POJ 2259 Team Queue

Team Queue Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4533   Accepted: 1569 Description Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for example.  In a team queue each element belongs to a team. If an element enters the queue, it first searches the queue from head to tail to check if some of its teammates (elements of the same team) are already in the queue. If yes, it enters the queue right behind them. If not, it enters the queue at the tail and becomes the new last element (bad luck). Dequeuing is done like in normal queues: elements are processed from head to tail in the order they appear in the team queue.  Your task is to write a program that simulates such a team queue. Input The input will contain one or more test cases. Each test case begins with the number of teams t (1<=t<=1000). Then t team descriptions follow, each one consisting of the number of elements belonging to the team and the elements themselves. Elements are integers in the range 0 - 999999. A team may consist of up to 1000 elements.  Finally, a list of commands follows. There are three different kinds of commands:  ENQUEUE x - enter element x into the team queue  DEQUEUE - process the first element and remove it from the queue  STOP - end of test case The input will be terminated by a value of 0 for t.  Warning: A test case may contain up to 200000 (two hundred thousand) commands, so the implementation of the team queue should be efficient: both enqueing and dequeuing of an element should only take constant time. Output For each test case, first print a line saying "Scenario #k", where k is the number of the test case. Then, for each DEQUEUE command, print the element which is dequeued on a single line. Print a blank line after each test case, even after the last one.  Sample Input 2 3 101 102 103 3 201 202 203 ENQUEUE 101 ENQUEUE 201 ENQUEUE 102 ENQUEUE 202 ENQUEUE 103 ENQUEUE 203 DEQUEUE DEQUEUE DEQUEUE DEQUEUE DEQUEUE DEQUEUE STOP 2 5 259001 259002 259003 259004 259005 6 260001 260002 260003 260004 260005 260006 ENQUEUE 259001 ENQUEUE 260001 ENQUEUE 259002 ENQUEUE 259003 ENQUEUE 259004 ENQUEUE 259005 DEQUEUE DEQUEUE ENQUEUE 260002 ENQUEUE 260003 DEQUEUE DEQUEUE DEQUEUE DEQUEUE STOP 0 Sample Output Scenario #1 101 102 103 201 202 203 Scenario #2 259001 259002 259003 259004 259005 260001 Source Ulm Local 1998

感觉不是很难的一个队列题，但是读题要读一下。多做做这种题动下脑子也挺还行？

题目大意是在一个组里面的数可以插到比它后面出现的组里面的数的前面，同一个组的数还按正常队列排序。

所以就是开两个队列，一个队列存每个队的数，一个队列存每组数的序号。最后注意一下输出结束后还要单独空一行。

#include
#include
#include
using namespace std;

int a[999999+10],in[1010];
queue q,tmp[1010];
char ch[10];

int main()
{
	int i,j,b,x;
	int t,n,kcase=1;
	while(scanf("%d",&t),t) 
	{
		memset(in,0,sizeof(in));
		while(!q.empty())
			q.pop();
		for(i=0;i<1010;i++)
			while(!tmp[i].empty())
				tmp[i].pop();
		printf("Scenario #%d\n",kcase++);
		for(i=0;i