oracle学习笔记１: SQL核心

关系模型就是指二维表格模型,因而一个关系型数据库就是由二维表及其之间的联系组成的一个数据组织。当前主流的关系型数据库有Oracle、DB2、PostgreSQL、Microsoft SQL Server、Microsoft Access、MySQL、浪潮K-DB等。
实体关系模型（Entity-Relationship Model)，简称E-R Model是陈品山（Peter P.S Chen)博士于1976年提出的一套数据库的设计工具，他运用真实世界中事物与关系的观念，来解释数据库中的抽象的数据架构。实体关系模型利用图形的方式（实体-关系图（Entity-Relationship Diagram））来表示数据库的概念设计，有助于设计过程中的构思及沟通讨论。

执行命令的几种方式

select empno, deptno from scott.emp where ename='SMITH';

select empno, deptno from scott.emp where ename='SMITH'
    ;

SQL> select empno, deptno from scott.emp where ename='SMITH'
  2  /

SQL> select empno, deptno from scott.emp where ename='SMITH'
  2  
SQL> /

SQL> @E:\bjc2016\study\list_depts.sql
 
DEPTNO DNAME          LOC
------ -------------- -------------
    10 ACCOUNTING     NEW YORK
    20 RESEARCH       DALLAS
    30 SALES          CHICAGO
    40 OPERATIONS     BOSTON

list_depts.sql
select * from scott.dept;

创建数据库

connect system/0529;
-- 创建表空间：
-- 格式:  create tablespace 表间名 datafile '数据文件名' size 表空间大小;
create tablespace oe_tablespace datafile 'E:\bjc2016\study\demo\oe.dbf' size 200M;
--创建用户：
--格式:  create user  用户名 identified by 密码  default tablespace 表空间表;
--创建（新）用户：
--也可以不创建新用户，而仍然用以前的用户，如：继续利用scott用户
--create user username identified by password;
create user tomluo identified by tomluo default tablespace oe_tablespace;
--将空间分配给用户：
--alert user username default tablespace oe_tablespace;
--将名字为oe_tablespace的表空间分配给username 
--授权给新建的用户
--grant create session,create table,unlimited oe_tablespace to username;
grant connect,resource,dba to tomluo;  --表示把 connect,resource权限授予tomluo用户
grant connect,resource,dba to scott;  --表示把 connect,resource权限授予scott用户
--用户登录，登录之后创建表即可。
conn tomluo/tomluo;

建表并准备实验数据

--创建customers表
drop table customers;
create table customers(
  customer_id number,
  gender char(1),
  cust_firt_name varchar(20),
  cust_last_name varchar(20),
  accout_mgr_id number
);
--准备测试数据
delete from customers;
insert into customers VALUES(1,'F','lili','zhang',1);
insert into customers VALUES(2,'M','jack','chen',1);
insert into customers VALUES(3,'F','tom','luo',2);
insert into customers VALUES(4,'F','hanmeimei','wu',2);
insert into customers VALUES(5,'F','polly','li',2);
select * from customers;

--准备测试数据
drop table jobs;
create table jobs(
job_id number primary key,
job_name varchar(20) not null
);
insert into jobs values(1,'soccer');
insert into jobs values(2,'reporter');
insert into jobs values(3,'dirver');


drop table departments;
create table departments(
department_id number primary key,
department_name varchar(20) not null,
manager_id number
);

--准备测试数据
delete from departments;
insert into departments VALUES(90,'Executive',1);
insert into departments VALUES(89,'Dev',90);
insert into departments VALUES(88,'Sales',7);
insert into departments VALUES(60,'Design',7);
select * from departments;
--创建employees表
drop table employees;
create table employees(
  employee_id number not null primary key,
  gender char(1) not null ,
  first_name varchar(20) not null ,
  last_name varchar(20) not null ,
  salary number not null ,
  commission_pct number not null ,
  department_id number   references departments(department_id) on delete cascade not null,
  job_id number not null ，
　email varchar2(30) not null 
);
create index EMP_EMAIL_UK on employees(EMAIL);
create index emp_dept_id_idx on employees(department_id);
--create index EMP_DEPARTMENT_IX on employees(DEPARTMENT_ID);

delete from employees;
insert into employees VALUES(1,'F','dongge','xu',24500,0,90,1,'[email protected]');
insert into employees VALUES(2,'M','ali','wu',19000,0,90,1,'[email protected]');
insert into employees VALUES(3,'M','miss','want',27000,0,89,1,'[email protected]');
insert into employees VALUES(4,'F','Zhang','Honold',9000,0,60,1,'[email protected]');
insert into employees VALUES(5,'M','wang','Rrnst',6000,0,60,1,'[email protected]');
insert into employees VALUES(6,'M','Li','Austin',8000,0,60,2,'[email protected]');
insert into employees VALUES(103,'F','Liu','Babala',7800,0,60,2,'[email protected]');
insert into employees VALUES(104,'M','Han','Lorents',6000,0,60,2,'[email protected]');
insert into employees VALUES(105,'M','Li','Tao',8000,0,60,2,'[email protected]');
insert into employees VALUES(106,'F','Li','Yun',8000,0,88,2,'[email protected]');
insert into employees VALUES(107,'F','Polly','bird',8000,0,88,2,'[email protected]');
select * from employees;



--创建orders表
drop table orders;
create table orders(
  order_id number primary key,
  customer_id number，
  sales_rep_id number,
  order_total number
);
drop sequence seq;
create sequence seq;
--准备测试数据
delete from orders;
insert into orders VALUES(seq.nextval,1,4,10000);
insert into orders VALUES(seq.nextval,2,4,10000);
insert into orders VALUES(seq.nextval,2,4,10000);
insert into orders VALUES(seq.nextval,1,4,10000);
insert into orders VALUES(seq.nextval,1,4,10000);
insert into orders VALUES(seq.nextval,2,4,10000);
insert into orders VALUES(seq.nextval,2,4,10000);
insert into orders VALUES(seq.nextval,1,4,10000);
insert into orders VALUES(seq.nextval,1,4,10000);
insert into orders VALUES(seq.nextval,2,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,3,4,10000);
insert into orders VALUES(seq.nextval,4,4,10000);
insert into orders VALUES(seq.nextval,4,4,10000);
insert into orders VALUES(seq.nextval,5,4,10000);
insert into orders VALUES(seq.nextval,5,4,10000);
insert into orders VALUES(seq.nextval,5,5,10000);
insert into orders VALUES(seq.nextval,5,4,100);
insert into orders VALUES(seq.nextval,5,7,10800);
insert into orders VALUES(seq.nextval,5,8,1000);
SELECT * from orders;
commit;

５个核心的ＳＱＬ语句

select 语句

下订单超过４次的女顾客

--下订单超过４次的女顾客
select c.customer_id, count(o.order_id) as orders_ct
  from oe.customers c
  join oe.orders o
    on c.customer_id = o.customer_id
 where c.gender = 'F'
 group by c.customer_id
having count(o.order_id) > 4
 order by orders_ct, c.customer_id;

• from
  from 列出了查询源的对象（表，视图，物化视图，分区或子分区或一个子查询来生成子对象）
  如果使用了多个源对象，其逻辑处理会应用到每个联结类型（交叉联结[笛卡儿乘积——内联结，外联结）

仅含from的子句的查询语句

--仅含from的子句的查询语句
select c.customer_id　cust_id, o.order_id as ord_id, c.gender
  from oe.customers c
  join oe.orders o
    on c.customer_id = o.customer_id;

• where
  where可按条件查询最终返回限制的记录的条数
  逻辑比较的结果可能为true,false,未知（当其中结果含空值null,代表相应值的缺失）
  where的作用是限制和减少结果集。
• group by
  group by 是经过from和where后的结果集进行聚合。也就是按group by条件进行分组，将分组的结果进行汇总。

--截至group by子句的部分查询
select c.customer_id, count(o.order_id) as orders_ct
  from oe.customers c
  join oe.orders o
    on c.customer_id = o.customer_id
 where c.gender = 'F'
 group by c.customer_id;

• having
  having子句将分组汇总后的查询结果限定为该子句中条件为真的数据行

--再将分组后的结果进行条件限制
select c.customer_id, count(o.order_id) as orders_ct
  from oe.customers c
  join oe.orders o
    on c.customer_id = o.customer_id
 where c.gender = 'F'
 group by c.customer_id
 having count(o.order_id) > 4;

• select列表

--展示select各种可能的查询
select c.customer_id,
       c.cust_first_name || ' ' || c.cust_last_name name,
       (select e.last_name
          from oe.employees e
         where e.employee_id = c.account_mgr_id) acct_mgr
  from oe.customers c;

用来展示要显示的那些列（实际的列，表达式或一个select语句的结果）
当使用另一个select语句来生成结果中的某一列的值时，这个查询只能返加一行一列的值，称为标量子查询
还可能用用到distinct用来去掉重复值

• order by
  用来将查询的返回结果排序
  注意排序是查询过程中开销相当大的处理步骤，尤其是返回结果集很大的时候。

insert语句

*　单表插入

--单表插入
insert into hr.jobs(job_id,job_title,min_salary,max_salary)
values('IT_PM','Project Manager',5000,10000);
commit;

insert into hr.jobs(job_id,job_title,min_salary,max_salary)
select ename,job,sal*.9,sal*1.1 from scott.emp
commit;

select * from hr.jobs;

*　多表插入

drop table small_customers;
drop table middle_customers;
drop table large_customers;

create table small_customers(
  customer_id number,
  sum_orders number
);

create table middle_customers(
  customer_id number,
  sum_orders number
);

create table large_customers(
  customer_id number,
  sum_orders number
);

insert all --当指定all子句后，会执行无条件的多表插入
when sum_orders<3 then
into small_customers
when sum_orders>=3 and sum_orders<=5 then
into middle_customers
else 
into large_customers
select o.customer_id,count(o.order_id) sum_orders
from orders o
group by o.customer_id;

select * from small_customers;
select * from middle_customers;
select * from large_customers;

update语句

更改表中原有行的列值。（update,set,where）

创建一个重复的表employees2

drop table employees2 ;
create table employees2 as select * from employees;
select * from employees2;
alter table employees2 
add constraint emp2_emp_id_pk primary key (employee_id);

select employee_id,last_name,salary from employees2 where department_id=90;

• 使用表达式更新某列

update employees2 set salary=salary*1.1  where department_id=90;
commit;
select employee_id,last_name,salary from employees2 where department_id=90;
rollback;

• 使用子查询更新某列

update employees
set salary=(select employees2.salary from employees2
where employees2.salary!=employees.salary and employees2.employee_id=employees.employee_id)
where department_id=90;
select employee_id,last_name,salary from employees2 where department_id=90;
-- select * from departments;
rollback;

• 使用in子查询更新表

select employee_id, last_name, salary
  from employees
 where department_id in
       (select department_id
          from departments
         where department_name = 'Executive');
 --更新      
update employees
   set salary = salary * 1.1
 where department_id in
       (select department_id
          from departments
         where department_name = 'Executive');
 --再次验证      
select employee_id, last_name, salary
  from employees
 where department_id in
       (select department_id
          from departments
         where department_name = 'Executive');
--回滚         
rollback;

• 定义一个表更新

select employee_id, last_name, salary from employees;
--更新
update (select e1.salary, e2.salary new_sal
          from employees e1, employees2 e2
         where e1.employee_id = e2.employee_id
           and e1.department_id = 90)
   set salary = new_sal;
--再次验证    
select employee_id, last_name, salary from employees;
--回滚  
rollback;

• 使用子查询更新多个列

select employee_id, last_name, salary, commission_pct
  from employees2
 where department_id = 90;
--更新
update employees
   set (salary, commission_pct) =
       (select employees2.salary, employees2.salary * .10 comm_pct
          from employees2
         where employees2.employee_id = employees.employee_id
           and (employees2.salary != employees.salary or
               employees.salary is null))
 where department_id = 90;
--再次验证
select employee_id, last_name, salary, commission_pct
  from employees
 where department_id = 90;
--回滚  
rollback;

delete语句

从表移出行(delete, from,where)

• 使用where子句中的筛选条件删除行

select employee_id, last_name, salary, department_id from employees;
delete from employees where employee_id = 103;
select employee_id, last_name, salary, department_id from employees;
rollback;

• 使用子查询删除行

select employee_id, last_name, salary, department_id from employees;
delete from (select * from employees where department_id = 90);
select employee_id, last_name, salary, department_id from employees;
rollback;

• 用where中的特定子查询来删除特定的行

select employee_id, last_name, salary, department_id from employees2;
delete from employees2
 where department_id in
       (select department_id
          from departments
         where department_name = 'Executive');
select employee_id, last_name, salary, department_id from employees2;
rollback;

merge语句

merge语句可以按条件获取要更新或插入到表中的数据行，然后从１个或多个源头对表进行更新或向表中插入行。

merge 
into 
using 
on ()
when matched then 
delete 
When not matched then 
[log erros   ]

drop table dept60_bonuse;

create table dept60_bonuse(
employee_id number,
bonus_amt number
);

delete from dept60_bonuse;
insert into dept60_bonuse values(103,0);
insert into dept60_bonuse values(104,122);
insert into dept60_bonuse values(105,0);


select * from dept60_bonuse;
select employee_id,salary,department_id from employees where department_id=60;

merge into dept60_bonuse b
using (
select employee_id,salary,department_id from employees where department_id=60
) e
on (b.employee_id = e.employee_id)
when matched then
  update set b.bonus_amt=e.salary*0.2
  where b.bonus_amt=0
  delete where (e.salary>7500)
when not matched then
  insert (b.employee_id,b.bonus_amt)
  values (e.employee_id,e.salary*0.1)
  where (e.salary>7500);
  
  
select * from dept60_bonuse;
select employee_id,salary,department_id from employees where department_id=60;
rollback;

参考

Begin oracle SQL
SQL reference guide