ZigZag Conversion

题目描述
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

解题思路
利用给定的这种规则进行字符串的输出。

自己的代码1
该代码超时了,需要选择更加高效的代码。
package leetcode;

import java.util.ArrayList;
import java.util.List;

public class ZigZagConversion {
	public String convert(String s, int nRows) {
		if(s == null || s == "") return s;
		if(nRows <= 0) return null;
		if(nRows == 1) return s;
		if(nRows >= s.length()) return s;
		
		String str = "";
		for(int i = 0; i < nRows; i++){
			int step = 0;
			if(i == 0 || i == nRows-1) step = 4;
			else step = 2;
			
			int sum = i;
			while(sum <= s.length()-1){
				str += s.charAt(sum);
				sum += step;
			}
		}
        return str;
    }
	
	public static void main(String[] args) {
		//String s = "";
		String s = "PAYPALISHIRING";
		int nRows = 3;
		
		ZigZagConversion zzc = new ZigZagConversion();
		System.out.println(zzc.convert(s, nRows));
	}
}


自己的代码2
该代码可以通过,将时间复杂度降到了O(n)。
package leetcode;

import java.util.ArrayList;
import java.util.List;

public class ZigZagConversion {
	@SuppressWarnings("unchecked")
	public String convert(String s, int nRows) {
		if(s == null || s == "") return s;
		if(nRows <= 0) return null;
		if(nRows == 1) return s;
		if(nRows >= s.length()) return s;
		
		List<Character>[] listArray = new List[nRows];
		for(int i = 0; i < nRows; i++){
			List<Character> list = new ArrayList<Character>();
			listArray[i] = list;
		}
		
		int times = 0;
		boolean ascending =  true;
		for(int i = 0; times < s.length(); times++){
			listArray[i].add(s.charAt(times));
			if(i == 0) {
				ascending = true;
			}
			else if(i == nRows - 1){
				ascending = false;
			}
			
			if(ascending) i++;
			else i--;
			
		}
		
		String str = "";
		for(List<Character> list : listArray){
			for(char c : list)
				str += c;
		}
		
        return str;
    }
	
	public static void main(String[] args) {
		//String s = "";
		String s = "PAYPALISHIRING";
		int nRows = 3;
		
		ZigZagConversion zzc = new ZigZagConversion();
		System.out.println(zzc.convert(s, nRows));
	}
}

你可能感兴趣的:(conversion)