leetcode two sums 比较傻x的实现方式

装逼了 用的二叉搜索树 效率低到爆

package main

import "fmt"

func main() {
    var nums = []int{217,231,523,52,547,243,648,509,415,149,689,710,265,187,370,56,977,182,400,329,471,805,955,989,255,766,38,566,79,843,295,229,988,108,781,619,704,542,335,307,359,907,727,959,161,699,123,650,147,459,657,188,304,268,405,685,620,721,351,570,899,60,388,771,24,659,425,440,508,373,32,645,409,272,356,175,533,740,370,152,34,510,745,251,227,494,258,527,817,773,178,194,860,387,627,851,449,736,15,212,529,950,316,28,65,484,968,63,4,643,795,669,203,677,139,636,289,555,430,849,150,493,301,377,240,873,965,441,230,349,447,470}
    res := twoSum(nums,718)
    fmt.Println(res)
}

type Node struct {
    Key []int
    Value int
    Left *Node
    Right *Node
}
var Head1 *Node = nil

func twoSum(nums []int, target int) []int {


    var res []int
    lens := len(nums)

    for i:=0;i head.Value{
        return get(head.Right,value)
    }else if value < head.Value{
        return get(head.Left,value)
    }else{
        return head,0
    }
}

func put(head *Node,key int,value int) *Node{

    if head == nil{
        var node = new(Node)
        node.Key = append(node.Key,key)
        node.Value = value
        if key == 0{
            Head1 = node
        }
        return node
    }

    if value < head.Value{
        head.Left = put(head.Left,key,value)
        return head
    }else if value > head.Value{
        head.Right = put(head.Right,key,value)
        return head
    }else{
        head.Key = append(head.Key,key)
        return head
    }
}

下面是golang自带map实现（大部分golang方法）

func twoSum(nums []int, target int) []int {

    var res []int
    var mp = make(map[int]int)
    for k,v := range nums{
        mp[v] = k
    }
    for k,v := range nums{
        if kk,ok := mp[target-v];ok && k != kk{
            res = append(res,k,kk)
            return res
        }
    }
    return res

}