UI_USER_INTERFACE_IDIOM()

使用 UI_USER_INTERFACE_IDIOM()进行区分 (iOS3.2 >=) 无法区分iphone和ipod

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
       // 
    } else {
      //  
    }
 
区分目前UI_USER_INTERFACE_IDIOM()有2个返回值
UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad    

UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone    ```

 
使用 UIDevice.model 进行区分  ([ios](http://lib.csdn.net/base/ios) 2.0 >=)
 

NSString *deviceType = [UIDevice currentDevice].model;

if([deviceType isEqualToString:@"iPhone"]) {
    //iPhone
}
else if([deviceType isEqualToString:@"iPod touch"]) {
    //iPod Touch
}
else {
    //iPad
}

使用系统的一个函数sysctlbyname 来获取设备名称

• (NSString *) platformString
  {
  size_t size;
  sysctlbyname("hw.machine", NULL, &size, NULL, 0);
  char *machine = malloc(size);
  sysctlbyname("hw.machine", machine, &size, NULL, 0);
  NSString *platform = [NSString stringWithUTF8String:machine];
  free(machine);
  if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
  if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
  if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
  if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
  if ([platform isEqualToString:@"iPhone3,3"]) return @"Verizon iPhone 4";
  if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
  if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
  if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
  if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";
  if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
  if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
  if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2 (GSM)";
  if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
  if ([platform isEqualToString:@"i386"]) return @"Simulator";
  return @"";
  }```

转自文章