用函数实现输入某年某月某日，判断这一天是这一年的第几天？闰年情况也考虑进去

#判断是否闰年
def is_leap_year(year):
    if (year%400)==0 or ((year%4==0) and (year%100!=0)):
        print("是闰年")
        return 1
    else :
        print("不是闰年")
        return 0

#计算天数
def month_turn_day(year,month,day):
    day_sum =0
    month31 = [1,3,5,7,8,10,12]
    month30 = [4,6,9,11]
    for x in range(1,month):
        if x in month31:
            day_sum +=31
        elif x in month30:
            day_sum +=30
        elif is_leap_year(year) and  x==2:   #判断是否是闰年
            day_sum +=29
        elif x==2:
            day_sum +=28
    day_sum +=day
    print("%s是这年的第%d天"%(time,day_sum))

#获取年月日
def get_y_m_d(time):
    year = int(time[0:4])
    month = int(time[4:6])
    day = int(time[6:8])
    month_turn_day(year,month,day)
    print("输入的年月日为",year,month,day)

time = input("请输入   年   月   日：")
get_y_m_d(time)