（HDOJ 2054）A == B ?

A == B ?

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

1 2

2 2 

3 3 

4 3

 

Sample Output

NO

YES 

YES 

NO

 

  AC code:

  #include <stdio.h>

#include  < string .h >

void  A( char   * s)
{
     int  len  =  strlen(s);
     char   * p  =  s  +  len  -   1 ;
     if  (strchr(s,  ' . ' ))
     while  ( * p  ==   ' 0 ' )  * p --   =   0 ;
     if  ( * p  ==   ' . ' )  * p  =   0 ;
}

int  main( void )
{
     char   * pa,  * pb;
     char  a[ 100024 ], b[ 100024 ];

     while  (scanf( " %s%s " ,  & a,  & b)  !=  EOF)
    {
        pa  =  a; pb  =  b;
         while  ( * pa  ==   ' 0 ' ) pa ++ ;
         while  ( * pb  ==   ' 0 ' ) pb ++ ;
        A(pa); A(pb);
        puts(strcmp(pa, pb)  ?   " NO "  :  " YES " );
    }

     return   0 ;
}

转载于:https://www.cnblogs.com/cpoint/archive/2011/04/25/2026616.html