Python 解码Base64 得到码流格式文本

# coding:utf8
import base64


def BaseToFlow():
    while True:
        str = input("Please input src: ")
        flag = input("Please input Decode - 1 or Encode - 2: ")
        if str == "":
            str = "ApIAGBcEAAAEBO6x3nLykEEhjWMX1wHs"
        if flag == "":
            flag = "1"
        if flag == "1":
            print("Decoding ...")
            dst = base64.b64decode(str)
            # print(type(dst))
            # 
            # print(dst)
            # b'\x02\x92\x00\x18\x17\x04\x00\x00\x04\x04\xee\xb1\xder\xf2\x90A!\x8dc\x17\xd7\x01\xec'
            # print(dst.hex()) --去掉\0x前缀 得到一个字符串
            # 02920018170400000404eeb1de72f29041218d6317d701ec
            HexFormat(dst.hex())
        elif flag == "2":
            print("Encoding ...")
            dst = base64.b64encode(str)
            print(dst)


def HexFormat(str):
    """
    :param str: 16进制连续字符串
    :return:  码流格式的16进制串
    """
    i = 1
    str2 = ""
    while (i <= len(str)):
        str2 = str2 + str[i - 1] + str[i] + " "
        if (i + 1) %16 == 0 and (i + 1) % 32 != 0:
            str2 = str2 + " "
        elif (i + 1) %32 == 0:
            str2 = str2 + "\n"
        i = i + 2


if __name__ == '__main__':
    BaseToFlow()

结果：

Please input src: 
Please input Decode - 1 or Encode - 2: 
Decoding ...
02 92 00 18 17 04 00 00  04 04 ee b1 de 72 f2 90 
41 21 8d 63 17 d7 01 ec