Codeforces Round #657 (Div. 2) A - Acacius and String

这题就是暴力。暴力一定要有耐心，绝对不能慌。暴力不出来，换个方法暴力，还暴力不出来，说明基础不劳2333

源码：

#include 
#include 
#include 
using namespace std;

string ss = "abacaba";

int main(){
	int t;
	cin >> t;
	while(t--){
		int m;
		cin >> m;
		string s;
		cin >> s;
		int f = 0;
		int flag = 0;
		for(int i = 0;i<m-6;i++){
			flag = 0;
			string t = s.substr(i,7);
			for(int j = 0;j<7;j++){
				if(t[j] == '?') continue;
				if(t[j] != ss[j]){
					flag = 1;
					break;
				}
			}
			if(!flag){
				string s1 = s;
				for(int j = 0;j<7;j++){
					s1[i+j] = ss[j];
				}
				for(int j = 0;j<m;j++){
					if(s1[j] == '?') s1[j] = 'd';
				}
				int ans = 0;
				for(int j = 0;j<m-6;j++){
					t = s1.substr(j,7);
					if(t == ss) ans++;
				}
				if(ans == 1){
					cout << "Yes" << endl;
					cout << s1 << endl;
					f = 1;
					break;
				}
				
			}
		}
		if(!f) cout << "No" << endl;
	}
	return 0;
}