2019 Xuzhou Online Contest Problem I Query

很脑残的写了主席树,其实树状数组就能解决

#include
using namespace std;
const int N=2e5+10;
inline void read(int &x){char ch;bool ok;
for(ok=0,ch=getchar();!isdigit(ch);ch=getchar()) if(ch=='-') ok=1;
for(x=0;isdigit(ch);x=x*10+ch-'0',ch=getchar());if(ok) x=-x;}
int A[N],B[N];
struct HisTree{
    int l,r,sum;
}T[N*110];
int R[N],cnt;
void build(int l,int r,int &x,int y,int pos,int val){
    T[++cnt]=T[y],T[cnt].sum+=val,x=cnt;
    if(l==r)return;
    int mid=(l+r)/2;
    if(pos<=mid)build(l,mid,T[x].l,T[y].l,pos,val);
    else build(mid+1,r,T[x].r,T[y].r,pos,val);
}
int ask(int l,int r,int x,int y,int L,int R){
    if(l>=L&&r<=R)return T[y].sum-T[x].sum;
    int mid=(r+l)/2;int val=0;
    if(L<=mid)val+=ask(l,mid,T[x].l,T[y].l,L,R);
    if(R>mid)val+=ask(mid+1,r,T[x].r,T[y].r,L,R);
    return val;
}
int main(){
    int n,m;cin>>n>>m;
    for(int i=1;i<=n;++i)read(A[i]),B[A[i]]=i;
    for(int i=1;i<=n;++i){
        build(1,n,R[i],R[i-1],i,1ll*0);
        for(int j=1;j*j<=A[i];++j){
            if(A[i]%j==0){
                int tmp;
                if(B[j]

 

你可能感兴趣的:(数据结构)