Python_不利用count对列表里的元素进行统计

 1 l1 = [1, 2, 3, 4, 2, 2, 3, 4, 55, 66]
 2 l2 = list()
 3 # [元素，‘次数’，元素，‘次数’。。。]
 4 for i in l1:
 5     if i not in l2:
 6         #不存在就把元素和1放进去
 7         l2.append(i)
 8         l2.append(str(1))
 9     else:
10         #存在就把次数加1
11         l2[l2.index(i) + 1] = str(int(l2[l2.index(i) + 1]) + 1)
12 print(l2)
13 i = 0
14 while i < len(l2):
15     print(l2[i], l2[i + 1], sep='---')
16     i += 2

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