iOS 简单地函数式编程

一 方法的实现

#import 

@interface RJBlockTool : NSObject
//计算
+ (RJBlockTool *)makeMethodCalculator:(CGFloat(^)(CGFloat result))block;
- (BOOL)isEqualResult:(BOOL (^)(CGFloat result))block;
@end
#import "RJBlockTool.h"
@interface RJBlockTool()
//1 计算的结果
@property(nonatomic,assign) CGFloat resultCalculator;
@end

@implementation RJBlockTool
+(RJBlockTool *)makeMethodCalculator:(CGFloat (^)(CGFloat))block{
    if (block) {
        RJBlockTool *tool = [[RJBlockTool alloc] init];
        tool.resultCalculator = block(tool.resultCalculator);
        return tool;
    }
    return nil;
}
-(BOOL)isEqualResult:(BOOL (^)(CGFloat))block{
    return block(self.resultCalculator);
}
@end

二 使用

NSLog(@"isEqualResult---%d",[[RJBlockTool makeMethodCalculator:^CGFloat(CGFloat result) {
        result += 100;result /= 10;return result;
    }] isEqualResult:^BOOL(CGFloat result) {
        return result==10;
    }]);
isEqualResult---1

你可能感兴趣的:(iOS 简单地函数式编程)