模板

数据结构

单调队列

// BZOJ 2096
#include
#include
#include
using namespace std;
#define N 3000005

int k,n,l,r,lmax,rmax,lmin,rmin,ans;
int a[N],qmax[N],qmin[N];
struct hp{int Max,Min;};

void push(int id)
{
    while (lmaxwhile (lmin=a[id]) --rmin;
    qmin[++rmin]=id;
}
hp pop(int id)
{
    while (lmax1]int Max=a[qmax[lmax+1]];
    while (lmin1]int Min=a[qmin[lmin+1]];
    return (hp){Max,Min};
}
int main()
{
    scanf("%d%d",&k,&n);
    for (int i=1;i<=n;++i) scanf("%d",&a[i]);
    l=r=1;lmax=rmax=lmin=rmin=0;push(l);
    while (l<=n)
    {
        if (l>r)
        {
            r=l;lmax=rmax=lmin=rmin=0;push(l);
        }
        while (rif (a[r+1]>now.Max)
                {if (a[r+1]-now.Min>k) break;}
            else if (a[r+1]if (now.Max-a[r+1]>k) break;}
            ++r;push(r);
        }
        ans=max(ans,r-l+1);
        ++l;
    }
    printf("%d\n",ans);
}

单调栈

// BZOJ 1657
#include
#include
#include
using namespace std;
#define N 50005

int n,h[N],val[N],l[N],r[N],Max,stack[N],top,sum[N],ans;

int main()
{
    scanf("%d",&n);
    for (int i=1;i<=n;++i) scanf("%d%d",&h[i],&val[i]),l[i]=1,r[i]=n;

    top=0;
    for (int i=1;i<=n;++i)
    {
        while (top&&h[stack[top]]stack[top]]=i-1;
            --top;
        }
        stack[++top]=i;
    }
    top=0;
    for (int i=n;i>=1;--i)
    {
        while (top&&h[stack[top]]stack[top]]=i+1;
            --top;
        }
        stack[++top]=i;
    }
    for (int i=1;i<=n;++i) sum[l[i]-1]+=val[i],sum[r[i]+1]+=val[i];
    for (int i=1;i<=n;++i) ans=max(ans,sum[i]);
    printf("%d\n",ans);
}

St表

// poj3264
#include
#include
#include
#include
#define N 50005
#define sz 16
using namespace std;  
int n,m,l,r,Max,Min;
int a[N],lg2[N],stmax[N][sz],stmin[N][sz];
int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1,p=0;i<=n;++i)
    {
        while ((1<
        lg2[i]=p-1;
    }
    for (int i=1;i<=n;++i)
      scanf("%d",&a[i]),stmax[i][0]=stmin[i][0]=a[i];
    for (int j=1;j
        for (int i=1;i<=n;++i)
          if (i+(1<
            {
                stmax[i][j]=max(stmax[i][j-1],stmax[i+(1<<(j-1))][j-1]);
                stmin[i][j]=min(stmin[i][j-1],stmin[i+(1<<(j-1))][j-1]);
            }
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d",&l,&r);
        if (l>r) swap(l,r);
        int k=lg2[r-l+1];
        Max=max(stmax[l][k],stmax[r-(1<
        Min=min(stmin[l][k],stmin[r-(1<
        printf("%d\n",Max-Min);
    }
}

Lca

#include
#include
#include
using namespace std;
#define N 100005
#define sz 17

int n,m,x,y;
int tot,point[N],nxt[N*2],v[N*2];
int f[N][sz+5],h[N],size[N];
struct hp{int pre,pt;};


void addedge(int x,int y)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x;
}
void build(int x,int fa,int dep)
{
    h[x]=dep; size[x]=1;
    for (int i=1;iif ((h[x]-(1<1) break;
        f[x][i]=f[f[x][i-1]][i-1];
    }
    for (int i=point[x];i;i=nxt[i])
        if (v[i]!=fa)
        {
            f[v[i]][0]=x;
            build(v[i],x,dep+1);
            size[x]+=size[v[i]];
        }
}
int lca(int x,int y)
{
    if (h[x]int k=h[x]-h[y];
    for (int i=0;iif ((1<if (x==y) return x;
    for (int i=sz-1;i>=0;--i)
        if (f[x][i]!=f[y][i]) x=f[x][i],y=f[y][i];
    return f[x][0];
}
hp find(int x,int high)
{
    int xx=x;
    for (int i=sz-1;i>=0;--i)
        while (h[f[x][i]]>high) xx=x,x=f[x][i];
    xx=x,x=f[x][0];
    hp ans;ans.pre=xx,ans.pt=x;
    return ans;
}
int main()
{
    scanf("%d",&n);
    for (int i=1;iscanf("%d%d",&x,&y);
        addedge(x,y);
    }
    build(1,0,1);
    scanf("%d",&m);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d",&x,&y);
        if (h[x]if (x==y)
        {
            printf("%d\n",n);
            continue;
        }
        int r=lca(x,y);
        int len=h[x]-h[r]+h[y]-h[r];
        if (len%2)
        {
            puts("0");
            continue;
        }
        len/=2;
        int high=h[x]-len;
        if (high==h[r])
        {
            hp date1=find(x,high);
            hp date2=find(y,high);
            printf("%d\n",n-size[r]+size[r]-size[date1.pre]-size[date2.pre]);
        }
        else
        {
            hp date=find(x,high);
            printf("%d\n",size[date.pt]-size[date.pre]);
        }
    }
}

Splay

// BZOJ 3224
#include
#include
#include
using namespace std;
#define N 300005

int n,opt,x,root,sz;
int f[N],ch[N][2],key[N],size[N],cnt[N];

void clear(int x)
{
    f[x]=ch[x][0]=ch[x][1]=key[x]=size[x]=cnt[x]=0;
}
int get(int x)
{
    return ch[f[x]][1]==x;
}
void update(int x)
{
    size[x]=cnt[x]+size[ch[x][0]]+size[ch[x][1]];
}
void rotate(int x)
{
    int old=f[x],oldf=f[old],wh=get(x);
    ch[old][wh]=ch[x][wh^1];
    if (ch[old][wh]) f[ch[old][wh]]=old;
    ch[x][wh^1]=old;
    f[old]=x;
    if (oldf) ch[oldf][ch[oldf][1]==old]=x;
    f[x]=oldf;
    update(old);
    update(x);
}
void splay(int x)
{
    for (int fa;fa=f[x];rotate(x))
        if (f[fa])
            rotate( (get(x)==get(fa))?fa:x );
    root=x;
}
void insert(int x)
{
    if (!root)
    {
        root=++sz;
        cnt[sz]=size[sz]=1;key[sz]=x;
        return;
    }
    int now=root,fa=0;
    while (1)
    {
        if (x==key[now])
        {
            cnt[now]++;
            update(now);
            splay(now);
            break;
        }
        fa=now;
        now=ch[now][x>key[now]];
        if (!now)
        {
            ++sz;
            f[sz]=fa;ch[fa][x>key[fa]]=sz;
            size[sz]=cnt[sz]=1;
            key[sz]=x;
            update(fa);
            splay(sz);
            break;
        }
    }
}
int find(int x)
{
    int now=root,ans=0;
    while (1)
    {
        if (x0];
        else
        {
            ans+=size[ch[now][0]];
            if (x==key[now])
            {
                splay(now);
                return ans+1;
            }
            ans+=cnt[now];
            now=ch[now][1];
        }
    }
}
int findx(int x)
{
    int now=root;
    while (1)
    {
        if (x<=size[ch[now][0]]) now=ch[now][0];
        else
        {
            x-=size[ch[now][0]];
            if (x<=cnt[now])
            {
                splay(now);
                return key[now];
            }
            x-=cnt[now];
            now=ch[now][1];
        }
    }
}
int pre()
{
    int now=ch[root][0];
    while (ch[now][1]) now=ch[now][1];
    return now;
}
int nxt()
{
    int now=ch[root][1];
    while (ch[now][0]) now=ch[now][0];
    return now;
}
void del(int x)
{
    int wh=find(x);
    if (cnt[root]>1)
    {
        --cnt[root];
        update(root);
        return;
    }
    if (!ch[root][0]&&!ch[root][1])
    {
        clear(root);
        root=0;
        return;
    }
    if (!ch[root][0])
    {
        int oldroot=root;
        root=ch[oldroot][1];
        f[root]=0;
        clear(oldroot);
        return;
    }
    if (!ch[root][1])
    {
        int oldroot=root;
        root=ch[oldroot][0];
        f[root]=0;
        clear(oldroot);
        return;
    }
    int oldroot=root;
    int leftbig=pre();splay(leftbig);
    ch[root][1]=ch[oldroot][1];
    f[ch[root][1]]=root;
    clear(oldroot);
    update(root);
    return;
}
int main()
{
    scanf("%d",&n);
    for (int i=1;i<=n;++i)
    {
        scanf("%d%d",&opt,&x);
        switch(opt)
        {
            case 1:
                {
                    insert(x);
                    break;
                }
            case 2:
                {
                    del(x);
                    break;
                }
            case 3:
                {
                    int ans=find(x);
                    printf("%d\n",ans);
                    break;
                }
            case 4:
                {
                    int ans=findx(x);
                    printf("%d\n",ans);
                    break;
                }
            case 5:
                {
                    insert(x);
                    printf("%d\n",key[pre()]);
                    del(x);
                    break;
                }
            case 6:
                {
                    insert(x);
                    printf("%d\n",key[nxt()]);
                    del(x);
                    break;
                }
        }
    }
    return 0;
}
// BZOJ 3223
#include
#include
#include
using namespace std;
#define N 100005
#define inf 1000000000

int n,m,l,r,root;
int a[N],f[N],ch[N][2],size[N],key[N],delta[N];

int get(int x)
{
    return ch[f[x]][1]==x;
}
void update(int x)
{
    size[x]=size[ch[x][0]]+size[ch[x][1]]+1;
}
void pushdown(int x)
{
    if (x&&delta[x])
    {
        delta[ch[x][0]]^=1;
        delta[ch[x][1]]^=1;
        swap(ch[x][0],ch[x][1]);
        delta[x]=0;
    }
}
int build(int l,int r,int fa)
{
    if (l>r) return 0;
    int mid=(l+r)>>1;
    f[mid]=fa;key[mid]=a[mid];size[mid]=1;
    int lch=build(l,mid-1,mid);
    int rch=build(mid+1,r,mid);
    ch[mid][0]=lch,ch[mid][1]=rch;
    update(mid);
    return mid;
}
void rotate(int x)
{
    pushdown(f[x]);
    pushdown(x);
    int old=f[x],oldf=f[old],wh=get(x);
    ch[old][wh]=ch[x][wh^1];
    if (ch[old][wh]) f[ch[old][wh]]=old;
    ch[x][wh^1]=old;
    f[old]=x;
    if (oldf) ch[oldf][ch[oldf][1]==old]=x;
    f[x]=oldf;
    update(old);
    update(x);
}
void splay(int x,int tar)
{
    for (int fa;(fa=f[x])!=tar;rotate(x))
        if (f[fa]!=tar)
            rotate( (get(x)==get(fa))?fa:x );
    if (!tar) root=x;
}
int find(int x)
{
    int now=root;
    while (1)
    {
        pushdown(now);
        if (x<=size[ch[now][0]]) now=ch[now][0];
        else
        {
            x-=size[ch[now][0]];
            if (x==1) return now;
            x-=1;
            now=ch[now][1];
        }
    }
}
void write(int x)
{
    pushdown(x);
    if (ch[x][0]) write(ch[x][0]);
    if (key[x]!=-inf&&key[x]!=inf) printf("%d ",key[x]);
    if (ch[x][1]) write(ch[x][1]);
}
int main()
{
    scanf("%d%d",&n,&m);
    a[1]=-inf;a[n+2]=inf;
    for (int i=1;i<=n;++i) a[i+1]=i;
    root=build(1,n+2,0);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d",&l,&r);
        if (l>=r) continue;
        int aa=find(l);
        int bb=find(r+2);
        splay(aa,0);
        splay(bb,aa);
        delta[ch[ch[root][1]][0]]^=1;
    }
    write(root);
    return 0;
}

树链剖分+dfs序

// BZOJ4196 NOI2015 软件包管理器
#include
#include
#include
using namespace std;

const int max_n=1e5+5;
const int max_e=max_n*2;
const int max_tree=max_n*5;

int n,q,x,N,ans;
char s[20];
int tot,point[max_n],next[max_e],v[max_e];
int size[max_n],h[max_n],father[max_n],son[max_n];
int top[max_n],in[max_n],out[max_n];
int sum[max_tree],delta[max_tree];

inline void addedge(int x,int y){
    ++tot; next[tot]=point[x]; point[x]=tot; v[tot]=y;
    ++tot; next[tot]=point[y]; point[y]=tot; v[tot]=x;
}

inline void dfs_1(int x,int fa,int dep){
    size[x]=1; h[x]=dep; father[x]=fa;
    int maxson=0;

    for (int i=point[x];i;i=next[i])
      if (v[i]!=fa){
        dfs_1(v[i],x,dep+1);
        size[x]+=size[v[i]];
        if (maxsoninline void dfs_2(int x,int fa){
    if (son[fa]!=x) top[x]=x;
    else top[x]=top[fa];
    in[x]=++N;

    if (son[x]) dfs_2(son[x],x);
    for (int i=point[x];i;i=next[i])
      if (v[i]!=fa&&v[i]!=son[x])
        dfs_2(v[i],x);

    out[x]=N;
}

inline void update(int now){
    sum[now]=sum[now<<1]+sum[now<<1|1];
}

inline void pushdown(int now,int l,int r,int mid){
    if (delta[now]>=0){
        sum[now<<1]=delta[now]*(mid-l+1);
        delta[now<<1]=delta[now];
        sum[now<<1|1]=delta[now]*(r-mid);
        delta[now<<1|1]=delta[now];
        delta[now]=-1;
    }
}

inline void interval_change(int now,int l,int r,int lrange,int rrange,int v){
    int mid=(l+r)>>1;
    if (lrange<=l&&r<=rrange){
        sum[now]=(r-l+1)*v;
        delta[now]=v;
        return;
    }

    pushdown(now,l,r,mid);
    if (lrange<=mid)
      interval_change(now<<1,l,mid,lrange,rrange,v);
    if (mid+1<=rrange)
      interval_change(now<<1|1,mid+1,r,lrange,rrange,v);
    update(now);
}

inline int query(int now,int l,int r,int lrange,int rrange){
    int mid=(l+r)>>1,ans=0;
    if (lrange<=l&&r<=rrange) return sum[now];

    pushdown(now,l,r,mid);
    if (lrange<=mid)
      ans+=query(now<<1,l,mid,lrange,rrange);
    if (mid+1<=rrange)
      ans+=query(now<<1|1,mid+1,r,lrange,rrange);
    return ans;
}

inline void QUERY(int u,int t){
    int f1=top[u],f2=top[t],ans=0;
    while (f1!=f2){
        if (h[f1]1,1,N,in[f1],in[u]);
        u=father[f1];
        f1=top[u];
    }
    if (in[u]>in[t]) swap(u,t);
    ans+=query(1,1,N,in[u],in[t]);
    int cnt=h[x];
    printf("%d\n",cnt-ans);
}

inline void CHANGE(int u,int t){
    int f1=top[u],f2=top[t],ans=0;
    while (f1!=f2){
        if (h[f1]1,1,N,in[f1],in[u],1);
        u=father[f1];
        f1=top[u];
    }
    if (in[u]>in[t]) swap(u,t);
    interval_change(1,1,N,in[u],in[t],1);
}

inline void INSTALL(int u,int t){
    QUERY(u,t);
    CHANGE(u,t);
}

inline void UNINSTALL(int x){
    ans=query(1,1,N,in[x],out[x]);
    printf("%d\n",ans);

    interval_change(1,1,N,in[x],out[x],0);
}

int main(){
    scanf("%d",&n);
    for (int i=1;iscanf("%d",&x);
        ++x;
        addedge(x,i+1);
    }

    dfs_1(1,0,1);
    dfs_2(1,0);

    memset(sum,0,sizeof(sum));
    memset(delta,128,sizeof(delta));

    scanf("%d",&q);
    for (int i=1;i<=q;++i){
        scanf("%s",s);
        scanf("%d",&x);
        ++x;
        if (s[0]=='i')
          INSTALL(1,x);
        else
          UNINSTALL(x);
    }
}

手写栈

inline void dfs_1()
{
    int temp=0;
    strack[++temp]=1; size[1]=1; h[1]=1;
    for (int i=1;i<=n;++i) cur[i]=point[i];
    while (temp)
    {
        int x=strack[temp];
        if (v[cur[x]]==father[x]) cur[x]=nxt[cur[x]];
        if (!cur[x])
        {
            temp--;
            if (father[x])
            {
                size[father[x]]+=size[x];
                if (size[x]>size[son[father[x]]]) son[father[x]]=x;
            }
            continue;
        }
        int vt=v[cur[x]];
        strack[++temp]=vt;
        size[vt]=1; h[vt]=h[x]+1; father[vt]=x;
        cur[x]=nxt[cur[x]];
    }
}
inline void dfs_2()
{
    int temp=0;
    strack[++temp]=1; num[1]=++N; top[1]=1;
    for (int i=1;i<=n;++i) cur[i]=point[i];
    while (temp)
    {
        int x=strack[temp];
        if (!use[x])
        {
            use[x]=1;
            int vt=son[x];
            if (vt)
            {
                strack[++temp]=vt;
                top[vt]=top[x];
                num[vt]=++N;
            }
            continue;
        }
        while (cur[x]&&(v[cur[x]]==father[x]||v[cur[x]]==son[x])) cur[x]=nxt[cur[x]];
        if (!cur[x])
        {
            temp--;
            continue;
        }
        else
        {
            int vt=v[cur[x]];
            strack[++temp]=vt;
            top[vt]=vt;
            num[vt]=++N;
            cur[x]=nxt[cur[x]];
        }
    }
}
// BZOJ2049
#include
#include
#include
#include
#include
using namespace std;
#define N 10005

char opt[10];
int n,m;
int f[N],ch[N][2],rev[N],stack[N];

bool isroot(int x)
{
    return ch[f[x]][0]!=x&&ch[f[x]][1]!=x;
}
int get(int x)
{
    return ch[f[x]][1]==x;
}
void pushdown(int x)
{
    if (x&&rev[x])
    {
        if (ch[x][0]) rev[ch[x][0]]^=1;
        if (ch[x][1]) rev[ch[x][1]]^=1;
        swap(ch[x][0],ch[x][1]);
        rev[x]=0;
    }
}
void rotate(int x)
{
    int old=f[x],oldf=f[old],wh=get(x);
    if (!isroot(old)) ch[oldf][ch[oldf][1]==old]=x;
    f[x]=oldf;
    ch[old][wh]=ch[x][wh^1];
    if (ch[old][wh]) f[ch[old][wh]]=old;
    ch[x][wh^1]=old;
    f[old]=x;
}
void splay(int x)
{
    int top=0;stack[++top]=x;
    for (int i=x;!isroot(i);i=f[i]) stack[++top]=f[i];
    for (int i=top;i>=1;--i) pushdown(stack[i]);

    for (int fa;!isroot(x);rotate(x))
        if (!isroot(fa=f[x]))
            rotate((get(x)==get(fa))?fa:x);
}
void access(int x)
{
    int t=0;
    for (;x;t=x,x=f[x])
    {
        splay(x);
        ch[x][1]=t;
    }
}
void reverse(int x)
{
    access(x);
    splay(x);
    rev[x]^=1;
}
void link(int x,int y)
{
    reverse(x);
    f[x]=y;
}
void cut(int x,int y)
{
    reverse(x);
    access(y);
    splay(y);
    f[x]=ch[y][0]=0;
}
int find(int x)
{
    access(x);
    splay(x);
    while (ch[x][0]) x=ch[x][0];
    return x;
}
int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=m;++i)
    {
        scanf("%s",opt);
        int x,y;scanf("%d%d",&x,&y);
        if (opt[0]=='C')
            link(x,y);
        else if (opt[0]=='D')
            cut(x,y);
        else
        {
            if (find(x)==find(y)) puts("Yes");
            else puts("No");
        }
    }
}

静态主席树

// POJ 2104 K-th Number
#include
#include
#include
#include
using namespace std;

const int max_n=1e5+5;

int n,m,x,y,z,sz,ans;
int val[max_n],p[max_n],num[max_n],root[max_n];
int sum[max_n*20],ls[max_n*20],rs[max_n*20];

inline int cmp(int a,int b){return val[a]inline void build(int &now,int l,int r,int x){
    int mid=(l+r)>>1;
    sum[++sz]=sum[now]; ls[sz]=ls[now]; rs[sz]=rs[now];
    now=sz;
    ++sum[now];
    if (l==r) return;
    if (x<=mid) build(ls[now],l,mid,x);
    else build(rs[now],mid+1,r,x);
}
inline int query(int i,int j,int l,int r,int k){
    int mid=(l+r)>>1;
    if (l==r) return l;
    int t=sum[ls[j]]-sum[ls[i]];
    if (t>=k) return query(ls[i],ls[j],l,mid,k);
    else return query(rs[i],rs[j],mid+1,r,k-t); 
}
int main(){
    scanf("%d%d",&n,&m);
    for (int i=1;i<=n;++i) scanf("%d",&val[i]),p[i]=i;
    sort(p+1,p+n+1,cmp);
    for (int i=1;i<=n;++i)
      num[p[i]]=i;

    sz=0; root[0]=0;
    for (int i=1;i<=n;++i){
        root[i]=root[i-1];
        build(root[i],1,n,num[i]);
    }
    for (int i=1;i<=m;++i){
        scanf("%d%d%d",&x,&y,&z);
        ans=query(root[x-1],root[y],1,n,z);
        printf("%d\n",val[p[ans]]);
    }
}

动态主席树

// BZOJ 1901 Dynamic Rankings
#include
#include
#include
#include
using namespace std;

const int max_n=1e4+5;
const int max_m=1e4+5;
const int max_log=30;
const int max_tree=3e6+5;

char opt[10];
int n,m,a,b,t,sz,N,cnt;
int val[max_n],A[max_m],B[max_m],K[max_m],flag[max_m];
int num[max_n*2],hash[max_n*2],root[max_n*2],L[max_log],R[max_log];
int sum[max_tree],ls[max_tree],rs[max_tree];

inline int find(int x){
    int l=1,r=N,mid;
    while (l<=r){
        mid=(l+r)>>1;
        if (hash[mid]1;
        else r=mid-1; 
    }
    return l;
}
inline void build(int last,int l,int r,int &now,int x,int v){
    int mid=(l+r)>>1;
    now=++sz;
    sum[now]=sum[last]+v; ls[now]=ls[last]; rs[now]=rs[last];
    if (l==r) return;
    if (x<=mid) build(ls[last],l,mid,ls[now],x,v);
    else build(rs[last],mid+1,r,rs[now],x,v);
}
inline int query(int l,int r,int k){
    int mid=(l+r)>>1;
    if (l==r) return l;
    int suml=0,sumr=0;
    for (int i=1;i<=a;++i) suml+=sum[ls[L[i]]];
    for (int i=1;i<=b;++i) sumr+=sum[ls[R[i]]];
    if (sumr-suml>=k){
        for (int i=1;i<=a;++i) L[i]=ls[L[i]];
        for (int i=1;i<=b;++i) R[i]=ls[R[i]];
        return query(l,mid,k);
    }
    else{
        for (int i=1;i<=a;++i) L[i]=rs[L[i]];
        for (int i=1;i<=b;++i) R[i]=rs[R[i]];
        return query(mid+1,r,k-(sumr-suml));
    }
}

int main(){
    scanf("%d%d",&n,&m);
    for (int i=1;i<=n;++i) scanf("%d",&val[i]),num[++cnt]=val[i];
    for (int i=1;i<=m;++i){
        scanf("%s",opt);
        if (opt[0]=='C'){
            scanf("%d%d",&A[i],&B[i]);
            num[++cnt]=B[i];
        }
        else{
            flag[i]=1;
            scanf("%d%d%d",&A[i],&B[i],&K[i]);
        }
    }
    sort(num+1,num+cnt+1);
    hash[++N]=num[1];
    for (int i=2;i<=cnt;++i)
      if (num[i]!=num[i-1]) hash[++N]=num[i];

    for (int i=1;i<=n;++i){
        t=find(val[i]);
        for (int j=i;j<=n;j+=j&(-j))
          build(root[j],1,N,root[j],t,1);
    }
    for (int i=1;i<=m;++i)
      if (flag[i]){
        a=0,b=0,A[i]--;
        for (int j=A[i];j>=1;j-=j&(-j)) L[++a]=root[j];
        for (int j=B[i];j>=1;j-=j&(-j)) R[++b]=root[j];
        printf("%d\n",hash[query(1,N,K[i])]);
      }
      else{
        t=find(val[A[i]]);
        for (int j=A[i];j<=n;j+=j&(-j)) build(root[j],1,N,root[j],t,-1);
        val[A[i]]=B[i];
        t=find(val[A[i]]);
        for (int j=A[i];j<=n;j+=j&(-j)) build(root[j],1,N,root[j],t,1);
      }
}

算法

高精度

#include
#include
#include
using namespace std;
#define N 505

char s1[N],s2[N];
int a[N],b[N];

void jia(int *a,int *b)
{
    a[0]=max(a[0],b[0]);
    for (int i=1;i<=a[0];++i) a[i]+=b[i];
    for (int i=1;i<=a[0];++i)
    {
        a[i+1]+=a[i]/10;
        a[i]%=10;
    }
    if (a[a[0]+1]) a[0]++;
}
int main()
{
    scanf("%s",s1);scanf("%s",s2);
    a[0]=strlen(s1);b[0]=strlen(s2);
    for (int i=0;i0];++i) a[i+1]=s1[a[0]-i-1]-'0';
    for (int i=0;i0];++i) b[i+1]=s2[b[0]-i-1]-'0';
    jia(a,b);
    for (int i=a[0];i>=1;--i) printf("%d",a[i]);
    putchar('\n');
}

#include
#include
#include
using namespace std;
#define N 505

char s1[N],s2[N];
int a[N],b[N];
bool flag;

bool compare(int *a,int *b)
{
    if (a[0]0]) return 1;
    else if (a[0]>b[0]) return 0;
    for (int i=a[0];i>=1;--i)
    {
        if (a[i]return 1;
        else if (b[i]return 0; 
    }
    return 0;
}
void jian(int *a,int *b)
{
    for (int i=1;i<=a[0];++i)
    {
        if (a[i]1],a[i]+=10;
        a[i]-=b[i];
    }
    while (a[0]>1&&!a[a[0]]) --a[0];
}
int main()
{
    scanf("%s",s1);scanf("%s",s2);
    a[0]=strlen(s1);b[0]=strlen(s2);
    for (int i=0;i0];++i) a[i+1]=s1[a[0]-i-1]-'0';
    for (int i=0;i0];++i) b[i+1]=s2[b[0]-i-1]-'0';
    flag=compare(a,b);
    if (flag)
        for (int i=0;i<=max(a[0],b[0]);++i) swap(a[i],b[i]);
    jian(a,b);
    if (flag) putchar('-');
    for (int i=a[0];i>=1;--i) printf("%d",a[i]);
    putchar('\n');
}

#include
#include
#include
using namespace std;
#define N 1005

char s1[N],s2[N];
int a[N],b[N],ans[N];

void cheng(int *a,int *b)
{
    ans[0]=a[0]+b[0]-1;
    for (int i=1;i<=a[0];++i)
    for (int j=1;j<=b[0];++j)
    ans[i+j-1]+=a[i]*b[j];
    for (int i=1;i<=ans[0];++i)
    {
        ans[i+1]+=ans[i]/10;
        ans[i]%=10;
    }
    while (ans[ans[0]+1])
    {
        ans[0]++;
        ans[ans[0]+1]=ans[ans[0]]/10;
        ans[ans[0]]%=10;
    }
}
int main()
{
    scanf("%s",s1);scanf("%s",s2);
    a[0]=strlen(s1);b[0]=strlen(s2);
    for (int i=0;i0];++i) a[i+1]=s1[a[0]-i-1]-'0';
    for (int i=0;i0];++i) b[i+1]=s2[b[0]-i-1]-'0';
    cheng(a,b);
    for (int i=ans[0];i>=1;--i) printf("%d",ans[i]);
    putchar('\n');
}

#include
#include
#include
using namespace std;
#define N 1005

char s1[N],s2[N];
int a[N],b[N],c[N],tmp[N];

void copy(int *a,int *b,int loc)
{
    for (int i=1;i<=a[0];++i) b[i+loc-1]=a[i];
    b[0]=a[0]+loc-1;
}
int compare(int *a,int *b)
{
    if (a[0]>b[0]) return 1;
    if (a[0]0]) return -1;
    for (int i=a[0];i>=1;--i)
    {
        if (a[i]>b[i]) return 1;
        else if (a[i]return -1;
    }
    return 0;
}
void jian(int *a,int *b)
{
    int flag=compare(a,b);
    if (flag==0)
    {
        a[0]=1,a[1]=0;
        return;
    }
    if (flag==1)
    {
        for (int i=1;i<=a[0];++i)
        {
            if (a[i]1],a[i]+=10;
            a[i]-=b[i];
        }
        while (a[0]>1&&!a[a[0]]) --a[0];
    }
}
void chu(int *a,int *b,int *c)
{
    c[0]=a[0]-b[0]+1;
    for (int i=c[0];i>=1;--i)
    {
        memset(tmp,0,sizeof(tmp));
        copy(b,tmp,i);
        while (compare(a,tmp)>=0) c[i]++,jian(a,tmp);
    }
    while (c[0]>1&&!c[c[0]]) --c[0];
}

int main()
{
    scanf("%s",s1);scanf("%s",s2);
    a[0]=strlen(s1);b[0]=strlen(s2);
    for (int i=0;i0];++i) a[i+1]=s1[a[0]-i-1]-'0';
    for (int i=0;i0];++i) b[i+1]=s2[b[0]-i-1]-'0';
    chu(a,b,c);
    for (int i=c[0];i>=1;--i) putchar(c[i]+'0');putchar('\n');
}

归并排序求逆序对

#include
#include
#include
using namespace std;
#define LL long long
#define N 100005

int n,k;LL rev;
int a[N],s[N],b[N];

void mergesort(int l,int r)
{
    int mid=(l+r)>>1;
    if (l==r) return;
    mergesort(l,mid);
    mergesort(mid+1,r);
    int i=l,j=mid+1,now=l;
    while (i<=mid&&j<=r)
    {
        if (s[i]else b[now++]=s[j++],rev+=(LL)mid-i+1;
    }
    while (i<=mid) b[now++]=s[i++];
    while (j<=r) b[now++]=s[j++];
    for (;l<=r;++l) s[l]=b[l];
}
int main()
{
    scanf("%d%d",&n,&k);
    for (int i=1;i<=n;++i) scanf("%d",&a[i]);
    for (int i=1;i<=n;++i)
    {
        s[i]=s[i-1]+a[i]-k;
        if (s[i]<=0) ++rev;
    }
    mergesort(1,n);
    printf("%lld\n",(LL)(n+1)*n/2-rev);
}

网络流

Dinic

// codevs 1993
#include
#include
#include
#include
#include
#include
using namespace std;
#define N 10005
#define inf 1000000000

int n,m,maxflow,x,y,z;
int tot,point[N],nxt[N],v[N],remain[N];
int cur[N],deep[N],last[N],num[N];
queue <int> q;

void addedge(int x,int y,int cap)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y; remain[tot]=cap;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x; remain[tot]=0;
}
bool bfs(int s,int t)
{
    for (int i=1;i<=t;++i) deep[i]=t;
    deep[s]=0;
    for (int i=1;i<=t;++i) cur[i]=point[i];
    q.push(s);
    while (!q.empty())
    {
        int now=q.front();q.pop();
        for (int i=point[now];i!=-1;i=nxt[i])
            if (deep[v[i]]==t&&remain[i])
            {
                deep[v[i]]=deep[now]+1;
                q.push(v[i]);
            }
    }
    return deep[t]int dfs(int now,int t,int limit)
{
    if (now==t||!limit) return limit;
    int flow=0,f;
    for (int i=cur[now];i!=-1;i=nxt[i])
    {
        cur[now]=i;
        if (deep[v[i]]==deep[now]+1&&(f=dfs(v[i],t,min(remain[i],limit))))
        {
            flow+=f;
            limit-=f;
            remain[i]-=f;
            remain[i^1]+=f;
            if (!limit) break;
        }
    }
    return flow;
}
void dinic(int s,int t)
{
    while (bfs(s,t))
        maxflow+=dfs(s,t,inf);
}
int main()
{
    tot=-1;
    memset(point,-1,sizeof(point));
    memset(nxt,-1,sizeof(nxt));
    scanf("%d%d",&m,&n);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d%d",&x,&y,&z);
        addedge(x,y,z);
    }
    dinic(1,n);
    printf("%d\n",maxflow);
}

Isap

// codevs 1993
#include
#include
#include
#include
#include
#include
using namespace std;
#define N 10005
#define inf 1000000000

int n,m,maxflow,x,y,z;
int tot,point[N],nxt[N],v[N],remain[N];
int cur[N],deep[N],last[N],num[N];
queue <int> q;

void addedge(int x,int y,int cap)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y; remain[tot]=cap;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x; remain[tot]=0;
}
void bfs(int t)
{
    for (int i=1;i<=t;++i) deep[i]=t;
    deep[t]=0;
    for (int i=1;i<=t;++i) cur[i]=point[i];
    q.push(t);
    while (!q.empty())
    {
        int now=q.front();q.pop();
        for (int i=point[now];i!=-1;i=nxt[i])
            if (deep[v[i]]==t&&remain[i^1])
            {
                deep[v[i]]=deep[now]+1;
                q.push(v[i]);
            }
    }
}
int addflow(int s,int t)
{
    int now=t,ans=inf;
    while (now!=s)
    {
        ans=min(ans,remain[last[now]]);
        now=v[last[now]^1];
    }
    now=t;
    while (now!=s)
    {
        remain[last[now]]-=ans;
        remain[last[now]^1]+=ans;
        now=v[last[now]^1];
    }
    return ans;
}
void isap(int s,int t)
{
    bfs(t);
    for (int i=1;i<=t;++i) ++num[deep[i]];

    int now=s;
    while (deep[s]if (now==t)
        {
            maxflow+=addflow(s,t);
            now=s;
        }
        bool has_find=0;
        for (int i=cur[now];i!=-1;i=nxt[i])
        {
            cur[now]=i;
            if (deep[now]==deep[v[i]]+1&&remain[i])
            {
                has_find=1;
                last[v[i]]=i;
                now=v[i];
                break;
            }
        }
        if (!has_find)
        {
            int minn=t-1;
            for (int i=point[now];i!=-1;i=nxt[i])
                if (remain[i]) minn=min(minn,deep[v[i]]);
            if (!(--num[deep[now]])) break;
            ++num[deep[now]=minn+1];
            cur[now]=point[now];
            if (now!=s) now=v[last[now]^1];
        }
    }
}
int main()
{
    tot=-1;
    memset(point,-1,sizeof(point));
    memset(nxt,-1,sizeof(nxt));
    scanf("%d%d",&m,&n);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d%d",&x,&y,&z);
        addedge(x,y,z);
    }
    isap(1,n);
    printf("%d\n",maxflow);
}

最小费用最大流

// codevs1237 餐巾计划问题
#include
#include
#include
#include
using namespace std;

const int max_N=1005;
const int max_Max=max_N*2+2;
const int max_m=max_Max*20;
const int max_e=max_m*2;
const int inf=1e9;

int N,p,m,f,n,s,Max,maxflow,mincost,r[max_N];
int point[max_Max],next[max_e],v[max_e],remain[max_e],c[max_e],tot;
int last[max_Max],dis[max_Max];
bool vis[max_Max];
queue <int> q;

inline void addedge(int x,int y,int cap,int z){
    ++tot; next[tot]=point[x]; point[x]=tot; v[tot]=y; remain[tot]=cap; c[tot]=z;
    ++tot; next[tot]=point[y]; point[y]=tot; v[tot]=x; remain[tot]=0; c[tot]=-z;
}

inline int addflow(int s,int t){
    int ans=inf,now=t;
    while (now!=s){
        ans=min(ans,remain[last[now]]);
        now=v[last[now]^1];
    }

    now=t;
    while (now!=s){
        remain[last[now]]-=ans;
        remain[last[now]^1]+=ans;
        now=v[last[now]^1];
    }

    return ans;
}

inline bool bfs(int s,int t){
    memset(dis,0x7f,sizeof(dis));
    memset(vis,0,sizeof(vis));
    dis[s]=0;
    vis[s]=true;
    while (!q.empty()) q.pop();
    q.push(s);

    while (!q.empty()){
        int now=q.front(); q.pop();
        vis[now]=false;
        for (int i=point[now];i!=-1;i=next[i])
          if (dis[v[i]]>dis[now]+c[i]&&remain[i]){
            dis[v[i]]=dis[now]+c[i];
            last[v[i]]=i;
            if (!vis[v[i]]){
                vis[v[i]]=true;
                q.push(v[i]);
            }
          }
    }

    if (dis[t]>inf) return false;
    int flow=addflow(s,t);
    maxflow+=flow;
    mincost+=flow*dis[t];
    return true;
}

inline void major(int s,int t){
    maxflow=0; mincost=0;
    while (bfs(s,t));
}

int main(){
    tot=-1;
    memset(point,-1,sizeof(point));
    memset(next,-1,sizeof(next));

    scanf("%d%d%d%d%d%d",&N,&p,&m,&f,&n,&s);
    for (int i=1;i<=N;++i)
      scanf("%d",&r[i]);
    Max=N*2+2;
    for (int i=1;i<=N;++i)
      addedge(1,1+i,r[i],0);
    for (int i=1;i<=N;++i)
      addedge(1+N+i,Max,r[i],0);
    for (int i=1;i<=N;++i)
      addedge(1,1+N+i,inf,p);
    for (int i=1;i1+i,1+i+1,inf,0);
    for (int i=1;i<=N;++i){
        if (i+m<=N)
          addedge(1+i,1+N+i+m,inf,f);
        if (i+n<=N)
          addedge(1+i,1+N+i+n,inf,s);
    }

    major(1,Max);
    printf("%d\n",mincost);
}

二分图判断、最大匹配数

// hdu 2444
#include
#include
#include
using namespace std;
#define N 40005

int n,m,x,y,ans;
bool flag;
int tot,point[N],nxt[N*2],v[N*2];
int belong[N],vis[N],col[N];

void clear()
{
    ans=0;
    tot=0;memset(point,0,sizeof(point));memset(v,0,sizeof(v));memset(nxt,0,sizeof(nxt));
    memset(belong,0,sizeof(belong));memset(vis,0,sizeof(vis));memset(col,-1,sizeof(col));
}
void add(int x,int y)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x;
}
void dfs(int x,int fa)
{
    for (int i=point[x];i&&flag;i=nxt[i])
        if (v[i]!=fa)
        {
            if (col[v[i]]==-1)
            {
                col[v[i]]=col[x]^1;
                dfs(v[i],x);
            }
            else
            {
                if (col[v[i]]!=(col[x]^1)) flag=false;
                return;
            }
        }
}
bool find(int x,int k)
{
    for (int i=point[x];i;i=nxt[i])
        if (vis[v[i]]!=k)
        {
            vis[v[i]]=k;
            if (!belong[v[i]]||find(belong[v[i]],k))
            {
                belong[v[i]]=x;
                return true;
            }
        }
    return false;
}
int main()
{
    while (~scanf("%d%d",&n,&m))
    {
        clear();
        if (n==1)
        {
            puts("No");
            continue;
        }
        for (int i=1;i<=m;++i)
        {
            scanf("%d%d",&x,&y);
            add(x,y);
        }
        flag=true;
        col[1]=0;dfs(1,0);
        if (!flag)
        {
            puts("No");
            continue;
        }
        for (int i=1;i<=n;++i)
            if (find(i,i)) ans++;
        printf("%d\n",ans>>1);
    }
}

Dijkstra 堆优化

// poj 2387
#include
#include
#include
#include
#include
using namespace std;
#define INF 2147483647
#define N 2005

int n,m,x,y,z,dis[N];
int tot,nxt[N*2],point[N],v[N*2],c[N*2];
bool vis[N*2];
struct hp
{
    int x,val;
    bool operator < (const hp &a) const
    {
        return a.val q;

inline void addedge(int x,int y,int z)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y; c[tot]=z;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x; c[tot]=z;
}
inline void dijkstra()
{
    memset(dis,127,sizeof(dis));dis[1]=0;
    q.push((hp){1,0});
    while (!q.empty())
    {
        int now=q.top().x;q.pop();
        if (vis[now]) continue; vis[now]=true;
        for (int i=point[now];i;i=nxt[i])
        if (!vis[v[i]]&&dis[now]+c[i]int main()
{
    scanf("%d%d",&m,&n);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d%d",&x,&y,&z);
        addedge(x,y,z);
    }
    dijkstra();
    printf("%d\n",dis[n]);
}

字符串

Kmp

// poj 3461 
#include
#include
#include
using namespace std;
const int max_W=10005;
const int max_s=1000005;
char W[max_W],s[max_s];
int T[max_W];
int t,len_W,len_s,ans;

inline void calc_T()
{
    T[0]=-1;
    int j;
for (int i=0;iwhile (j!=-1&&W[j]!=W[i])
          j=T[j];
        T[i+1]=++j;
    }
}
inline void calc_ans()
{
    int j=0;
for (int i=0;iwhile (j!=-1&&W[j]!=s[i]) 
          j=T[j];
        j++;
        if (j==len_W)
        {
            ans++;
            j=T[j];
        }
    }
}
int main(){
    scanf("%d\n",&t);
    while (t--){
        gets(W);
        gets(s);        
        len_W=strlen(W);
        len_s=strlen(s);
        memset(T,0,sizeof(T));
        calc_T();
        ans=0;
        calc_ans();
        printf("%d\n",ans);
    }
}

AC自动机

// hdu 2222
#include
#include
#include
#include
using namespace std;
#define N 500005

char s[N*2];
int T,n,sz,ans;
int ch[N][30],is_end[N],fail[N];
bool vis[N];
queue <int> q;

void clear()
{
    n=sz=ans=0;
    memset(ch,0,sizeof(ch));memset(is_end,0,sizeof(is_end));
    memset(fail,0,sizeof(fail));memset(vis,0,sizeof(vis));
}
void insert()
{
    int len=strlen(s),now=0;
    for (int i=0;iint x=s[i]-'a';
        if (!ch[now][x]) ch[now][x]=++sz;
        now=ch[now][x];
    }
    ++is_end[now];
}
void make_fail()
{
    while (!q.empty()) q.pop();
    for (int i=0;i<26;++i)
        if (ch[0][i]) q.push(ch[0][i]);
    while (!q.empty())
    {
        int now=q.front();q.pop();
        for (int i=0;i<26;++i)
        {
            if (!ch[now][i])
            {
                ch[now][i]=ch[fail[now]][i];
                continue;
            }
            fail[ch[now][i]]=ch[fail[now]][i];
            q.push(ch[now][i]);
        }
    }
}
void ac()
{
    int len=strlen(s),now=0;
    for (int i=0;i1;
        int x=s[i]-'a';
        int y=ch[now][x];
        while (y&&!vis[y])
        {
            vis[y]=1;
            ans+=is_end[y];
            y=fail[y];
        }
        now=ch[now][x];
    }
}
int main()
{
    scanf("%d",&T);
    while (T--)
    {
        clear();
        scanf("%d\n",&n);
        for (int i=1;i<=n;++i)
        {
            gets(s);
            insert();
        }
        gets(s);
        make_fail();
        ac();
        printf("%d\n",ans);
    }
}

后缀数组

#include
#include
#include
using namespace std;

const int max_n=2e5+5;

int n,m=300,sa[max_n],c[max_n],x[max_n],y[max_n],rank[max_n],height[max_n];
char s[max_n];

inline void build_sa(){
    for (int i=0;i0;
    for (int i=0;ifor (int i=1;i1];
    for (int i=n-1;i>=0;--i) sa[--c[x[i]]]=i;

    for (int k=1;k<=n;k<<=1){
        int p=0;
        for (int i=n-k;ifor (int i=0;iif (sa[i]>=k) y[p++]=sa[i]-k;

        for (int i=0;i0;
        for (int i=0;ifor (int i=1;i1];
        for (int i=n-1;i>=0;--i) sa[--c[x[y[i]]]]=y[i];

        swap(x,y);
        p=1; x[sa[0]]=0;
        for (int i=1;i1]]==y[sa[i]]&&
                              ((sa[i-1]+k>=n?-1:y[sa[i-1]+k])==(sa[i]+k>=n?-1:y[sa[i]+k]))?p-1:p++;
        if (p>n) break;
        m=p;
    }
}

inline void build_lcp(){
    for (int i=0;i0]=0;
    int k=0;
    for (int i=0;iif (!rank[i]) continue;
        if (k) --k;
        int j=sa[rank[i]-1];
        while (i+kint main(){
    gets(s);
    n=strlen(s);
    build_sa();
    build_lcp();
    for (int i=0;iprintf("%d%c",sa[i]+1," \n"[i==n-1]);
    for (int i=0;iprintf("%d%c",height[i]," \n"[i==n-1]);
}

Tarjan

Tarjan(强连通分量)/spfa

// BZOJ 1179
#include
#include
#include
#include
using namespace std;
#define N 500005

int n,m,s,p,dfs_clock,scc,ans;
struct hp{int x,y;}e[N];
int val[N],bar[N],dfn[N],low[N],stack[N],tmp,belong[N],size[N],dis[N];
int tot,point[N],nxt[N],v[N];
bool vis[N];
queue <int> q;

void add(int x,int y)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y;
}
void tarjan(int x)
{
    dfn[x]=low[x]=++dfs_clock;vis[x]=true;stack[++tmp]=x;
    for (int i=point[x];i;i=nxt[i])
        if (!dfn[v[i]])
        {
            tarjan(v[i]);
            low[x]=min(low[x],low[v[i]]);
        }
        else if (vis[v[i]])
            low[x]=min(low[x],dfn[v[i]]);
    if (dfn[x]==low[x])
    {
        ++scc;int now=0;
        while (now!=x)
        {
            now=stack[tmp--];
            vis[now]=false;
            belong[now]=scc;
            size[scc]+=val[now];
        }
    }
}
void rebuild()
{
    tot=0;memset(point,0,sizeof(point));
    for (int i=1;i<=m;++i)
        if (belong[e[i].x]!=belong[e[i].y])
            add(belong[e[i].x],belong[e[i].y]);
}
void spfa()
{
    memset(vis,0,sizeof(vis));
    dis[belong[s]]=size[belong[s]];vis[belong[s]]=true;q.push(belong[s]);
    while (!q.empty())
    {
        int now=q.front();q.pop();
        vis[now]=false;
        for (int i=point[now];i;i=nxt[i])
            if (dis[v[i]]if (!vis[v[i]])
                {
                    vis[v[i]]=true;
                    q.push(v[i]);
                }
            }
    }
}
int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d",&e[i].x,&e[i].y);
        add(e[i].x,e[i].y);
    }
    for (int i=1;i<=n;++i) scanf("%d",&val[i]);
    scanf("%d%d",&s,&p);
    for (int i=1;i<=p;++i) scanf("%d",&bar[i]);

    for (int i=1;i<=n;++i)
        if (!dfn[i]) tarjan(i);
    rebuild();
    spfa();
    for (int i=1;i<=p;++i)
        ans=max(ans,dis[belong[bar[i]]]);
    printf("%d\n",ans);
}

Tarjan(双连通分量)

// POJ 3177
#include
#include
#include
using namespace std;
#define N 10005

int n,m,dfs_clock,dcc,ans;
int tot,point[N],nxt[N*2],v[N*2];
int dfn[N],low[N],stack[N],tmp,belong[N],du[N];
struct hp{int x,y;}e[N];
bool vis[N];

void add(int x,int y)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x;
}
void tarjan(int x,int fa)
{
    dfn[x]=low[x]=++dfs_clock;vis[x]=true;stack[++tmp]=x;
    bool flag=false;
    for (int i=point[x];i;i=nxt[i])
    {
        if (v[i]==fa&&!flag)
        {
            flag=true;
            continue;
        }
        if (!dfn[v[i]])
        {
            tarjan(v[i],x);
            low[x]=min(low[x],low[v[i]]);
        }
        else if (vis[v[i]]) low[x]=min(low[x],dfn[v[i]]);
    }
    if (dfn[x]==low[x])
    {
        dcc++;int now=0;
        while (now!=x)
        {
            now=stack[tmp--];
            belong[now]=dcc;
        }
    }
}
int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=m;++i)
    {
        scanf("%d%d",&e[i].x,&e[i].y);
        add(e[i].x,e[i].y);
    }
    for (int i=1;i<=n;++i)
        if (!dfn[i]) tarjan(i,0);
    for (int i=1;i<=m;++i)
        if (belong[e[i].x]!=belong[e[i].y])
            du[belong[e[i].x]]++,du[belong[e[i].y]]++;
    for (int i=1;i<=dcc;++i)
        if (du[i]==1) ans++;
    ans=(ans+1)>>1;
    printf("%d\n",ans);
}

Tarjan(求割点及去掉割点之后连通块数量)

// POJ 1523
#include
#include
#include
using namespace std;
#define N 500005

int n,m,x,y,dfs_clock,Case;
int tot,point[1005],nxt[N*2],v[N*2];
int dfn[1005],low[1005],ans[1005];
bool flag;

void clear()
{
    n=m=x=y=dfs_clock=tot=flag=0;
    memset(v,0,sizeof(v));memset(point,0,sizeof(point));memset(nxt,0,sizeof(nxt));
    memset(dfn,0,sizeof(dfn));memset(low,0,sizeof(low));memset(ans,0,sizeof(ans));
}
void add(int x,int y)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y;
    ++tot; nxt[tot]=point[y]; point[y]=tot; v[tot]=x;
}
void tarjan(int x)
{
    dfn[x]=low[x]=++dfs_clock;
    for (int i=point[x];i;i=nxt[i])
        if (!dfn[v[i]])
        {
            tarjan(v[i]);
            low[x]=min(low[x],low[v[i]]);
            if (dfn[x]<=low[v[i]]) ans[x]++;
        }
        else low[x]=min(low[x],dfn[v[i]]);
}
int main()
{
    while (1)
    {
        clear();
        m=0;
        while (1)
        {
            scanf("%d",&x);if (!x) break;
            scanf("%d",&y);m++;add(x,y);
            n=max(n,x);n=max(n,y);
        }
        if (!m) break;

        tarjan(1);
        printf("Network #%d\n",++Case);
        flag=false;
        for (int i=1;i<=n;++i)
            if (i==1&&ans[i]>1)
            {
                flag=true;
                printf("  SPF node %d leaves %d subnets\n",i,ans[i]);
            }
            else if (i!=1&&ans[i]+1>1)
            {
                flag=true;
                printf("  SPF node %d leaves %d subnets\n",i,ans[i]+1);
            }

        if (!flag) puts("  No SPF nodes");
        putchar('\n');
    }
}

悬线法

// BZOJ 3039
#include
#include
#include
using namespace std;
#define N 1005

int n,m,a[N][N],L[N][N],R[N][N],l[N][N],r[N][N],h[N][N],ans;

int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=n;++i)
        for (int j=1;j<=m;++j)
        {
            char ch=getchar();
            while (ch!='R'&&ch!='F') ch=getchar();
            if (ch=='R') a[i][j]=1;
        }
    for (int i=1;i<=n;++i)
    {
        int Max=0,Min=m+1;
        for (int j=1;j<=m;++j)
        {
            if (a[i][j]) Max=max(Max,j);
            L[i][j]=Max;
        }
        for (int j=m;j>=1;--j)
        {
            if (a[i][j]) Min=min(Min,j);
            R[i][j]=Min;
        }
    }
    for (int j=1;j<=m;++j) r[0][j]=m+1;
    for (int i=1;i<=n;++i)
        for (int j=1;j<=m;++j)
        {
            if (a[i][j])
            {
                h[i][j]=0;
                l[i][j]=0,r[i][j]=m+1;
            }
            else
            {
                h[i][j]=h[i-1][j]+1;
                l[i][j]=max(l[i-1][j],L[i][j]);
                r[i][j]=min(r[i-1][j],R[i][j]);
            }
        }
    for (int i=1;i<=n;++i)
        for (int j=1;j<=n;++j)
            ans=max(ans,(r[i][j]-l[i][j]-1)*h[i][j]);
    printf("%d\n",3*ans);
}

数学相关

快速幂

int fast_pow(int a,int p)
{
int ans=1;
    for (;p;p>>=1,a=(a*a)%Mod)
        if (p&1)
            ans=(ans*a)%Mod;
    return ans;
}

欧几里得算法

int gcd(int a,int b)
{
    if (!b) return a;
    else return gcd(b,a%b);
}

扩展欧几里得算法

// BZOJ 1477
#include
#include
#include
using namespace std;
#define LL long long

LL x,y,m,n,L,a,b,c;

inline LL gcd(LL a,LL b){
    if (!b) return a;
    else return gcd(b,a%b);
}

inline void exgcd(LL a,LL b,LL &x,LL &y){
    if (!b) x=1,y=0;
    else exgcd(b,a%b,y,x),y-=a/b*x;
}

int main(){
    scanf("%lld%lld%lld%lld%lld",&x,&y,&m,&n,&L);
    a=n-m; b=L; c=x-y;
    int t=gcd(a,b);
    if (c%t){
        printf("Impossible\n");
        return 0;
    }
    a/=t; b/=t; c/=t;
    x=y=0;
    exgcd(a,b,x,y);
    x=((c*x)%b+b)%b;
    if (!x) x+=b;
    printf("%lld\n",x);
}

欧拉筛(phi/mu/d/t/g/f)

inline void get(){
    phi[1]=1; mu[1]=1; d[1]=1; t[1]=1; f[1]=1;
for (LL i=2;i<=N;++i)
{
        if (!p[i])
{
            phi[i]=i-1; mu[i]=-1; d[i]=2; t[i]=1; f[i]=(i*i+1)%m; g[i]=1;
            prime[++prime[0]]=i;
        }
        for (LL j=1;j<=prime[0]&&i*prime[j]<=N;++j)
{
            p[i*prime[j]]=1;
            if (i%prime[j]==0)
{
                phi[i*prime[j]]=phi[i]*prime[j];
                mu[i*prime[j]]=0;
                t[i*prime[j]]=t[i]+1;
                d[i*prime[j]]=d[i]/(t[i]+1)*(t[i*prime[j]]+1);
                g[i*prime[j]]=g[i];
                f[i*prime[j]]=f[i]*prime[j]*prime[j]+f[g[i]];
                break;
            }
            else
{
                phi[i*prime[j]]=phi[i]*(prime[j]-1);
                mu[i*prime[j]]=-mu[i];
                d[i*prime[j]]=d[i]*2;
                t[i*prime[j]]=1;
                g[i*prime[j]]=i;
                f[i*prime[j]]=f[i]*prime[j]*prime[j]+f[i];
            }
        }
    }
}

根n求phi

inline LL phi(LL x){
    LL ans=x;
    for (LL i=2;i*i<=x;++i)
      if (x%i==0){
        ans=ans*(i-1)/i;
        while (x%i==0) x/=i;
      }
    if (x>1) ans=ans*(x-1)/x;
    return ans;
}

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