, division and mod operator.
·2015-11-12 19:29

__future__模块

2 内容 'absolute_import' 'all_feature_names' 'division'：定义整数除法/，地板除用//。老版本/表示地板除。
·2015-11-12 18:19

java多线程向数据库写入数据

关键代码 //将数据库中的数据条数分段 public void division(){ //获取要导入的总的数据条数 String sql3="SELECT count(*
·2015-11-12 18:24

leetcode--Divide two integers

1.题目描述 Divide two integers without using multiplication, division and mod operator.
·2015-11-12 17:40

POJ 3140 Contestants Division（树形DP）

题意： 给定一棵 n 棵节点的树，求删去某条边后两个分支的最小差异值。 思路： 1. 题目给出来的是一张无向图，所以要设置 vis 标记数组按照深度遍历树的方法来解析，得到 dp[u] ： u 为根节点的子树学生数量总数。 2. 最后的到的结果为 ans = min(2 * dp[u] - sum)，注意会超过 int 表示范围，用 __int64 范围的数来表示。 3. 学习了一种“孩
·2015-11-12 17:01
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