Android之获取Android唯一ID

//获得独一无二的Psuedo ID
    private static String getUniquePsuedoID() {
        String serial = null;
        String m_szDevIDShort = "35" +
                Build.BOARD.length() % 10 + Build.BRAND.length() % 10 +

                Build.CPU_ABI.length() % 10 + Build.DEVICE.length() % 10 +

                Build.DISPLAY.length() % 10 + Build.HOST.length() % 10 +

                Build.ID.length() % 10 + Build.MANUFACTURER.length() % 10 +

                Build.MODEL.length() % 10 + Build.PRODUCT.length() % 10 +

                Build.TAGS.length() % 10 + Build.TYPE.length() % 10 +

                Build.USER.length() % 10; //13 位

        try {
            serial = android.os.Build.class.getField("SERIAL").get(null).toString();
            //API>=9 使用serial号
            return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
        } catch (Exception exception) {
            //serial需要一个初始化
            serial = "serial"; // 随便一个初始化
        }
        //使用硬件信息拼凑出来的15位号码
        return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
    }

结果：00000000-7dc2-f1aa-ffff-fffff6f7ee5d