1200. Stick 匹配相同长度筷子

1200. Stick

Constraints

Time Limit: 1 secs, Memory Limit: 32 MB

Description

 Anthony has collected a large amount of sticks for manufacturing chopsticks. In order to simplify his job, he wants to fetch two equal-length sticks for machining at a time. After checking it over, Anthony finds that it is always possible that only one stick is left at last, because of the odd number of sticks and some other unknown reasons. For example, Anthony may have three sticks with length 1, 2, and 1 respectively. He fetches the first and the third for machining, and leaves the second one at last. You task is to report the length of the last stick. 

Input

The input file will consist of several cases.   

Each case will be presented by an integer n (1<=n<=100, and n is odd) at first. Following that, n positive integers will be given, one in a line. These numbers indicate the length of the sticks collected by Anthony.   

The input is ended by n=0. 

Output

For each case, output an integer in a line, which is the length of the last stick. 

Sample Input

3

1

2

1

0

Sample Output

2

Problem Source

ZSUACM Team Member

#include 

using namespace std;

int main () {
	int n;
	int a[105] = {0};
	while (cin>>n && n) {
		int b;
		for (int i = 0; i < n; i++) {
			cin>>b;
			bool flag = false;
			for (int j = 0; j <= i; j++) {  //从头查找有没有跟新输入匹配的 如果有就把原来的设为0
				if (a[j] == b) {
					a[j] = 0;
					flag = true;
					break;
				}
			}
			if (flag == false)
				a[i] = b;
		}
		for (int i = 0; i < n; i++) { //把没匹配的输出
			if ( a[i]!= 0 )
				cout<