hdu1071

HDU1071微积分公式求曲线面积

解题思路：我们已知三个点分别是抛物线顶点，直线交于抛物线的两点。求出两条线的解析式然后用定积分公式就解决了。那么，难点来了，怎么求这个直线和抛物线的解析式呢？直线的解析式我们已知两点，用两点斜率公式求出斜率k，然后回待直线方程中求出与y轴的交点的纵坐标L，之后看看抛物线，因为知道顶点横坐标，即抛物线的对称轴，x1=-b/2*a，如果求出a，b之后我们就可以带入假设的抛物线坐标方程y=ax^2+bx
小胡同的诗·2022-12-01 10:57

HDU1071(数学题)

题意:给你这三个点的坐标,求面积题解:水题,不想写题解了出去骑行有点虚;就是利用三点求出直线方程,抛物线方程,然后求积分直接上代码code:#includeintmain(){intn;scanf("%d",&n);doublex,y,x1,y1,x2,y2;while(n--){scanf("%lf%lf%lf%lf%lf%lf",&x,&y,&x1,&y1,&x2,&y2);doublek=(
风尘tel小城·2020-08-10 13:42

hdu1071 The area

TheareaProblemDescriptionIgnatiusboughtalandlastweek,buthedidn'tknowtheareaofthelandbecausethelandisenclosedbyaparabolaandastraightline.Thepicturebelowshowsthearea.Nowgivenalltheintersectantpointsshow
wchhlbt·2016-02-25 23:00

hdu1071（抛物线，直线以及二重积分）

http://acm.hdu.edu.cn/showproblem.php?pid=1071 View Code // 抛物线 yp=a*(x-b)^2+c; // 直线 yz=k*x+s; // 二重积分公式： f(x0,x1)(yp-yz)*dx; #include " iostream " using namespace std; doubl
·2015-11-08 17:10

ZZULI-Summer Training Contest(Six) 解题报告

巩固下strcpy  strcat  strstr函数的应用   1002 --HDU1846 博弈题 最基础的博弈，规律很容易发现的   1003 –HDU1071
·2015-11-07 15:36

The area （hdu1071）积分求面积

The area Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7066 Accepted Submission(s): 4959 Problem Description Ignatius bought a land last week
·2015-10-31 09:33

hdu1071数学题 The area

TheareaTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):8279    AcceptedSubmission(s):5810ProblemDescriptionIgnatiusboughtalandlastweek,buthedidn'tknowthea
chaiwenjun000·2015-04-13 22:00

HDU1071 The area 【积分】

TheareaTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):7476    AcceptedSubmission(s):5222ProblemDescriptionIgnatiusboughtalandlastweek,buthedidn'tknowthea
u012846486·2014-07-23 11:00

ACM-计算几何之The area——hdu1071

Thearea题目：http://acm.hdu.edu.cn/showproblem.php?pid=1071ProblemDescriptionIgnatiusboughtalandlastweek,buthedidn'tknowtheareaofthelandbecausethelandisenclosedbyaparabolaandastraightline.Thepicturebelow
lx417147512·2014-04-11 14:00
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