原生和es6复杂数组去重的方法

1、注意后面objArray和objArray1的输出.

2、追加了ES6的一个封装方法Array.from(new Set(oArray))，经过测试效果一致。

 

 

let oArray = [1,2,1,1,3,2,4,5,6,2,10];
    let user = {name:"xiaozhang"};
    let objArray=[1,2,3,2,3,user,user]
    let objArray1=[1,2,3,2,3,{name:"xiaoqiang"},{name:"xiaoqiang"}]
    function duplicate(origin){
        if(typeof origin != "object"){
            return origin;//如果不是引用类型就直接返回。
        }
        //调用对象原型链上面的tostring方法判断数据主体是对象还是数组
        let toString = Object.prototype.toString,
            obj_array = "[object Array]",
            target = (toString.call(origin) == obj_array ? [] : {});//判断当前源主体是对象还是数组并赋值
                 
        for(let prop in origin){
            if(target.indexOf(origin[prop]) == -1){
                target.push(origin[prop]);
            }
        }
        return target;
    }
    console.log(duplicate(oArray))                    //[1, 2, 3, 4, 5, 6, 10]
    console.log(duplicate(objArray))            //[1,2,3,{name:"xiaozhang"}]
    console.log(duplicate(objArray1))            //[1,2,3,{name:"xiaoqiang"},{name:"xiaoqiang"}]
    console.log(Array.from(new Set(oArray)))     //[1, 2, 3, 4, 5, 6, 10]
    console.log(Array.from(new Set(objArray)))    //[1,2,3,{name:"xiaozhang"}]
    console.log(Array.from(new Set(objArray1)))    //[1,2,3,{name:"xiaoqiang"},{name:"xiaoqiang"}]