纯记录,51单片机 8*8点阵练习
```c
#include
#include
#define uchar unsigned char
#define uint unsigned int
unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char code digittab[10][8]={
// {0x00,0x18,0x80,0x80,0x08,0x80,0x80,0x1c},
{0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00},//0
{0x00,0x00,0x00,0x21,0x7f,0x01,0x00,0x00},//1
{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00},//2
{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00},//3
{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00},//4
{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00},//5
{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00},//6
{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00},//7
{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00},//8
{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00} //9
};
//延时
void DelayMS(uint x){
uchar i;
while(x–){
for(i=0;i<120;i++);
}
}
int timecount;
char tnta;
char tntb;
void main(){
TMOD=0x01;
TH0=(65535-3000)/256;
TL0=(65535-3000)%256;
TR0=1;
ET0=1;
EA=1;
while(1){
;
}
}
void t0(void) interrupt 1 using 0
{
TH0=(65535-3000)/256;
TL0=(65535-3000)%256;
P3=tab[tnta];
P0=digittab[tntb][tnta];
tnta++;
if(tnta8){
tnta=0;
}
timecount++;
if(timecount333){
timecount=0;
tntb++;
if(tntb==10){
tntb=0;
}
}
}